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roaa
Joined: 18 Apr 2009
Posts: 112
Location: Sweden
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 Posted: Wed Apr 01, 2015 8:27 am Post subject: Apr 1 VH |
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| One of several X-wings 179 gives r2c6=6, which solves it. |
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hughwill
Joined: 05 Apr 2010
Posts: 424
Location: Birmingham UK
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| Posted: Wed Apr 01, 2015 10:05 am Post subject: Re: Apr 1 VH |
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| roaa wrote: | | One of several X-wings 179 gives r2c6=6, which solves it. |
After basics:
| Code: |
+-----------+----------+---------+
| 4 8 19 | 17 3 2 | 6 5 79 |
| 167 79 3 | 8 5 16 | 19 4 2 |
| 16 5 2 | 4 67 9 | 18 3 78 |
+-----------+----------+---------+
| 8 3 7 | 9 2 4 | 5 1 6 |
| 2 4 5 | 17 67 16 | 39 8 39 |
| 9 1 6 | 5 8 3 | 7 2 4 |
+-----------+----------+---------+
| 3 6 8 | 2 9 5 | 4 7 1 |
| 5 2 4 | 6 1 7 | 38 9 38 |
| 17 79 19 | 3 4 8 | 2 6 5 |
+-----------+----------+---------+
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Play this puzzle online at the Daily Sudoku site
Yes indeed- the 167-XY wing also removes the 1 in r1c3 and this can also
be done by a W-wing on 17.
On the one hand- nice to get a double VH to end and start the month
On the other- Yet another 1 stepper (though with more than one
solution.....). |
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