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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Mon Jul 11, 2011 11:10 pm Post subject: Puzzle 11/07/11: ~ XY |
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Code: | +-----------------------+
| 8 5 . | . 3 4 | . 1 9 |
| 1 3 . | 5 . . | 4 . 8 |
| . . . | . . 1 | 3 . . |
|-------+-------+-------|
| . 4 . | 1 . . | . . . |
| 9 . . | . 4 . | . . 3 |
| 2 . 5 | . . 3 | . . . |
|-------+-------+-------|
| . 2 3 | . . . | 1 . . |
| 5 . . | . . . | . 6 . |
| 4 8 . | . 5 . | . . 2 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Jul 14, 2011 2:59 pm Post subject: |
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I finally had some time to work on this puzzle and it was a lot of fun; I turned it into a BBDBer! It may be that some of the moves were not useful/required but they were what I found.
anp(67=9)b6q37-(9=7)r9c7-r7c9=r4c9: r45c78<>7
anp(79=6)r96c7-r6c2=r3c2-(6=5=2)r3c98-(2=7)r2c8; r1c7<>7
skyscraper (6) r3c29; r4c3,r6c7<6> r4c6<>7, which is not obviously helpful. However if we transport the fin then: (7)r6c5-r6c7=r4c9; r4c3<>7=8
skyscraper (2)r3c48; r4c5,r5c7<>2
aur(56)r45c67 sis r4c59=6,r5c3=6: aur(56)r45c67[(6)r4c59=(6)r5c3]-r1c3=r1c7-r3c9=r4c9; r4c67<>6
anp(56=7)r5c67-(7=6)r4c5-r4c9=r5c7; r5c3<>6=7
Ted |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Thu Jul 14, 2011 4:42 pm Post subject: |
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Although there are additional turbot-type eliminations present, this puzzle does have a reasonable solution.
Code: | after basics
+-----------------------------------------------------------------------+
| 8 5 26 | 267 3 4 | 267 1 9 |
| 1 3 269 | 5 2679 679 | 4 27 8 |
| 7 69 4 | 2689 2689 1 | 3 25 56 |
|-----------------------+-----------------------+-----------------------|
| 3 4 678 | 1 2679 5679 | 25679 2789 67 |
| 9 1 678 | 267 4 567 | 2567 278 3 |
| 2 67 5 | 6789 6789 3 | 679 4 1 |
|-----------------------+-----------------------+-----------------------|
| 6 2 3 | 4 79 8 | 1 579 57 |
| 5 79 79 | 3 1 2 | 8 6 4 |
| 4 8 1 | 679 5 679 | 79 3 2 |
+-----------------------------------------------------------------------+
# 69 eliminations remain
c29r3 Skyscraper <> 6 r4c3,r6c7
r7c7 2-String Kite <> 7 r6c5
M-Wing 5A (6=7)r4c9 - r6c7 = (7-6)r6c2 = (6)r3c2 => r3c9<>6 -or-
M-Wing 5B (6=7)r6c2 - r6c7 = (7-6)r4c9 = (6)r3c9 => r3c2<>6
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Ted, I hope you had fun finding the patterns you posted !
Regards, Danny |
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dejsmith
Joined: 23 Oct 2005 Posts: 42
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Posted: Thu Jul 14, 2011 10:08 pm Post subject: |
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This has to be a first that I used less steps than Ted! I hope I did not just mess up "correctly".
I had the same 2 first steps as Danny; then
X Wing on 7 in c59; r4c36<>7
XY Chain starting with r5c3, 76-62-26-65-52-29-97; r6c2<>7
Dave |
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susume
Joined: 13 May 2011 Posts: 36 Location: Southeastern US
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Posted: Fri Jul 15, 2011 1:38 am Post subject: |
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tlanglet wrote: | I turned it into a BBDBer! |
What does BBDB mean? I see it on some of Danny's puzzles but not in the Ratings thread. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Fri Jul 15, 2011 4:25 am Post subject: |
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Quote: | What does BBDB mean? |
Bends But Doesn't Break
Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9.
W-Wing (79), boxes 89, SL7 in r6; r7c8, r9c46<>9. |
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Fri Jul 15, 2011 12:13 pm Post subject: |
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Marty R. wrote: | Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9. |
Using daj95376's pencilmarks ...
Code: |
after basics
+-----------------------------------------------------------------------+
| 8 5 26 | 267 3 4 | 267 1 9 |
| 1 3 269 | 5 2679 679 | 4 27 8 |
| 7 69 4 | *89+26 *89+26 1 | 3 *25 *56 |
|-----------------------+-----------------------+-----------------------|
| 3 4 678 | 1 2679 5679 | 25679 2789 67 |
| 9 1 678 | 267 4 567 | 2567 278 3 |
| 2 67 5 | *89+67 *89+67 3 | 679 4 1 |
|-----------------------+-----------------------+-----------------------|
| 6 2 3 | 4 79 8 | 1 579 57 |
| 5 79 79 | 3 1 2 | 8 6 4 |
| 4 8 1 | 679 5 679 | 79 3 2 |
+-----------------------------------------------------------------------+ |
... I see that pseudo-cell in r2c45 combined with r2c89 forms a quantum naked triple <256> implying r3c2<>6. However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Fri Jul 15, 2011 3:38 pm Post subject: |
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ronk wrote: | Marty R. wrote: | Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9. |
Using daj95376's pencilmarks ...
Code: |
after basics
+-----------------------------------------------------------------------+
| 8 5 26 | 267 3 4 | 267 1 9 |
| 1 3 269 | 5 2679 679 | 4 27 8 |
| 7 69 4 | *89+26 *89+26 1 | 3 *25 *56 |
|-----------------------+-----------------------+-----------------------|
| 3 4 678 | 1 2679 5679 | 25679 2789 67 |
| 9 1 678 | 267 4 567 | 2567 278 3 |
| 2 67 5 | *89+67 *89+67 3 | 679 4 1 |
|-----------------------+-----------------------+-----------------------|
| 6 2 3 | 4 79 8 | 1 579 57 |
| 5 79 79 | 3 1 2 | 8 6 4 |
| 4 8 1 | 679 5 679 | 79 3 2 |
+-----------------------------------------------------------------------+ |
... I see that pseudo-cell in r2c45 combined with r2c89 forms a quantum naked triple <256> implying r3c2<>6. However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify. |
With the pseudo pair 67, r6c7=9-->r9c7=7-->r7c9=5-->r3c9=6-->r3c2=9. |
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Fri Jul 15, 2011 5:22 pm Post subject: |
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Marty R. wrote: | ronk wrote: | However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify. |
With the pseudo pair 67, r6c7=9-->r9c7=7-->r7c9=5-->r3c9=6-->r3c2=9. |
That's simple enough, but I didn't try for chains quite that long. Thanks. |
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