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Puzzle 11/06/15: ~ Advanced

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Wed Jun 15, 2011 6:31 am    Post subject: Puzzle 11/06/15: ~ Advanced Reply with quote
Code:
 +-----------------------+
 | 4 7 6 | 3 . 1 | 2 9 . |
 | 9 3 . | 7 . 2 | 8 . . |
 | 2 . . | . . . | 7 . . |
 |-------+-------+-------|
 | 5 2 . | 1 . 4 | 6 7 . |
 | . . . | . 6 . | . . . |
 | 8 6 . | 5 . 7 | 3 . . |
 |-------+-------+-------|
 | 6 4 2 | 9 . 5 | 1 . 3 |
 | 7 . . | 4 . . | . 5 . |
 | . . . | . . . | 4 . . |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK
PostPosted: Thu Jun 16, 2011 8:31 am    Post subject: Reply with quote
Two steps...
Quote:
kite(3) r5, c3 ; r8c6<>3=6
ur(18)r38c23[(5)r3c23=(3)r8c3] - (3=9)r4c3 - (9=5)r9c3 ; r2c3<>5=1
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Thu Jun 16, 2011 10:33 pm    Post subject: Reply with quote
First, a finned x-wing (3)r48c35; r8c6<>3=6

This results in the following code with a BUG+4 condition with two polyvalued cells in b1.
Code:
 *--------------------------------------------------*
 | 4    7    6    | 3    8    1    | 2    9    5    |
 | 9    3    15   | 7    45   2    | 8    14   6    |
 | 2    158  158  | 6    45   9    | 7    3    14   |
 |----------------+----------------+----------------|
 | 5    2    39   | 1    39   4    | 6    7    8    |
 | 13   19   7    | 28   6    38   | 5    24   49   |
 | 8    6    4    | 5    29   7    | 3    12   19   |
 |----------------+----------------+----------------|
 | 6    4    2    | 9    7    5    | 1    8    3    |
 | 7    18   138  | 4    13   6    | 9    5    2    |
 | 13   59   59   | 28   123  38   | 4    6    7    |
 *--------------------------------------------------*


Following the procedure provided recently by RonK, I concluded that r8c3=1, or r9c5=3, or r3c2=1, or finally that r3c3=5

BUG+4; r3c5<>5
(1)r8c3-r9c1=r5c1-(1=9)r5c2-(9=4)r5c9-r3c9=r2c8-(4=5)r2c5;
(3)r9c5-(3=9)r4c5-r4c3=r5c2-(9=4)r5c9-r3c9=r2c8-(4=5)r2c5;
(1)r3c2-(1=9)r5c2-(9=4)r5c9-r3c9=r2c8-(4=5)r2c5;
(5)r3c3;

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sat Jun 18, 2011 5:00 am    Post subject: Reply with quote
Finned X-Wing; r8c6<>3
XY-Wing (491); r3c2<>1
BUG+2
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