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Vanhegan fiendish August 1, 2012

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arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Thu Aug 02, 2012 7:15 am Post subject: Vanhegan fiendish August 1, 2012

Code:

*-----------*
|2..|...|5.8|
|.7.|.81|.9.|
|6..|2..|...|
|---+---+---|
|.5.|.6.|8..|
|.4.|8.2|.3.|
|..3|.9.|.6.|
|---+---+---|
|...|..4|..9|
|.9.|63.|.2.|
|3.4|...|..1|
*-----------*

tlanglet

Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

Posted: Thu Aug 02, 2012 12:53 pm Post subject:

Code after basics:

Code:

*-----------------------------------------------------------*
| 2 3 19 | 79 47 6 | 5 147 8 |
| 4 7 5 | 3 8 1 | 2 9 6 |
| 6 18 189 | 2 457 579 | 147 147 3 |
|-------------------+-------------------+-------------------|
| 9 5 27 | 147 6 3 | 8 147 247 |
| 17 4 6 | 8 157 2 | 9 3 57 |
| 178 128 3 | 1457 9 57 | 147 6 2457 |
|-------------------+-------------------+-------------------|
| 578 6 27 | 15 125 4 | 3 58 9 |
| 158 9 18 | 6 3 58 | 47 2 47 |
| 3 28 4 | 579 257 5789 | 6 58 1 |
*-----------------------------------------------------------*

I did not readily spot an easy pattern type solution, so...............

9r3c6=(9-8)r9c6=r8c6-r8c3=r3c3; -9r3c3

Ted

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Thu Aug 02, 2012 4:32 pm Post subject:

Code:

M-Wing (47). Either the 4 or 7 in r8c7 proves itself in r13c8. If r13c8<>4 or 7, then r4c8 is that value; r6c7<>47.

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Thu Aug 02, 2012 11:45 pm Post subject:

Quote:

M-Wing (47). Either the 4 or 7 in r8c7 proves itself in r13c8. If r13c8<>4 or 7, then r4c8 is that value; r6c7<>47.

I was extremely proud of my solution. However, a reliable source told me (offline) that my reasoning was invalid. So, I guess no more grouped M-Wings or whatever it was called. Crying or Very sad

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