View previous topic :: View next topic |
Author |
Message |
ZeroAssoluto
Joined: 05 Feb 2017 Posts: 941 Location: Rimini, Italy
|
Posted: Fri Nov 11, 2022 10:26 am Post subject: Nov 11 VH |
|
|
Hi everyone,
Code: |
+-------------+---------------+-----------------+
| 4 15 9 | 6 8 17 | 257 3 25 |
| 17 6 378 | 2 5 137 | 478 478 9 |
| 2 35 3578 | 4 9 37 | 5678 1 56 |
+-------------+---------------+-----------------+
| 3 7 26 | 5 124 469 | 12469 469 8 |
| 8 49 1 | 7 24 469 | 3 4569 2456 |
| 5 49 26 | 139 1234 8 | 12469 469 7 |
+-------------+---------------+-----------------+
| 17 8 3457 | 139 6 2 | 4579 4579 345 |
| 6 135 357 | 1389 134 49 | 5789 2 35 |
| 9 2 34 | 38 7 5 | 468 468 1 |
+-------------+---------------+-----------------+
|
Play this puzzle online at the Daily Sudoku site
Quote: | X-Wing with number 7 in r27c18 and -7 in r2c367,r7c37
AND
W-wing 3,8 in r2c3,r9c4 SL with number 8 in r29c8 and -3 in r9c3
AND
XY-Wing 1,3,7 in r2c16,r3c6 and -7 in r3c3
OR with only 1 step with some AIC
if r2c1=7 -7 in r23c3,r7c1
if r2c1=1 r1c6=1 r1c7=7 r8c3=7 and -7 in r23c3,r7c1
OR
if r2c3=3 -3 in r3c2,r789c3
if r2c3 is not 3 r2c6=3 r2c1=1 r7c1=7 r2c8=7 r1c6=7 r3c6=3 r8c2=3 and -3 in r3c2,r789c3 |
Ciao Gianni |
|
Back to top |
|
|
TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
|
Posted: Fri Nov 11, 2022 1:29 pm Post subject: |
|
|
Remove <1> from r2c1 to solve
Code: |
+-----------------+-----------------+---------------------+
| 4 m15 9 | 6 8 x17 | e257 3 f25 |
| a17 6 378 | 2 5 137 | 478 d478 9 |
| 2 35 3578 | 4 9 37 | 5678 1 56 |
+-----------------+-----------------+---------------------+
| 3 7 26 | 5 124 469 | 12469 469 8 |
| 8 49 1 | 7 24 469 | 3 4569 2456 |
| 5 49 26 | 139 1234 8 | 12469 469 7 |
+-----------------+-----------------+---------------------+
| b17 8 3457 | 139 6 2 | 4579 c4579 345 |
| 6 135 357 | 1389 134 49 | 5789 2 35 |
| 9 2 34 | 38 7 5 | 468 468 1 |
+-----------------+-----------------+---------------------+
|
The X-wing on <7> in abcd and the <1>'s in mx produce the contradiction:
If a=1 then d=7, e<>7, x=7
If a=1 then m<>1, x=1 |
|
Back to top |
|
|
TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
|
Posted: Fri Nov 11, 2022 3:02 pm Post subject: |
|
|
Another way to look at this is an Almost Naked Pair in r1c79 (ef)
If r1c79 is a <25> pair then m=1, a=7
If r1c79 is NOT a <25> pair then e=7, d<>7, c=7, b<>7, a=7 |
|
Back to top |
|
|
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum
|
Powered by phpBB © 2001, 2005 phpBB Group
|