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xMetaRidley
Joined: 30 Sep 2006 Posts: 2
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Posted: Sat Sep 30, 2006 9:24 pm Post subject: Sept 17th Hard, Hint |
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I am pretty new to sudoku, and have been stuck on this one for a while. When I asked for the hint, it gave me this. Any ideas of the logic behind it? |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Sep 30, 2006 9:37 pm Post subject: Naked triple |
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Look in the last three cells of Row 9. They contain a triple <368>; 3 cells, 3 possibilities.
So, you can clear these possibilities from the other cells in the row (and in Box 9). In particular, R9C5 is not <68>, it must be <2>.
I think the rest of the puzzle is routine.
Keith |
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xMetaRidley
Joined: 30 Sep 2006 Posts: 2
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Posted: Sat Sep 30, 2006 9:45 pm Post subject: |
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I see, thanks |
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ravel
Joined: 21 Apr 2006 Posts: 536
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Posted: Sat Sep 30, 2006 9:58 pm Post subject: |
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What you dont need:
1 in row 2 can only be in box 3 => r1c79<>1, r3c79<>1 => r2c8=1
(which would have been my hint)
or:
5 in box 1 can only be in row 3 => r3c9<>5
5 in box 9 can only be in row 7 => r7c123<>5
1 in column 7 can only be in box 1 => r2c8<>1, r123c9<>1
8 in row 8 can only be in box 7 => r79c13<>8
(Keith already told you) What you need:
Hidden triple 479 in r9c134 => r9c1<>368,r9c34<>28 |
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