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au tough 4/5/2012

 
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Thu Apr 05, 2012 7:04 am    Post subject: au tough 4/5/2012 Reply with quote

Code:
 
 *-----------*
 |.76|3..|...|
 |...|19.|2..|
 |2..|...|.9.|
 |---+---+---|
 |..8|...|..4|
 |...|879|...|
 |6..|...|5..|
 |---+---+---|
 |.2.|...|..6|
 |..1|.23|...|
 |...|..5|74.|
 *-----------*

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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu Apr 05, 2012 5:03 pm    Post subject: Reply with quote

I should've saved my grid, but I didn't.

M-Wing (27). R6c3=7--->r4c8=7. R4c8<2>r4c4=2; r6c4<>2.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Thu Apr 05, 2012 5:42 pm    Post subject: Reply with quote

Marty R. wrote:
I should've saved my grid, but I didn't.

M-Wing (27). R6c3=7--->r4c8=7. R4c8<2>r4c4=2; r6c4<>2.

I saved it.

Code:
 
 *-----------------------------------------------------------*
 | 9     7     6     | 3     458   2     | 148   158   158   |
 | 38    458   345   | 1     9     467   | 2     3567  357   |
 | 2     1     345   | 457   4568  4678  | 3468  9     3578  |
 |-------------------+-------------------+-------------------|
 |b17    39    8     |d25    356   16    | 19   c127   4     |
 | 145   45    245   | 8     7     9     | 136   1236  13    |
 | 6     39   a27    | 4-2   34    14    | 5     1278  1789  |
 |-------------------+-------------------+-------------------|
 | 457   2     4579  | 479   48    478   | 13    13    6     |
 | 47    46    1     | 467   2     3     | 89    58    589   |
 | 38    68    39    | 69    1     5     | 7     4     2     |
 *-----------------------------------------------------------*

m-wing
(2=7)r6c3-r4c1=(7-2)r4c8=(2)r4c4 => r6c4<>2; stte

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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu Apr 05, 2012 5:49 pm    Post subject: Reply with quote

Quote:
M-Wing (27). R6c3=7--->r4c8=7. R4c8<2>r4c4=2; r6c4<>2.


That line should've read:

R6c3=7--->r4c8=7. R4c8<2>r4c4=2; r6c4<>2.
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Thu Apr 05, 2012 11:04 pm    Post subject: Reply with quote

An anp() has some similarities to to the solution already posted.

anp(17=2)r4c18-r4c4=r6c4-(2=7)r6c3-(7=1)r4c1; r4c67<>1

Ted
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