dailysudoku.com

[Bill Denholm]

I was trying to play the May 23 puzzle, but I got stuck, so I asked for a hint. The program gave me: 2 at R6, C3. I don't see the logic (if I did, I wouldn't have needed a hint). Can somebody explain the logic to me? Thanks.

Bill

[Charles]

Bill: Two is restricted to R9C1 and R9C2 - thus other twos in block 7 can be excluded. Good Luck. Charles

[Marty R.]

I agree with Charles. After eliminating those other 2s, the puzzle is broken wide open.

[guest]

There are 6 linked pairs

r1c9 5 8
r2c7 8 5

r8c7 5 2
r7c9 2 5

r4c7 2 8
r4c9 8 2

r1c5 8 1
r2c6 1 8

r5c5 1 2
r6c6 2 1

r8c5 2 8
r7c6 8 2

Either the first option (column) or second option has a 2 at r4, r7 and r8.
That leads to r6c3 2.

[Bill Denholm]

I'll have to study it some more, since I still don't understand it. I agree with guest about the linked pairs, I found them, too.

Charles, the hint was for a 2 in block four, not block 7, but thanks, anyway.

Bill

[Charles]

Bill: The exclusion of twos in block 7 is what allowed/forced the choice for two in block 4.

[guest]

Bill

I should explain the linked pair a little further. The linked pairs put
a 2 at row 4, 7 and 8. Now look at column 3: the only place the 2 can
go is at row 6

[Bill Denholm]

Charles,

I am still having problems seeing how the 2s in block 7 are restricted to R9C1 and R9C2. I think they probably are, but there seems to be a missing step somewhere. What I see when I look at my block 7 is this:

000 | 003 | 120
000 | 000 | 056
700 | 000 | 080

000 | 020 | 120
000 | 056 | 056
009 | 080 | 080

120 | 020 | 000
050 | 050 | 400
080 | 080 | 000

I assume that you see something else.

Bill

[David Bryant]

I'm puzzled by this entire discussion. I think that a picture is worth a thousand words.