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Hollydoll
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 Posted: Mon Aug 15, 2005 1:44 pm Post subject: August 13 |
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Sort of new to this but quite addicted. I have gone over and over this and am so stuck. Please help with the obvious that I don't see. Thanks
21- 8-- ---
87- 541 2-9
495 --- 1-8
--- 3-- -27
3-2 678 9-1
7-- 4-2 ---
6-- --- 584
--7 -84 -1-
--- --- 79- |
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David Bryant
Joined: 29 Jul 2005
Posts: 559
Location: Denver, Colorado
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| Posted: Mon Aug 15, 2005 3:06 pm Post subject: Re: August 13 |
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| Hollydoll wrote: | Sort of new to this but quite addicted. I have gone over and over this and am so stuck. Please help with the obvious that I don't see. Thanks
21- 8-- ---
87- 541 2-9
495 --- 1-8
--- 3-- -27
3-2 678 9-1
7-- 4-2 ---
6-- --- 584
--7 -84 -1-
--- --- 79- |
I think your best move is to analyze the remaining possibilities in row 8 (where you already have four numbers filled in) and in the lower left-hand box (r7 - r9 / c1 - c3). Recognizing that the pair (3,6) must fit in the first two rows of column 3 you will obtain these possibilities for the lower left corner of this puzzle:
*6* 2/3 1/9
5/9 2/3 *7*
1/5 4/8 4/8
(Note that the "1" can't appear in r9c3 because of the (1,5,9) triplet appearing in this box.)
Now if you examine row 8 you will see that the triplet (2,3,6) must appear in (r8c2, r8c7, r8c9) leaving a "5" as the only possibility in r8c1. This of course leads immediately to a "9" in r8c4, a "1" in r9c1, and a "5" in r1c4, etc.
Hope that helps! dcb |
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