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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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 Posted: Sun Jul 10, 2011 5:29 am Post subject: Another Menneske |
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I have a simple one-stepper: I have no idea what it is.
| Code: | Puzzle: M4226678sh(5)
+-------+-------+-------+
| . . . | . . 4 | . . . |
| . . . | . 8 . | 9 . . |
| . . . | . 3 9 | 8 5 1 |
+-------+-------+-------+
| . 8 . | 3 . 7 | . 1 . |
| . . . | . . . | . 7 6 |
| . . 2 | . 9 . | . . . |
+-------+-------+-------+
| 5 . . | . 1 . | . 9 . |
| 4 . 7 | . . . | . . 8 |
| . . 8 | . 4 . | 3 . . |
+-------+-------+-------+ |
Keith |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Sun Jul 10, 2011 2:42 pm Post subject: |
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Keith,
I found a "simple" one step solution that results in r3c1<>2.
Ted |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Sun Jul 10, 2011 2:56 pm Post subject: |
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I think that top left corner is very fragile!!
| Quote: | Consider the 5 in block1, if r1c2<>5 then we have a (19)r1c23 pair, if r2c2<>5 then we have a (16)r2c26 pair. Either way r2c13<>1
als-xz (19=5)r1c23 - (5=16)r2c26 ; r2c13<>1 |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sun Jul 10, 2011 3:45 pm Post subject: |
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After basics: | Code: | +----------------+----------------+----------------+
| 8 159 19 | 15 7 4 | 6 3 2 |
| 123 156 13 | 1256 8 16 | 9 4 7 |
| 27 67 4 | 26 3 9 | 8 5 1 |
+----------------+----------------+----------------+
| 6 8 5 | 3 2 7 | 4 1 9 |
| 139 149 139 | 14 5 8 | 2 7 6 |
| 17 147 2 | 146 9 16 | 5 8 3 |
+----------------+----------------+----------------+
| 5 2 6 | 8 1 3 | 7 9 4 |
| 4 3 7 | 9 6 5 | 1 2 8 |
| 19 19 8 | 7 4 2 | 3 6 5 |
+----------------+----------------+----------------+ |
Look at B1R2C13. The two cells 123 and 13 must be (3) and (12). The 12 pseudocell forms an XY-wing 1-26 with R2C6 and R3C4, so R3C1 <>2.
Keith |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sun Jul 10, 2011 4:36 pm Post subject: |
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[Withdrawn: Doesn't contribute anything!]
Last edited by daj95376 on Mon Jul 11, 2011 4:42 am; edited 1 time in total |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Sun Jul 10, 2011 7:03 pm Post subject: |
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Because of Keith's initial comments, I was looking for a "not named pattern", and definitely not an "almost" step since Keith is not into those. I soon focused in on box 1&2.
I found a number of possibilities but when I made my post, I was thinking of a Kraken cell (123)r2c1; r3c1<>2
(1)r2c1-(1=6)r2c6-(6=2)r3c4;
(2)r2c1;
(3)r2c1-(3=1)r2c3-(1=6)r2c6-(6=2)r3c4;
I hoping a Kraken cell was a "less know pattern".
Ted |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Jul 10, 2011 10:01 pm Post subject: |
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| This stuff is too complicated for me. In the Type 3 UR on 19 in boxes 47 a 3 or 4 is needed to kill it off. The 4 proves a 3 in r2c3, so the pincers get rid of a couple of 3s, exposing the 162 XY-Wing. |
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susume
Joined: 13 May 2011
Posts: 36
Location: Southeastern US
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| Posted: Wed Jul 13, 2011 5:26 pm Post subject: |
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| (6)r2c2=(6-7)r3c2=(7)r6c2-(7=1)r6c1-(1=6)r6c6 => r2c6<>6=1 |
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