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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Nov 26, 2011 5:55 pm Post subject: Vanhagen Extreme November 25 |
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(Reposted from another thread - Keith.)
A little late, but here it is....
Code: |
+-------+-------+-------+
| 4 . . | 7 3 . | 1 . 8 |
| . . 5 | 2 . 4 | . . . |
| 2 . . | . 6 . | . 3 . |
+-------+-------+-------+
| . 4 . | . . . | . 5 6 |
| 9 . 8 | . . . | 3 . 7 |
| 3 5 . | . . . | . 8 . |
+-------+-------+-------+
| . 8 . | . 7 . | . . 3 |
| . . . | 6 . 8 | 5 . . |
| 6 . 4 | . 5 3 | . . 2 |
+-------+-------+-------+
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Play online
After basics:
Code: | *--------------------------------------------------*
| 4 69 69 | 7 3 5 | 1 2 8 |
| 8 3 5 | 2 1 4 | 7 6 9 |
| 2 7 1 | 8 6 9 | 4 3 5 |
|----------------+----------------+----------------|
| 1 4 27 | 3 8 27 | 9 5 6 |
| 9 26 8 | 5 24 126 | 3 14 7 |
| 3 5 67 | 19 49 67 | 2 8 14 |
|----------------+----------------+----------------|
| 5 8 29 | 4 7 12 | 6 19 3 |
| 7 129 3 | 6 29 8 | 5 149 14 |
| 6 19 4 | 19 5 3 | 8 7 2 |
*--------------------------------------------------* |
I used three steps.
xy-wing(67-1)r63c3+r5c2=(2)r5c2-(2=4=1)r5c58-r6c9=r8c9-(1=7)r8c1-r4c1=r46c3-(7=1)r3c3; r3c2<>1
skyscraper (4)r58c8; r6c4,r8c5<>4
BUG+3; r5c5<>2
(2)r5c6;
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(9)r8c2-(9=6=2)r15c2;
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(1)r8c8-r8c2=r9c2-r9c4=(1-9)r6c4=(9-4)r6c5=r5c5;
Ted |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sat Nov 26, 2011 8:55 pm Post subject: |
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Code: | correct grid after basics
+--------------------------------------------------------------+
| 4 69 69 | 7 3 5 | 1 2 8 |
| 8 3 5 | 2 1 4 | 7 6 9 |
| 2 p17 17 | 8 6 9 | 4 3 5 |
|--------------------+--------------------+--------------------|
| 17 4 127 | 3 8 127 | 9 5 6 |
| 9 v16+2 8 | 5 24 126 | 3 14 7 |
| 3 5 p67 | 149 49 67 | 2 8 14 |
|--------------------+--------------------+--------------------|
| 5 8 129 | 149 7 12 | 6 149 3 |
| 17 1279 3 | 6 249 8 | 5 1479 14 |
| 6 179 4 | 19 5 3 | 8 179 2 |
+--------------------------------------------------------------+
# 43 eliminations remain
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Ted wrote: | xy-wing(67-1)r63c3+r5c2=(2)r5c2-(2=4=1)r5c58-r6c9=r8c9-(1=7)r8c1-r4c1=r46c3-(7=1)r3c3; r3c2<>1
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I would have written:
(7)r3c3-[<16+7> XY-Wing r5c2/r3c2+r6c3]=(2)r5c2-(2=4=1)r5c58-r6c9=r8c9-(1=7)r8c1-r4c1=r46c3-(7)r3c3
I might have chosen a Kraken Cell interpretation:
Code: | (1)r5c2-(1=7)r3c2-(7)r3c3
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(6)r5c2-(6=7)r6c3-(7)r3c3
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(2)r5c2-(2=4)r5c5-(4=1)r5c8-r6c9=r8c9-(1=7)r8c1-r4c1=r46c3-(7)r3c3
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Note: several editing changes to get here. |
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