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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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 Posted: Fri Nov 11, 2011 3:16 pm Post subject: Free Press November 11, 2011 |
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| Code: | Puzzle: FP111111
+-------+-------+-------+
| . . 5 | . . . | 8 . . |
| 1 8 6 | . 4 . | . 3 . |
| . 7 . | . . . | . . 1 |
+-------+-------+-------+
| . . . | 7 . 4 | . 1 . |
| . . 7 | . 6 . | 9 . . |
| . 6 . | 9 . 3 | . . . |
+-------+-------+-------+
| 8 . . | . . . | . 4 . |
| . 4 . | . 5 . | 3 6 9 |
| . . 9 | . . . | 5 . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
Keith |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Fri Nov 11, 2011 5:08 pm Post subject: |
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| Code: | X Wing r6c9<>4
*-----------------------------------------------------------*
| 349 23 5 | 1 237 27-6 | 8 29 a46 |
| 1 8 6 | 25 4 9 | 27 3 257 |
| 39 7 234 |f36 238 2568 | 4-6 259 1 |
|-------------------+-------------------+-------------------|
| 5 9 c38 | 7 28 4 | 26 1 b36 |
| 34 1 7 | 258 6 258 | 9 28 34 |
| 2 6 48 | 9 1 3 | 47 578 578 |
|-------------------+-------------------+-------------------|
| 8 5 d23 |e36 9 67 | 1 4 27 |
| 7 4 1 | 28 5 28 | 3 6 9 |
| 6 23 9 | 4 37 1 | 5 278 278 |
*-----------------------------------------------------------*
s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6 |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Fri Nov 11, 2011 6:45 pm Post subject: |
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| arkietech wrote: | s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6 |
An s-wing would have a bivalued cell at its center. This is an l-wing with transport (I think). |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Nov 11, 2011 6:47 pm Post subject: |
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| I hacked my way through to the finish using an X-Wing, M-Wing and three XY-Wings, with three of the moves involving pincer transports. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sat Nov 12, 2011 3:04 am Post subject: |
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After basics: | Code: | +-------------------+-------------------+-------------------+
| 2349 239 5 | 1236 1237 1267 | 8 29 46 |
| 1 8 6 | 25 4 9 |B27 3 257 |
| 2349 7 234 | 23568 238 2568 | 46 259 1 |
+-------------------+-------------------+-------------------+
| 2359 239 238 | 7 28 4 |C26 1 -23568 |
| 234 123 7 | 1258 6 1258 | 9 28 -2348 |
| 245 6 1248 | 9 128 3 |C247 2578 -24578 |
+-------------------+-------------------+-------------------+
| 8 5 23 | 236 9 267 | 1 4 A27 |
| 7 4 12 | 128 5 128 | 3 6 9 |
| 6 123 9 | 4 1237 127 | 5 278 278 |
+-------------------+-------------------+-------------------+ |
Cool! A grouped M-wing.
7 in A forces 7 in B. Not 2 in B forces 2 in one of C. Eliminating 2 in B6C9.
Nice move, though it does not solve the puzzle.
Keith |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sat Nov 12, 2011 3:09 am Post subject: |
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| arkietech wrote: | | Code: | s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6 |
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I find that it matches what Norm calls an Inverted w wing. | Code: | | iW-Wing: (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Sat Nov 12, 2011 4:57 am Post subject: |
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| arkietech wrote: | | arkietech wrote: | | Code: | s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6 |
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I find that it matches what Norm calls an Inverted w wing. | Code: | | iW-Wing: (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t |
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That's an ill-advised name. All other wings have three strong links ... except for the x-wing, of course. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sat Nov 12, 2011 8:53 am Post subject: |
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| ronk wrote: | | arkietech wrote: | | arkietech wrote: | | Code: | s wing?
(6)r1c9=(6-3)r4c9=(3)r4c3-(3)r7c3=(3-6)r7c4=(6)r3c4 => r1c6,r3c7<>6 |
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I find that it matches what Norm calls an Inverted w wing. | Code: | | iW-Wing: (Y)s = (Y-X)a = (X)b - (X)c = (X-Y)d = (Y)t |
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That's an ill-advised name. All other wings have three strong links ... except for the x-wing, of course. |
Though, wings can often be extended by another couple of strong links while keeping basically the same logic.
Keith |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sat Nov 12, 2011 5:28 pm Post subject: |
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In Norm's inverse/inverted wing patterns, he exchanges weak inferences and strong inferences, and then adds a strong inference to the front and end to complete the pattern. (at least, that's been my observation.)
| Code: | W-Wing: (X=Y)a - (Y)b = (Y)c - (Y=X)d
iW-Wing: (X)s = (X-Y)a = (Y)b - (Y)c = (Y-X)d = (X)t
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