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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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 Posted: Sun Nov 24, 2013 11:45 pm Post subject: Nov 25 VH |
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| Code: |
+-------------+---------+--------------+
| *26 5 7 | 3 9 8 | 1 *246 46 |
| 49 1 49 | 7 2 6 | 3 8 5 |
| 8 3 #26 | 5 1 4 | 26 7 9 |
+-------------+---------+--------------+
| 1 29 29 | 46 3 7 | 8 5 46 |
| 7 8 3 | 1 46 5 | 46 9 2 |
| 45 6 45 | 2 8 9 | 7 3 1 |
+-------------+---------+--------------+
| 3 4 25-6 | 9 7 1 | 256 #26 8 |
| 2569 29 1 | 8 46 3 | 24569 2-46 7 |
| 69 7 8 | 46 5 2 | 469 1 3 |
+-------------+---------+--------------+
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W-Wing 26 in BOX 19 with SL 2 in row 1; r7c3<>6 opens single's chains on 4; r8c8<>4; stte. |
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roaa
Joined: 18 Apr 2009
Posts: 112
Location: Sweden
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| Posted: Mon Nov 25, 2013 10:16 am Post subject: Nov 25 VH |
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| An xy-wing (269) opens up a new xy-wing (249) which solves it. |
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hughwill
Joined: 05 Apr 2010
Posts: 424
Location: Birmingham UK
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| Posted: Mon Nov 25, 2013 10:59 am Post subject: Nov 25 VH |
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After basics: | Code: |
+-------------+---------+--------------+
| 26 5 7 | 3 9 8 | 1 246 46 |
| 49 1 49 | 7 2 6 | 3 8 5 |
| 8 3 26 | 5 1 4 | 26 7 9 |
+-------------+---------+--------------+
| 1 29 29 | 46 3 7 | 8 5 46 |
| 7 8 3 | 1 46 5 | 46 9 2 |
| 45 6 45 | 2 8 9 | 7 3 1 |
+-------------+---------+--------------+
| 3 4 256 | 9 7 1 | 256 26 8 |
| 2569 29 1 | 8 46 3 | 24569 246 7 |
| 69 7 8 | 46 5 2 | 469 1 3 |
+-------------+---------+--------------+
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Play this puzzle online at the Daily Sudoku site
Or taking a piece of both solutions: By removing the 6's in r89 in box 9
Clement's W wing leads to roaa's second (249) XY wing. I found this one
very hard to see today for some reason......
Hugh |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Nov 25, 2013 11:51 am Post subject: |
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| I also used the two XY-Wings. These are much more fun when they're not one-steppers. |
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yeoks
Joined: 16 May 2010
Posts: 33
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| Posted: Mon Nov 25, 2013 12:28 pm Post subject: Nov 25 VH |
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| I used Remote Pairs (46) in r5c7 and r9c4 which solves it |
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George Woods
Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK
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| Posted: Wed Nov 27, 2013 8:33 pm Post subject: Chain of 46 single step |
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Taking Clements position and ignoring the w Wing I posited r8c8 as 4 and via r1c9 = 4 went through all the 46s leading to r8c5 being 4. Hence r8c8 cannot be 4 so r1c8 must be 4 which solves the puzzle.
I was not very happy with this solution as it smacked of trial and error, but wonder if it is equivalent to colouring 4. Can anyone tell me?
Last edited by George Woods on Wed Nov 27, 2013 10:27 pm; edited 1 time in total |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Nov 27, 2013 10:46 pm Post subject: Re: Chain of 46 single step |
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| George Woods wrote: | Taking Clements position and ignoring the w Wing I posited r8c8 as 4 and via r1c9 = 4 went through all the 46s leading to r8c5 being 4. Hence r8c8 cannot be 4 so r1c8 must be 4 which solves the puzzle.
I was not very happy with this solution as it smacked of trial and error, but wonder if it is equivalent to colouring 4. Can anyone tell me? |
I don't know what you did to set r8c5=4, but once that is done, you don't need the hence.... It solves from that initial setting of 4. The "hence" part is redundant since it occurs automatically as part of the cleaning up process. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Nov 28, 2013 1:06 am Post subject: Re: Chain of 46 single step |
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| Marty R. wrote: | | George Woods wrote: | Taking Clements position and ignoring the w Wing I posited r8c8 as 4 and via r1c9 = 4 went through all the 46s leading to r8c5 being 4. Hence r8c8 cannot be 4 so r1c8 must be 4 which solves the puzzle.
