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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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 Posted: Thu May 21, 2015 11:17 pm Post subject: May 22 VH |
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| Code: |
+---------------+-------------+---------------+
| 1 369 7 | 36 5 8 | 369 4 2 |
| 358 3568 4 | 2 9 67 | 356 367 1 |
| 359 2 69 | 367 4 1 | 8 3679 3567 |
+---------------+-------------+---------------+
| 358 358 2 | 49 7 49 | 356 1 3568 |
| 6 7 1 | 5 8 3 | 4 2 9 |
| 3589 4 89 | 1 6 2 | 7 38 358 |
+---------------+-------------+---------------+
| 2 689 3 | 4679 1 4679 | 69 5 78 |
| 4 689 689 | 679 2 5 | 1 378 378 |
| 7 1 5 | 8 3 69 | 2 69 4 |
+---------------+-------------+---------------+
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X-Wing on 5 in r36; r24c1, r4c9<>5; lclste |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri May 22, 2015 5:32 am Post subject: |
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| You did better than me. I used X-Wings on 5 and 8. |
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danw
Joined: 31 Jul 2012
Posts: 16
Location: Phoenixville, PA USA
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| Posted: Fri May 22, 2015 10:10 am Post subject: |
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You both did better then me, to be honest I still don't see Clement's solution after x wings on 5. I needed the x wing on 5's then x wing on 3's (r68) then xyz wing 679 (pivot r3c8).
I was totally challenged and really had a lot of fun though.
DanW |
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hughwill
Joined: 05 Apr 2010
Posts: 424
Location: Birmingham UK
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| Posted: Fri May 22, 2015 12:30 pm Post subject: May 22 VH |
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| Code: |
+---------------+-------------+---------------+
| 1 369 7 | 36 5 8 | 369 4 2 |
| 358 3568 4 | 2 9 67 | 356 367 1 |
| 359 2 69 | 367 4 1 | 8 3679 3567 |
+---------------+-------------+---------------+
| 358 358 2 | 49 7 49 | 356 1 3568 |
| 6 7 1 | 5 8 3 | 4 2 9 |
| 3589 4 89 | 1 6 2 | 7 38 358 |
+---------------+-------------+---------------+
| 2 689 3 | 4679 1 4679 | 69 5 78 |
| 4 689 689 | 679 2 5 | 1 378 378 |
| 7 1 5 | 8 3 69 | 2 69 4 |
+---------------+-------------+---------------+
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Play this puzzle online at the Daily Sudoku site
I can see that the X-wing on 5 is a one-stepper, though it needs a naked
pair and two box-lines on 3's to come to the crucial elimination leaving r3c4=3.
I didn't see an X wing on 8 nor did I understand Clement's elimination (and
this is despite just having had a holiday!).
Hugh |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri May 22, 2015 3:12 pm Post subject: |
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| Clement made eliminations on 5 in r24c1 and r4c9. It took me a while before I figured it out. I don't see an X-Wing on 8 either, but I could easily play a wing that isn't there. |
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danw
Joined: 31 Jul 2012
Posts: 16
Location: Phoenixville, PA USA
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| Posted: Sat May 23, 2015 9:38 am Post subject: |
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Thanks Hugh for explaining the box lines on 3's. It is one of my weaknesses not following through on all the basics once I have found an elimination. Even my x wing on 3's would have been enough to discover that same elimination but I needed to add an XYZ wing to my solution. Learning and striving for efficiency and I appreciate the lessons.
DanW |
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