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Guest Guest
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Posted: Fri Aug 19, 2005 1:34 pm Post subject: August 19th |
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Need help...
Got to here:
x83 192 45x
95x 864 x23
42x xx5 x98
598 4xx x3x
x1x 95x x4x
x4x xx7 9x5
1x9 5xx x64
865 x4x xx9
2x4 6x9 5xy
The hint was to put 1 at "y" but I cant understand why that is clearly decided.
Would be glad to get som help of "SuDoku-thinking" |
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Guest
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Posted: Fri Aug 19, 2005 2:05 pm Post subject: |
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Other than going for y, after looking at the pattern, we can get these conclusions:
r8c8 can only be 1,7
r9c8 can only be 1,7,8
r9c9 can only be 1,7
Since r8c8 and r9c9 can only be 1,7 we can eliminate these two numbers from r9c8, giving it the answer 8 in that cell. |
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Guest Guest
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Posted: Fri Aug 19, 2005 3:19 pm Post subject: Ah... |
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...I see. Thanks a lot!!!
After staring at the numbers for too long I got stuck and saw no solution. Thanks for clearing things up for me!
//Klas |
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Guest
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Posted: Fri Aug 19, 2005 4:17 pm Post subject: Re: August 19th |
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Guest wrote: | Need help...
Got to here:
x83 192 45x
95x 864 x23
42x xx5 x98
598 4xx x3x
x1x 95x x4x
x4x xx7 9x5
1x9 5xx x64
865 x4x xx9
2x4 6x9 5xy
The hint was to put 1 at "y" but I cant understand why that is clearly decided.
Would be glad to get som help of "SuDoku-thinking" |
r9c9 has to be 1 or 7.
c8 needs a 7. Since r6 already has a 7 (r6c6), that only leaves r8c8, r8c9.
Therefore, r9c9 can't be a 7, so it must be 1. |
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Guest Guest
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Posted: Mon Aug 22, 2005 9:57 am Post subject: True!!! |
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Thanks for clearing that '1' for me as well.
Great!
//Klas |
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