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Earl
Joined: 30 May 2007 Posts: 677 Location: Victoria, KS
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Posted: Thu Jun 28, 2007 6:33 pm Post subject: Help ! |
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"Hint" says that R5C7 is 8. Why?
Thanks
Earl
Code: |
+----------------+------------+--------------+
| 7 134 5 | 8 146 2 | 9 136 134 |
| 1368 1348 34 | 5 146 9 | 346 2 7 |
| 16 9 2 | 3 7 46 | 5 8 14 |
+----------------+------------+--------------+
| 389 5 39 | 2 48 34 | 1 7 6 |
| 4 368 7 | 1 9 36 | 38 5 2 |
| 2 368 1 | 7 68 5 | 34 9 348 |
+----------------+------------+--------------+
| 15 2 6 | 9 3 8 | 7 4 15 |
| 359 7 349 | 46 25 1 | 2368 36 358 |
| 135 134 8 | 46 25 7 | 236 136 9 |
+----------------+------------+--------------+
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Steve R
Joined: 24 Oct 2005 Posts: 289 Location: Birmingham, England
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Posted: Thu Jun 28, 2007 7:59 pm Post subject: |
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Because you can eliminate 8 from r6c9 using the xy-wing for (36) pivoted on r5c6 with pincers r5c7 and r6c5.
Steve |
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