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Mar 09 VH

 
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 940
Location: Rimini, Italy
PostPosted: Wed Mar 09, 2022 9:42 am    Post subject: Mar 09 VH Reply with quote
Hi everyone,

Code:

+---------------+------------+---------+
| 34  6    9    | 245 24  57 | 1 37 8  |
| 5   7    12   | 3   16  8  | 9 4  26 |
| 8   134  1234 | 9   146 17 | 5 37 26 |
+---------------+------------+---------+
| 7   148  148  | 14  9   2  | 6 5  3  |
| 13  9    6    | 158 138 15 | 7 2  4  |
| 2   5    34   | 7   34  6  | 8 1  9  |
+---------------+------------+---------+
| 6   18   5    | 128 128 4  | 3 9  7  |
| 9   2    7    | 6   5   3  | 4 8  1  |
| 134 1348 1348 | 18  7   9  | 2 6  5  |
+---------------+------------+---------+

Play this puzzle online at the Daily Sudoku site

XYZ-Wing 1,5,8 in r5c46,r9c4 and -1 in r4c4

Ciao Gianni
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Wed Mar 09, 2022 11:40 am    Post subject: Reply with quote
Code:

+----------------+-------------+---------+
| 34   6    9    | 245 24  57c | 1 37d 8 |
| 5    7    12   | 3   16  8   | 9 4  26 |
| 8    134  1234 | 9   146 17  | 5 37 26 |
+----------------+-------------+---------+
| 7    148  148  | 14  9   2   | 6 5  3  |
| 13a  9    6    | 158 138 15b | 7 2  4  |
| 2    5    34   | 7   34  6   | 8 1  9  |
+----------------+-------------+---------+
| 6    18   5    | 128 128 4   | 3 9  7  |
| 9    2    7    | 6   5   3   | 4 8  1  |
| 134  1348 1348 | 18  7   9   | 2 6  5  |
+----------------+-------------+---------+

Pincers on <3> in a + d means r1c1<> 3
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Mogulmeister



Joined: 03 May 2007
Posts: 1151
PostPosted: Fri Mar 11, 2022 5:10 pm    Post subject: Reply with quote
Not a VH technique but helps in general solving to look at the "dark side".

What happens if you say r1c1 = 3 ? Follow Tom's a-b-c-d. You end up with another 3 in r1c8. Not possible. R1c3 can not = 3.
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Fri Mar 11, 2022 6:40 pm    Post subject: Reply with quote
Another contradiction:

If c=5, b=1, a=3, r1c1=4, r1c5=2 leaves r1c4 with absolutely nothing in it at all!

So c must be <7>


(Or you could see it as an ANP <245> in r1)
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