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Free Press October 21, 2011

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sat Oct 22, 2011 1:31 am    Post subject: Free Press October 21, 2011 Reply with quote
Not yet done.
Code:
Puzzle: FP102111
+-------+-------+-------+
| 7 5 . | . . . | . . . |
| 3 . . | . . 8 | . . 6 |
| 1 . . | 6 . . | . . . |
+-------+-------+-------+
| . . 3 | 7 . . | 8 . . |
| 6 . 2 | 8 . 4 | 9 . 3 |
| . . . | . . 9 | 1 . . |
+-------+-------+-------+
| . . . | . . 1 | . . 4 |
| 9 . . | 4 . . | 5 . 7 |
| . . . | . . . | . 3 8 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

Keith
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sat Oct 22, 2011 4:06 am    Post subject: Reply with quote
Nice puzzle!

I found two one-steppers. Look at 6 and 4.

Keith
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Sat Oct 22, 2011 2:10 pm    Post subject: Reply with quote
Another one stepper is

anp(23=6)r6c45-(6=9=5)r9c54-(5=3=2)r76c4; r4c6<>2

Ted
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sat Oct 22, 2011 3:35 pm    Post subject: Reply with quote
After basics:
Code:
+----------------+----------------+----------------+
| 7    5    6    | 239  2349 23   | 34   8    1    |
| 3    2    9    | 1    47   8    | 47   5    6    |
| 1    8    4    | 6    37   5    | 37   2    9    |
+----------------+----------------+----------------+
| 45   9    3    | 7    1    26   | 8    46   25   |
| 6    1    2    | 8    5    4    | 9    7    3    |
| 8    47   57   | 23   236  9    | 1    46   25   |
+----------------+----------------+----------------+
| 25   367  57   | 35   8    1    | 26   9    4    |
| 9    36   8    | 4    236  236  | 5    1    7    |
| 245  46   1    | 59   69   7    | 26   3    8    |
+----------------+----------------+----------------+

There is a W-wing 46. With transport, it takes out 6 in R9C5.

An M-wing based on 36 takes out 6 in R8C6.

Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sat Oct 22, 2011 4:48 pm    Post subject: Reply with quote
Quote:
There is a W-wing 46. With transport, it takes out 6 in R9C5.

I played the same move.
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Sat Oct 22, 2011 5:15 pm    Post subject: Reply with quote
keith wrote:
I found two one-steppers. Look at 6 and 4.

I thought your hint meant:

Code:
M-Wing 1A:  (6=4)r9c2 - r6c2 = (4-6)r6c8 = (6)r6c5  =>  r9c5<>6

But, after reading ...

keith wrote:
There is a W-wing 46. With transport, it takes out 6 in R9C5.

I realized that you meant:

Code:
(6=4)r9c2 - r6c2 = r4c1 - (4=6)r4c8 - r4c6 = (6)r8c6  =>  r8c2,r9c5<>6

Now, I wouldn't have even mentioned it, if it wasn't for the fact that I can't find:

keith wrote:
An M-wing based on 36 takes out 6 in R8C6.
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sat Oct 22, 2011 6:29 pm    Post subject: Reply with quote
daj95376 wrote:

Now, I wouldn't have even mentioned it, if it wasn't for the fact that I can't find:
keith wrote:
An M-wing based on 36 takes out 6 in R8C6.

After basics:
Code:
+----------------+----------------+----------------+
| 7    5    6    | 239  2349 23   | 34   8    1    |
| 3    2    9    | 1    47   8    | 47   5    6    |
| 1    8    4    | 6    37   5    | 37   2    9    |
+----------------+----------------+----------------+
| 45   9    3    | 7    1    26d  | 8    46   25   |
| 6    1    2    | 8    5    4    | 9    7    3    |
| 8    47   57   | 23   236c 9    | 1    46   25   |
+----------------+----------------+----------------+
| 25   367  57   | 35b  8    1    | 26   9    4    |
| 9    36a  8    | 4    236 23-6  | 5    1    7    |
| 245  46   1    | 59   69   7    | 26   3    8    |
+----------------+----------------+----------------+
My W-wing was based on 46 in R4C8 and R9C2, transport 6 from the first to R6C5. R6C8 and R9C2 are the basis of an M-wing that does the same thing.

3 in a forces 3 in c (via b). ad are pincers on 6.

Keith
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Sun Oct 23, 2011 1:32 am    Post subject: Reply with quote
Withdrawn: I was tired and thought I had a point. Now, I'm not so sure.

Last edited by daj95376 on Sun Oct 23, 2011 7:32 am; edited 1 time in total
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sun Oct 23, 2011 3:15 am    Post subject: Reply with quote
daj95376 wrote:
When basic MWSL-Wings are expanded/transported by adding additional strong links for one or both values, accurately describing the path becomes important. For the current puzzle, there may only be two 3-SIS/basic M-Wings present, but there are twelve 4-SIS M-Wings present. In particular, there are four 4-SIS M-Wings for "(6=4)r9c2 - ... - (6)r6c5 => r9c5<>6".

Code:
 +--------------------------------------------------------------+
 |  7     5     6     |  239   2349  23    |  34    8     1     |
 |  3     2     9     |  1     47    8     |  47    5     6     |
 |  1     8     4     |  6     37    5     |  37    2     9     |
 |--------------------+--------------------+--------------------|
 |  45    9     3     |  7     1     26    |  8     46    25    |
 |  6     1     2     |  8     5     4     |  9     7     3     |
 |  8     47    57    |  23    236   9     |  1     46    25    |
 |--------------------+--------------------+--------------------|
 |  25    367   57    |  35    8     1     |  26    9     4     |
 |  9     36    8     |  4     236   236   |  5     1     7     |
 |  245   46    1     |  59    69    7     |  26    3     8     |
 +--------------------------------------------------------------+
 # 39 eliminations remain

===== =====

M-Wing 1A (6=4)r9c2 - r6c2 = (4-6)r6c8 = (6)r6c5                 => r9c5<6> r8c6<6> r8c6<6> r8c6<6> r8c6<6> r9c5<6> r9c5<6> r9c5<6> r9c5<6> r8c2<6> r8c2,r9c5<6> r8c2,r9c5<6> r13c5<3> r1c7,r3c5<>3

Trust me, you don't want to see the list of 5-SIS and 6-SIS M-Wings in this grid.

_____

Danny,

I said:
Quote:

3 in a forces 3 in c (via b). ad are pincers on 6.

I am not sure what the point of your post is, but I found my elimination by hand, and I think it is relatively easy to spot.

Keith
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ronk



Joined: 07 May 2006
Posts: 398
PostPosted: Sun Oct 23, 2011 3:35 am    Post subject: Reply with quote
keith wrote:
I said:
Quote:

3 in a forces 3 in c (via b). ad are pincers on 6.

I am not sure what the point of your post is, but I found my elimination by hand, and I think it is relatively easy to spot.

Almost easier to spot than the 'a', 'b', 'c' and 'd' tags on the pencilmarks. Smile With candidates left-justified, the tags would be easier to spot if they were on the left.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Sun Oct 23, 2011 12:52 pm    Post subject: Reply with quote
tlanglet wrote:
Another one stepper is
anp(23=6)r6c45-(6=9=5)r9c54-(5=3=2)r76c4; r4c6<>2


Beautiful! Great logic -- even if it hurt my head
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