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ZeroAssoluto
Joined: 05 Feb 2017 Posts: 941 Location: Rimini, Italy
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Posted: Sun Sep 19, 2021 11:54 am Post subject: Sep 19 VH |
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Hi everyone,
Code: |
+--------------+-----------+---------------+
| 3789 3679 68 | 367 2 4 | 3569 1356 136 |
| 5 36 4 | 136 69 19 | 2 7 8 |
| 379 2 1 | 367 8 5 | 369 4 36 |
+--------------+-----------+---------------+
| 4 16 9 | 8 5 2 | 7 136 136 |
| 2 1567 68 | 4 3 67 | 56 1568 9 |
| 78 567 3 | 9 1 67 | 4 568 2 |
+--------------+-----------+---------------+
| 6 8 5 | 2 4 3 | 1 9 7 |
| 39 4 2 | 16 7 19 | 8 36 5 |
| 1 39 7 | 5 69 8 | 36 2 4 |
+--------------+-----------+---------------+
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Play this puzzle online at the Daily Sudoku site
in one step AIC in r1c3
if r1c3 is 6 -6 in r12c2,r5c3
if r1c3 is 8 r5c8=8 r5c2=1 r4c2=6 and -6 in r12c2,r5c3
or in 2 steps
first
XY-Wing 3,6,9 in r2c25,r9c2 and -9 in r9c5
Code: |
+-------------+----------+-------------+
| 789 367 68 | 367 2 4 | 569 135 136 |
| 5 36 4 | 36 9 1 | 2 7 8 |
| 79 2 1 | 367 8 5 | 69 4 36 |
+-------------+----------+-------------+
| 4 16 9 | 8 5 2 | 7 13 136 |
| 2 1567 68 | 4 3 67 | 56 158 9 |
| 78 567 3 | 9 1 67 | 4 58 2 |
+-------------+----------+-------------+
| 6 8 5 | 2 4 3 | 1 9 7 |
| 3 4 2 | 1 7 9 | 8 6 5 |
| 1 9 7 | 5 6 8 | 3 2 4 |
+-------------+----------+-------------+
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Play this puzzle online at the Daily Sudoku site
second step
XY-Wing 5,6,8 in r5c37,r6c8 and -8 in r5c8,r6c1
Ciao Gianni |
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TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
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Posted: Sun Sep 19, 2021 1:38 pm Post subject: |
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I used two XY wings
first XY 678 -7 in r5c2 and r6c6
then the same second step as Gianni |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Sun Sep 19, 2021 3:00 pm Post subject: |
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Looking at Gianni's AIC we can see that pincers for 6 are at r1c3 and r4c2 - one of these pincers must be 6.
Eureka as follows.
Even when we set r1c3 to "not 6" ie 8, the other pincer r4c2 is 6 removing r12c2,r5c3
8-6(r1c3)=(6-8)r5c3=(8-156)=1(r5c2)-(1=6)r4c2
Going the other way, if we set the other pincer r4c2 to "not 6" ie 1, then r1c3 is 6 also removing r12c2,r5c3
6=1(r4c2)-(r5c2)=(1-568)r5c8=(8-6)r5c3=(6-8)r1c3 |
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