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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Nov 12, 2014 6:00 am Post subject: Nov 11 VH |
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Code: |
+---------+----------+------------+
| 7 9 3 | 1 4 6 | 2 5 8 |
| 26 4 1 | 23 5 8 | 369 7 69 |
| 5 8 26 | 237 9 37 | 36 1 4 |
+---------+----------+------------+
| 4 2 69 | 5 7 1 | 8 69 3 |
| 3 1 8 | 6 2 9 | 5 4 7 |
| 69 7 5 | 8 3 4 | 69 2 1 |
+---------+----------+------------+
| 8 5 29 | 37 1 37 | 4 69 269 |
| 29 3 7 | 4 6 5 | 1 8 29 |
| 1 6 4 | 9 8 2 | 7 3 5 |
+---------+----------+------------+
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Play this puzzle online at the Daily Sudoku site
Quote: | XY-Wing (26-9), pivot r2c1=>r8c9<>9 | [/quote] |
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Wed Nov 12, 2014 3:06 pm Post subject: Nov 11 VH |
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Good to see you getting in there early again Marty.
For those of us who sometimes see different solutions (and usually more cumbersome solutions) there is a W-wing of 69 in r2c9 and r4c8 eliminating the candidate 9 in r8c1 which also quickly solves. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Nov 12, 2014 4:27 pm Post subject: |
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Lee, I'm unable to find a W-Wing that makes an elimination. |
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Wed Nov 12, 2014 4:59 pm Post subject: |
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Marty,
Sorry, I made a typo, the elimination of candidate 9 should have been in r7c3.
69 in r2c9 sees 269 in r7c9 which has a strong link on 6 to 69 in r7c8 which sees 69 in r4c8, thus 9 is eliminated in r7c3.
I think I have it right now. My mind and fingers sometimes don't work together very well. |
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Wed Nov 12, 2014 5:32 pm Post subject: Nov 11 VH |
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Marty, and everyone else. I'm so sorry. Take back everything I said. I had W-wing definitions fouled up. If there is a W-wing elimination it certainly isn't what I said.
Sorry again. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Nov 12, 2014 6:00 pm Post subject: |
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Lee wrote: | Marty,
Sorry, I made a typo, the elimination of candidate 9 should have been in r7c3.
69 in r2c9 sees 269 in r7c9 which has a strong link on 6 to 69 in r7c8 which sees 69 in r4c8, thus 9 is eliminated in r7c3.
I think I have it right now. My mind and fingers sometimes don't work together very well. |
Lee, I'm still not seeing it. Neither r2c9 nor r4c8 sees r7c3. The only way an elimination can occur in r7c3 is if the W-Wing were on cells r4c3 and r7c8. |
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Wed Nov 12, 2014 8:13 pm Post subject: Nov 11 VH |
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Marty,
See my post immediately before your last comment. I'm sorry, but apparently my mind has turned to mush. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Nov 12, 2014 8:17 pm Post subject: |
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Lee, if I can be of any help with the W-Wing, don't hesitate to ask. |
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Thu Nov 13, 2014 2:43 am Post subject: Nov 11 VH |
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Thanks Marty, I appreciate it! |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu Nov 13, 2014 4:27 pm Post subject: |
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For openers, we need two identical bivalue cells, let's say they contain XY. There needs to be a strong link somewhere (just two possibilities) on either X or Y and each of our bivalue cells must see one of the possibilities in the strong link. Whether the strong link is on X or Y, our two bivalue cells become pincers on the other number. Any cell(s) seeing both of our bivalue cells may not contain that nbumber. Back to the puzzle:
Code: |
+---------+----------+------------+
| 7 9 3 | 1 4 6 | 2 5 8 |
| 26 4 1 | 23 5 8 | 369 7 69 |
| 5 8 26 | 237 9 37 | 36 1 4 |
+---------+----------+------------+
| 4 2 69 | 5 7 1 | 8 69 3 |
| 3 1 8 | 6 2 9 | 5 4 7 |
| 69 7 5 | 8 3 4 | 69 2 1 |
+---------+----------+------------+
| 8 5 29 | 37 1 37 | 4 69 269 |
| 29 3 7 | 4 6 5 | 1 8 29 |
| 1 6 4 | 9 8 2 | 7 3 5 |
+---------+----------+------------+
You pointed out that there is a W-Wing on the 69 cells in r2c9 and r4c8. There are strong links in c7 on both 6 and 9. Both numbers can be removed from any cell(s) that see both r2c9 and r4c8. However, no eliminations can be made because no cell sees both those cells.
Hope this helps.
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Lee
Joined: 10 Jun 2014 Posts: 24 Location: San Francisco
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Posted: Thu Nov 13, 2014 7:26 pm Post subject: Nov 11 VH |
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Got it, thanks again Marty. |
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dongrave
Joined: 06 Mar 2014 Posts: 568
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Posted: Fri Nov 14, 2014 12:05 am Post subject: |
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Hi Marty, I just thought I'd mention that there's also a 269 XY wing with the pivot at r2c9 which forces r8c1<>2 which also solves it. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Fri Nov 14, 2014 4:11 pm Post subject: |
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Don, I used the 26-9 XY-Wing pivoted in r2c1. |
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dongrave
Joined: 06 Mar 2014 Posts: 568
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Posted: Sat Nov 15, 2014 1:50 am Post subject: |
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Hi Marty, Yes, I know. I always check the VH solutions that are posted here and when I saw that your XY had a different pivot than mine, I thought I'd post it. That probably explains why I solved it twice as fast as normal - because there were two solutions sitting right there in front of me! |
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fantazi-ic-giyim
Joined: 07 Dec 2014 Posts: 1
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Posted: Sun Dec 07, 2014 6:46 pm Post subject: thanks |
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thanks for share |
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lucygp
Joined: 29 Dec 2014 Posts: 3
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Posted: Mon Dec 29, 2014 8:01 am Post subject: |
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I saw that your XY had a different pivot than mine
________________________________
Fifa 15 coins |
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