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Puzzle 11/07/11: ~ XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Mon Jul 11, 2011 11:10 pm    Post subject: Puzzle 11/07/11: ~ XY Reply with quote
Code:
 +-----------------------+
 | 8 5 . | . 3 4 | . 1 9 |
 | 1 3 . | 5 . . | 4 . 8 |
 | . . . | . . 1 | 3 . . |
 |-------+-------+-------|
 | . 4 . | 1 . . | . . . |
 | 9 . . | . 4 . | . . 3 |
 | 2 . 5 | . . 3 | . . . |
 |-------+-------+-------|
 | . 2 3 | . . . | 1 . . |
 | 5 . . | . . . | . 6 . |
 | 4 8 . | . 5 . | . . 2 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Thu Jul 14, 2011 2:59 pm    Post subject: Reply with quote
I finally had some time to work on this puzzle and it was a lot of fun; I turned it into a BBDBer! It may be that some of the moves were not useful/required but they were what I found.

anp(67=9)b6q37-(9=7)r9c7-r7c9=r4c9: r45c78<>7
anp(79=6)r96c7-r6c2=r3c2-(6=5=2)r3c98-(2=7)r2c8; r1c7<>7
skyscraper (6) r3c29; r4c3,r6c7<6> r4c6<>7, which is not obviously helpful. However if we transport the fin then: (7)r6c5-r6c7=r4c9; r4c3<>7=8
skyscraper (2)r3c48; r4c5,r5c7<>2
aur(56)r45c67 sis r4c59=6,r5c3=6: aur(56)r45c67[(6)r4c59=(6)r5c3]-r1c3=r1c7-r3c9=r4c9; r4c67<>6
anp(56=7)r5c67-(7=6)r4c5-r4c9=r5c7; r5c3<>6=7

Ted
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Thu Jul 14, 2011 4:42 pm    Post subject: Reply with quote
Although there are additional turbot-type eliminations present, this puzzle does have a reasonable solution.

Code:
 after basics
 +-----------------------------------------------------------------------+
 |  8      5      26     |  267    3      4      |  267    1      9      |
 |  1      3      269    |  5      2679   679    |  4      27     8      |
 |  7      69     4      |  2689   2689   1      |  3      25     56     |
 |-----------------------+-----------------------+-----------------------|
 |  3      4      678    |  1      2679   5679   |  25679  2789   67     |
 |  9      1      678    |  267    4      567    |  2567   278    3      |
 |  2      67     5      |  6789   6789   3      |  679    4      1      |
 |-----------------------+-----------------------+-----------------------|
 |  6      2      3      |  4      79     8      |  1      579    57     |
 |  5      79     79     |  3      1      2      |  8      6      4      |
 |  4      8      1      |  679    5      679    |  79     3      2      |
 +-----------------------------------------------------------------------+
 # 69 eliminations remain

 c29r3   Skyscraper                      <> 6    r4c3,r6c7

 r7c7    2-String Kite                   <> 7    r6c5

M-Wing 5A (6=7)r4c9 - r6c7 = (7-6)r6c2 = (6)r3c2  =>  r3c9<>6   -or-
M-Wing 5B (6=7)r6c2 - r6c7 = (7-6)r4c9 = (6)r3c9  =>  r3c2<>6

Ted, I hope you had fun finding the patterns you posted !

Regards, Danny
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dejsmith



Joined: 23 Oct 2005
Posts: 42
PostPosted: Thu Jul 14, 2011 10:08 pm    Post subject: Reply with quote
This has to be a first that I used less steps than Ted! I hope I did not just mess up "correctly".

I had the same 2 first steps as Danny; then
X Wing on 7 in c59; r4c36<>7
XY Chain starting with r5c3, 76-62-26-65-52-29-97; r6c2<>7

Dave
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susume



Joined: 13 May 2011
Posts: 36
Location: Southeastern US
PostPosted: Fri Jul 15, 2011 1:38 am    Post subject: Reply with quote
tlanglet wrote:
I turned it into a BBDBer!


What does BBDB mean? I see it on some of Danny's puzzles but not in the Ratings thread.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Fri Jul 15, 2011 4:25 am    Post subject: Reply with quote
Quote:
What does BBDB mean?


Bends But Doesn't Break

Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9.

W-Wing (79), boxes 89, SL7 in r6; r7c8, r9c46<>9.
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ronk



Joined: 07 May 2006
Posts: 398
PostPosted: Fri Jul 15, 2011 12:13 pm    Post subject: Reply with quote
Marty R. wrote:
Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9.

Using daj95376's pencilmarks ...
Code:

 after basics
 +-----------------------------------------------------------------------+
 |  8      5      26     |  267    3      4      |  267    1      9      |
 |  1      3      269    |  5      2679   679    |  4      27     8      |
 |  7      69     4      | *89+26 *89+26  1      |  3     *25    *56     |
 |-----------------------+-----------------------+-----------------------|
 |  3      4      678    |  1      2679   5679   |  25679  2789   67     |
 |  9      1      678    |  267    4      567    |  2567   278    3      |
 |  2      67     5      | *89+67 *89+67  3      |  679    4      1      |
 |-----------------------+-----------------------+-----------------------|
 |  6      2      3      |  4      79     8      |  1      579    57     |
 |  5      79     79     |  3      1      2      |  8      6      4      |
 |  4      8      1      |  679    5      679    |  79     3      2      |
 +-----------------------------------------------------------------------+

... I see that pseudo-cell in r2c45 combined with r2c89 forms a quantum naked triple <256> implying r3c2<>6. However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Fri Jul 15, 2011 3:38 pm    Post subject: Reply with quote
ronk wrote:
Marty R. wrote:
Looking at the potential 89 DP in boxes 25, either the 26 pseudo cell in r3 or the 67 pseudo cell in r6 kills it. Common outcome; r3c2=9.

Using daj95376's pencilmarks ...
Code:

 after basics
 +-----------------------------------------------------------------------+
 |  8      5      26     |  267    3      4      |  267    1      9      |
 |  1      3      269    |  5      2679   679    |  4      27     8      |
 |  7      69     4      | *89+26 *89+26  1      |  3     *25    *56     |
 |-----------------------+-----------------------+-----------------------|
 |  3      4      678    |  1      2679   5679   |  25679  2789   67     |
 |  9      1      678    |  267    4      567    |  2567   278    3      |
 |  2      67     5      | *89+67 *89+67  3      |  679    4      1      |
 |-----------------------+-----------------------+-----------------------|
 |  6      2      3      |  4      79     8      |  1      579    57     |
 |  5      79     79     |  3      1      2      |  8      6      4      |
 |  4      8      1      |  679    5      679    |  79     3      2      |
 +-----------------------------------------------------------------------+

... I see that pseudo-cell in r2c45 combined with r2c89 forms a quantum naked triple <256> implying r3c2<>6. However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify.

With the pseudo pair 67, r6c7=9-->r9c7=7-->r7c9=5-->r3c9=6-->r3c2=9.
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ronk



Joined: 07 May 2006
Posts: 398
PostPosted: Fri Jul 15, 2011 5:22 pm    Post subject: Reply with quote
Marty R. wrote:
ronk wrote:
However, I don't see how the pseudo-cell r6c45 with <67> leads to the same outcome. Please clarify.

With the pseudo pair 67, r6c7=9-->r9c7=7-->r7c9=5-->r3c9=6-->r3c2=9.

That's simple enough, but I didn't try for chains quite that long. Thanks.
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