I was not very happy with this solution as it smacked of trial and error, but wonder if it is equivalent to colouring 4. Can anyone tell me? |
I don't know what you did to set r8c5=4, but once that is done, you don't need the hence.... It solves from that initial setting of 4. The "hence" part is redundant since it occurs automatically as part of the cleaning up process. |
Here's what I did with the 4s.
| Code: | +-------------+-----------+----------------+
| 26 5 7 | 3 9 8 | 1 B246 C46 |
| 49 1 49 | 7 2 6 | 3 8 5 |
| 8 3 26 | 5 1 4 | 26 7 9 |
+-------------+-----------+----------------+
| 1 29 29 | E46 3 7 | 8 5 D46 |
| 7 8 3 | 1 F46 5 | 46 9 2 |
| 45 6 45 | 2 8 9 | 7 3 1 |
+-------------+-----------+----------------+
| 3 4 256 | 9 7 1 | 256 26 8 |
| 2569 29 1 | 8 46 3 | 24569 A246 7 |
| 69 7 8 | 46 5 2 | 469 1 3 |
+-------------+-----------+----------------+ |
Going from A to F or F to A, that is classic coloring, with an even number of cells and the start and end of the chain being T-F or F-T.
However, you said you set r8c5=4 but the coloring says it's <>4. |
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George Woods
Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK
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| Posted: Thu Nov 28, 2013 11:34 am Post subject: colouring of 4s |
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| My explanation maybe wasn't clear. What I might have said is that r8c8 cannot be 4, because if it were it leads to r8c5 being 4 also ---- and that is not valid hence r8c8 cannot be 4 and since r8c8 cannot be 4 the value of r8c5 is unknown as yet but the value of r1c8 is now kown to be 4 and the puzzle falls out |
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Jeff
Joined: 06 May 2007
Posts: 46
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| Posted: Fri Nov 29, 2013 4:48 am Post subject: Re: Nov 25 VH |
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| roaa wrote: | | An xy-wing (269) opens up a new xy-wing (249) which solves it. |
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I think I see the 269 xy-wing with c1r9 (69), c2r8(29), and c1r1(26). This eliminates the 2 in c1r8, which does not seem to make much progress. I certainly can't find the 249 xy-wing and would appreciate some comments. Maybe I am missing something obvious. Thanks. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Nov 29, 2013 5:15 am Post subject: Re: Nov 25 VH |
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| Jeff wrote: | | roaa wrote: | | An xy-wing (269) opens up a new xy-wing (249) which solves it. |
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I think I see the 269 xy-wing with c1r9 (69), c2r8(29), and c1r1(26). This eliminates the 2 in c1r8, which does not seem to make much progress. I certainly can't find the 249 xy-wing and would appreciate some comments. Maybe I am missing something obvious. Thanks. |
Removing that 2 from r8c1 leaves r1c1 as the only remaining 2 in c1. Carrying on from there exposes the 249 Wing. Pay careful attention to the 6s in c1 and r7. |
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Jeff
Joined: 06 May 2007
Posts: 46
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| Posted: Fri Nov 29, 2013 4:03 pm Post subject: Re: Nov 25 VH |
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| Marty R. wrote: | | Jeff wrote: | | roaa wrote: | | An xy-wing (269) opens up a new xy-wing (249) which solves it. |
.
I think I see the 269 xy-wing with c1r9 (69), c2r8(29), and c1r1(26). This eliminates the 2 in c1r8, which does not seem to make much progress. I certainly can't find the 249 xy-wing and would appreciate some comments. Maybe I am missing something obvious. Thanks. |
Removing that 2 from r8c1 leaves r1c1 as the only remaining 2 in c1. Carrying on from there exposes the 249 Wing. Pay careful attention to the 6s in c1 and r7. |
Thank you so much. Somehow, I missed those key points. Jeff |
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