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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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 Posted: Wed May 30, 2012 5:11 am Post subject: Vanhegan Fiendish May 30, 2012 |
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| Code: | *-----------*
|.64|...|...|
|.7.|3..|.98|
|...|.19|..7|
|---+---+---|
|..6|.5.|.8.|
|..5|2.1|3..|
|.3.|.6.|1..|
|---+---+---|
|4..|53.|...|
|68.|..2|.5.|
|...|...|92.|
*-----------*
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Wed May 30, 2012 1:10 pm Post subject: |
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Code after basics:
| Code: | *--------------------------------------------------*
| 9 6 4 | 78 278 58 | 25 3 1 |
| 125 7 12 | 3 24 45 | 6 9 8 |
| 38 25 38 | 6 1 9 | 25 4 7 |
|----------------+----------------+----------------|
| 17 19 6 | 79 5 3 | 4 8 2 |
| 78 4 5 | 2 78 1 | 3 6 9 |
| 28 3 289 | 489 6 48 | 1 7 5 |
|----------------+----------------+----------------|
| 4 29 29 | 5 3 7 | 8 1 6 |
| 6 8 13 | 14 9 2 | 7 5 34 |
| 135 15 7 | 148 48 6 | 9 2 34 |
*--------------------------------------------------*
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a VH solution is a xy-wing(25-1)r3c2+r2c3|r9c2; r8c3<>1 followed by a BUG+2
A one step solution is anp(8=14)r89c4-(4=8)r9c5-(8=7)r5c5-r1c5=r1c4; r1c4<>8
I also tried to solve the BUG+6 present in the code after basics but one of the cells did not satisfy the BUG condition of three occurrences in each row, column and box; the other 5 cells resulted in a common outcome.
Ted |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Wed May 30, 2012 1:36 pm Post subject: |
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| tlanglet wrote: | | I also tried to solve the BUG+6 |
BUG+6 hurts my head to think about. 
| Code: |
*--------------------------------------------------*
| 9 6 4 | 78 278 58 | 25 3 1 |
| 125 7 12 | 3 #24 #45 | 6 9 8 |
| 38 25 38 | 6 1 9 | 25 4 7 |
|----------------+----------------+----------------|
| 17 19 6 | 79 5 3 | 4 8 2 |
| 78 4 5 | 2 7-8 1 | 3 6 9 |
| 28 3 289 | 489 6 *48 | 1 7 5 |
|----------------+----------------+----------------|
| 4 29 29 | 5 3 7 | 8 1 6 |
| 6 8 13 | 14 9 2 | 7 5 34 |
| 135 15 7 | 148 *48 6 | 9 2 34 |
*--------------------------------------------------*
w-wing
(8=4)r6c6-r2c6=r2c5-(4=8)r9c5 => r5c5<>8; stte
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed May 30, 2012 4:26 pm Post subject: |
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| Same XY-Wing as Ted and BUG+2 or W-Wing on 78. |
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aran
Joined: 19 Apr 2010
Posts: 70
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| Posted: Thu May 31, 2012 3:33 pm Post subject: |
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| tlanglet wrote: | Code after basics:
| Code: | *--------------------------------------------------*
| 9 6 4 | 78 278 58 | 25 3 1 |
| 125 7 12 | 3 24 45 | 6 9 8 |
| 38 25 38 | 6 1 9 | 25 4 7 |
|----------------+----------------+----------------|
| 17 19 6 | 79 5 3 | 4 8 2 |
| 78 4 5 | 2 78 1 | 3 6 9 |
| 28 3 289 | 489 6 48 | 1 7 5 |
|----------------+----------------+----------------|
| 4 29 29 | 5 3 7 | 8 1 6 |
| 6 8 13 | 14 9 2 | 7 5 34 |
| 135 15 7 | 148 48 6 | 9 2 34 |
*--------------------------------------------------*
|
I also tried to solve the BUG+6 present in the code after basics but one of the cells did not satisfy the BUG condition of three occurrences in each row, column and box; the other 5 cells resulted in a common outcome. |
This can be reduced to BUG+4 considerations as follows
2r2c1=2r6c1-2r6c3 (with no other reductions following)=BUG+4
+4 = 8r1c5, 8r6c4, 1r9c1, 4r9c4
ie 2r2c1={8r1c5, 8r6c4, 1r9c1, 4r9c4}
and all of those =>r4c2=1 |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Fri Jun 01, 2012 12:39 am Post subject: |
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| tlanglet wrote: |
| Code: | *--------------------------------------------------*
| 9 6 4 | 78 27+8 58 | 25 3 1 |
| 15+2 7 12 | 3 24 45 | 6 9 8 |
| 38 25 38 | 6 1 9 | 25 4 7 |
|----------------+----------------+----------------|
| 17 19 6 | 79 5 3 | 4 8 2 |
| 78 4 5 | 2 78 1 | 3 6 9 |
|(28) 3 89+2 | 49+8 6 48 | 1 7 5 |
|----------------+----------------+----------------|
| 4 29 29 | 5 3 7 | 8 1 6 |
| 6 8 13 | 14 9 2 | 7 5 34 |
| 35+1 15 7 | 18+4 48 6 | 9 2 34 |
*--------------------------------------------------*
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I also tried to solve the BUG+6 present in the code after basics but one of the cells did not satisfy the BUG condition of three occurrences in each row, column and box; the other 5 cells resulted in a common outcome. |
I believe this is OK; from the set of all unsolved cells omit r6c1, and then you have a BUG-Lite+6. |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Fri Jun 01, 2012 1:39 pm Post subject: |
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Aran and Ron,
I greatly appreciate the feedback on this BUG+6 pattern. I originally tried to find a common result for several cells but failed. Given the clue of cell r4c2, it is rather easy to solve.
Aran, I have been thinking about your suggestion to reduce the pattern constraints but am unable to make the mental leap. I recognize the relationship between 2r2c1 & 2r4c3 as you noted, but I fail to understand how that eliminates the original inference 8r6c3.
Ron, I see the BUG-Lite+6 but do not appreciate the rationale to omit cell r6c1. Doing so results in the same condition as Aran suggested but still has 6 inferences.
Maybe another pot of coffee will help otherwise I will try scotch.
Ted |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Fri Jun 01, 2012 2:59 pm Post subject: |
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| tlanglet wrote: | | I see the BUG-Lite+6 but do not appreciate the rationale to omit cell r6c1. Doing so results in the same condition as Aran suggested but still has 6 inferences. |
It is essentially the same, but uses an established definition rather than an ad hoc one. For my BUG-Lite+6, the set of selected cells (without the extra candidates) as indicated have each candidate value appearing exactly twice in each row, column and box.
BTW aran used strong inference 2r2c1=2r6c1 for r6c3<>2. Therefore r6c3=2 implies r2c1=2 with the same SI and use of the latter only is sufficient. |
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