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Jan 10 VH

 
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
PostPosted: Mon Jan 09, 2012 10:53 pm    Post subject: Jan 10 VH Reply with quote
XY-Wing 159 pivoted in r3c2 solves it by setting r1c2<>9.
Also the XYZ-wing 158 hinged in r3c1; r2c1<>1. So is the Type 1 UR 69; r2c7=1.
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Stanley P



Joined: 27 Feb 2008
Posts: 20
Location: Tennessee, USA
PostPosted: Tue Jan 10, 2012 1:46 pm    Post subject: Reply with quote
I had a 159 XY-Wing pivoted at R2C1, setting R3C1 <>5 and solving it.
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