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Unfair 081820

 
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immpy



Joined: 06 May 2017
Posts: 571
PostPosted: Tue Aug 18, 2020 7:10 pm    Post subject: Unfair 081820 Reply with quote
Hello all, enjoy the puzzle...

Code:

+-------+-------+-------+
| 9 1 7 | 2 . . | . . 8 |
| 5 . . | . . . | . . . |
| . . 4 | . 9 1 | . . . |
+-------+-------+-------+
| 7 . . | . 6 . | 9 . . |
| 8 . 6 | 1 . 2 | 5 . . |
| . . 3 | . 7 . | . . 6 |
+-------+-------+-------+
| . . . | 8 2 . | 4 . . |
| . . . | . . . | . . 7 |
| 4 . . | . 3 7 | . 1 5 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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dongrave



Joined: 06 Mar 2014
Posts: 568
PostPosted: Wed Aug 19, 2020 2:07 pm    Post subject: Reply with quote
Code:

+-------------+--------------+---------------+
| 9   1    7  | 2    5  346  | 36   346  8   |
| 5   36   2  | 3467 8  346  | 1367 9    14  |
| 36  8    4  | 367  9  1    | 367  5    2   |
+-------------+--------------+---------------+
| 7   245  15 | 35   6  358  | 9    248  14  |
| 8   9    6  | 1    4  2    | 5    7    3   |
| 12  245  3  | 59   7  589  | 128  248  6   |
+-------------+--------------+---------------+
| 136 7    15 | 8    2  56   | 4    36   9   |
| 236 2356 89 | 4569 1  4569 | 2368 2368 7   |
| 4   26   89 | 69   3  7    | 268  1    5   |
+-------------+--------------+---------------+

Is the following Eureka notation right?  I modeled it after a recent post of Clement's that did something similar. 
I'm trying to represent the following: if r4c3 is not a 1 then it's a 5 and r4c4 is a 3
and then later on that cell r3c4 = 7 because of the -3 from r4c4 and the -6 from r3c1. 
Thanks ahead of time for any feedback, Don.

(1=5,3)r4c3,r4c4-(5=24)r46c2-(2=6)r9c2-r2c2=r3c1-(36=7)r3c4-(7=36)r13c7-(36=4)r1c8-(4=1)r2c9 => r4c9<>1; stte.

How is the person reading this supposed to know that the 3 mentioned so much earlier is being referenced for the step '-(36=7)r3c4'?' 
Maybe something like the following would be clearer?

(1=5)r4c3[-(5=3)r4c4]
         [-(5=24)r46c2-(2=6)r9c2-r2c2=r3c1]
          -(36=7)r3c4-(7=36)r13c7-(36=4)r1c8-(4=1)r2c9 => r4c9<>1; stte.

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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
PostPosted: Thu Aug 20, 2020 11:39 am    Post subject: Reply with quote
dongrave wrote:
Code:


Is the following Eureka notation right?  I modeled it after a recent post of Clement's that did something similar. 
I'm trying to represent the following: if r4c3 is not a 1 then it's a 5 and r4c4 is a 3
and then later on that cell r3c4 = 7 because of the -3 from r4c4 and the -6 from r3c1. 
Thanks ahead of time for any feedback, Don.

(1=5,3)r4c3,r4c4-(5=24)r46c2-(2=6)r9c2-r2c2=r3c1-(36=7)r3c4-(7=36)r13c7-(36=4)r1c8-(4=1)r2c9 => r4c9<>1; stte.

How is the person reading this supposed to know that the 3 mentioned so much earlier is being referenced for the step '-(36=7)r3c4'?' 
Maybe something like the following would be clearer?

(1=5)r4c3[-(5=3)r4c4]
         [-(5=24)r46c2-(2=6)r9c2-r2c2=r3c1]
          -(36=7)r3c4-(7=36)r13c7-(36=4)r1c8-(4=1)r2c9 => r4c9<>1; stte.

Good solution Dongrave, The chain is right as far as I am concerned except for minor modifications. The second term should look like this (5=2|4)r46c2 to show that they appear in pairs and (7=3|6)r13c7 for the same reason.
Up to now the Eureka Notation is not exhaustive to carter for complex chains like this. New symbols are still being suggested/discussed in some forums. When a candidate is needed for reference later it can be marked with a symbol say * or any in the chain or grid. In your chain you could have marked it like (1=5,3*)r4c3, r4c4, then refer it (3*6=7)r3c4.
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dongrave



Joined: 06 Mar 2014
Posts: 568
PostPosted: Thu Aug 20, 2020 12:00 pm    Post subject: Reply with quote
Ah! I see! Thanks for your help Clement! It's much appreciated! Don.
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
PostPosted: Thu Aug 20, 2020 4:31 pm    Post subject: Unfair 081820 Reply with quote
Code:

+--------------------+-------------------+----------------------+
| 9      1       7   | 2       5    346  |h36       i346     8  |
| 5      36      2   | 3467    8    346  |h1367      9      j14 |
| 36     8       4   | 367     9    1    |h367       5       2  |
+--------------------+-------------------+----------------------+
| 7     m245   ld15  | 35      6    358  | 9         248     k14|
| 8      9       6   | 1       4    2    | 5         7        3 |
|c12    m245     3   | 59      7    589  | 128       248      6 |
+--------------------+-------------------+----------------------+
| 136    7      e15  | 8       2   e56   | 4         36       9 |
|b236    2356    589 | 4569    1    4569 | 2368      2368     7 |
| 4    ba6*-2    89  |f6*9     3    7    |g268       1        5 |
+--------------------+-------------------+----------------------+

Just for fun when things get hot
2r9c2 - [(2)r8c1-(6*)r9c2] = (2-1)r6c1 = r4c3 - (1=56)r7c36 - (6*)r9c4 = (6)r9c7 - 123c7 = (6-4)r1c8 = (4-1)r2c9 = r4c9 - (1=5)r4c3 - (5=2|4)r46c2 => - 2r9c2; stte
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