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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Jun 03, 2012 12:30 am Post subject: Vanhegan Extreme June 3, 2012 |
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Code: |
*-----------*
|.9.|267|.4.|
|..4|935|1..|
|...|1.4|...|
|---+---+---|
|.8.|.9.|.1.|
|412|.7.|965|
|.6.|.1.|.3.|
|---+---+---|
|...|6.9|...|
|..1|843|6..|
|.3.|751|.9.|
*-----------*
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There was an old wwII song "commin' in on a wing and a prayer"
This is a "wing and a pair"
Code: |
*--------------------------------------------------*
| 1 9 58 | 2 6 7 | 58 4 3 |
|b278 b27 4 | 9 3 5 | 1 c278 6 |
| 36 b257 36 | 1 8 4 | 257 c27 9 |
|----------------+----------------+----------------|
| 357 8 357 | 45 9 6 | 247 1 247 |
| 4 1 2 | 3 7 8 | 9 6 5 |
| 57 6 9 | 45 1 2 | 478 3 478 |
|----------------+----------------+----------------|
| 578 4 578 | 6 2 9 | 3 578 1 |
| 9 a257 1 | 8 4 3 | 6 a5-27 27 |
| 268 3 68 | 7 5 1 | 248 9 248 |
*--------------------------------------------------*
(27=5)r8c29-(5=278)r2c12,r3c2-(8=27)r23c8 => r8c8<>27; stte
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Jun 03, 2012 4:42 pm Post subject: |
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In the potential 27 UR in boxes 13, either r3c2=5 or r2c8=8. The 8 proves a 5 or the 5 proves an 8. Either way, one of r1c3 or r1c7 is solved and that's all that's needed.
Code: |
+-------------+--------+-------------+
| 1 9 58 | 2 6 7 | 58 4 3 |
| 278 27 4 | 9 3 5 | 1 278 6 |
| 36 257 36 | 1 8 4 | 257 27 9 |
+-------------+--------+-------------+
| 357 8 357 | 45 9 6 | 247 1 247 |
| 4 1 2 | 3 7 8 | 9 6 5 |
| 57 6 9 | 45 1 2 | 478 3 478 |
+-------------+--------+-------------+
| 578 4 578 | 6 2 9 | 3 578 1 |
| 9 257 1 | 8 4 3 | 6 257 27 |
| 268 3 68 | 7 5 1 | 248 9 248 |
+-------------+--------+-------------+
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Play this puzzle online at the Daily Sudoku site |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Mon Jun 04, 2012 2:48 pm Post subject: |
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Marty, you and I seem to enjoy the potential UR patterns. This puzzle is a good example of that technique.
I looked for a second solution using another favorite technique.
anp(2=68)r9c13-(8)r9c79=r7c8-r2c8=r1c7-(8=5)r1c3-r3c2=r8c2; r8c2<>2
Ted |
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