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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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 Posted: Sun Aug 26, 2012 6:13 am Post subject: Vanhegan extreme August 26, 2012 |
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| Code: |
*-----------*
|..1|.95|...|
|...|..3|..8|
|..3|1..|...|
|---+---+---|
|83.|.7.|2.5|
|4.9|...|7.3|
|1.5|.2.|.64|
|---+---+---|
|...|..2|5..|
|9..|4..|...|
|...|63.|8..|
*-----------*
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Play/Print this puzzle online |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Sun Aug 26, 2012 2:56 pm Post subject: |
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Code after basics:
| Code: | *-----------------------------------------------------------*
| 267 48 1 | 278 9 5 | 346 237 267 |
| 2567 459 247 | 27 46 3 | 1 2579 8 |
| 2567 4589 3 | 1 468 67 | 46 2579 2679 |
|-------------------+-------------------+-------------------|
| 8 3 6 | 9 7 4 | 2 1 5 |
| 4 2 9 | 5 16 16 | 7 8 3 |
| 1 7 5 | 3 2 8 | 9 6 4 |
|-------------------+-------------------+-------------------|
| 3 146 47 | 78 18 2 | 5 479 1679 |
| 9 16 8 | 4 5 17 | 36 237 1267 |
| 257 145 247 | 6 3 9 | 8 47 17 |
*-----------------------------------------------------------*
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4r2c5=(4-8)r3c5=r3c2-(8=4)r1c2; -4r2c23
I found the above solution only after working on a double almost xy-wing (AAXY-wing ??)
Double Almost XY-wing (18-6) plus transport, fin(4)r3c5 & fin(4)r7c2 => -6r2c5,r3c179
xy-wing: (6=8)r3c5-(8=1)r7c5-(1=6)r7c2-(6=1=7)r8c26-(7=6)r3c6;
fin: (4-8)r3c5=r3c2-(8=4)r1c2-r2c2=r2c5 ==> Conflict; -4r3c5
fin : (4)r7c2-(4=7=8=1)r7c345-(1=7)r8c6-(7=6)r3c6;
Ted |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sun Aug 26, 2012 3:37 pm Post subject: |
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| tlanglet wrote: | | 4r2c5=(4-8)r3c5=r3c2-(8=4)r1c2; -4r2c23 |
Another m-wing 
Note the weak link r3c5 has 3 values. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Aug 26, 2012 4:43 pm Post subject: |
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| Quote: | | 4r2c5=(4-8)r3c5=r3c2-(8=4)r1c2; -4r2c23 |
I don't understand that one. However, using the 48 in r1c2 and 468 in r3c5 yields the same two eliminations. Unfortunately, I missed the fact that that finishes the puzzle. The 46 M-Wing in r2c5 and r3c7 sets r3c2<>4. |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Sun Aug 26, 2012 5:25 pm Post subject: |
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| Marty R. wrote: | | Quote: | | 4r2c5=(4-8)r3c5=r3c2-(8=4)r1c2; -4r2c23 |
I don't understand that one. |
Given that either r2c5=4 or r3c5=4. If r3c5=4 then r3c5<>8, then r3c2=8, then r1c2=4; -4r2c34
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sun Aug 26, 2012 7:20 pm Post subject: |
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| Marty R. wrote: | | Quote: | | 4r2c5=(4-8)r3c5=r3c2-(8=4)r1c2; -4r2c23 |
I don't understand that one. However, using the 48 in r1c2 and 468 in r3c5 yields the same two eliminations. Unfortunately, I missed the fact that that finishes the puzzle. |
Marty,
As you appear to have noticed, Ted's chain follows the classical M-Wing pattern when read right-to-left. It just takes practice to notice the reverse M-Wing in chains like Ted's. As for the remining puzzle solution, basics were not specifically listed prior to Ted's grid, and he didn't list those present after the M-Wing, either. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Aug 26, 2012 7:27 pm Post subject: |
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Thanks Ted.
Easy enough to follow, but Dan referred to it as an M-Wing and if that's correct, then M-Wings have aspects to them that I'm unfamiliar with.
Starting out with noting that one cell or another must be a certain value sounds to me like a DIC as opposed to an M-Wing. |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sun Aug 26, 2012 8:05 pm Post subject: |
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Marty, it is the notation not a new form of m-wing. How is this?
| Code: | *-----------------------------------------------------------*
| 267 a48 1 | 278 9 5 | 346 237 267 |
| 2567 59-4 27-4 | 27 d46 3 | 1 2579 8 |
| 2567 b4589 3 | 1 c468 67 | 46 2579 2679 |
|-------------------+-------------------+-------------------|
| 8 3 6 | 9 7 4 | 2 1 5 |
| 4 2 9 | 5 16 16 | 7 8 3 |
| 1 7 5 | 3 2 8 | 9 6 4 |
|-------------------+-------------------+-------------------|
| 3 146 47 | 78 18 2 | 5 479 1679 |
| 9 16 8 | 4 5 17 | 36 237 1267 |
| 257 145 247 | 6 3 9 | 8 47 17 |
*-----------------------------------------------------------*
m-wing
(4=8)r1c2-r3c2=(8-4)r3c5=4r2c5; -4r2c23; lclste |
If the notation would start at r2c5 it would still be the same.
edit to fix boo-boo |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Aug 26, 2012 9:02 pm Post subject: |
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Danny,
Even though I don't speak Eureka, I would have figured out what was going on had the notation been reversed. I don't understand your comments about basics. After the wing, basics are all that's needed to finish it off, even though I didn't see that when I originally did the puzzle.
Dan,
Your grid with the abcd chain noted is the M-Wing that I used as my first step.
I still think Ted's explanation to me sounds like a DIC.
Thank you both, I always appreciate it when people address my questions. |
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Luke451
Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California
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| Posted: Mon Aug 27, 2012 4:25 am Post subject: |
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| Marty R. wrote: | | Starting out with noting that one cell or another must be a certain value sounds to me like a DIC as opposed to an M-Wing. |
When you make comments like that I think you're doing a bit of a disservice to folks who might be trying to logically figure out some of this stuff.
Once again...that initial inference doesn't say anything about what the value of one cell or another must be. The statement is only that one value must be true. Nothing is said or implied about which one must be true.
Please don't tell us again it's all in the eye of the beholder, Marty. I know that's how you feel, but it just ain't necessarily so.
Sorry to be such a DIC. |
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