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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sat Dec 15, 2007 1:40 pm Post subject: Dec 15 vh |
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One single xy-wing.
Doesn't seem to do much (removes 3 out of a cell with 5! candidates {3,4,7,8,9}).
But it solves the puzzle.
Better fill in your PMs, guys....
Hm ... Is that a semi-O-wing then?
_______
For you friends of w-wings out there:
(8)r1c8= [83-35-57-76-63-38] =(8)r9c7; removes a LOT of "8"s in r7c8 r1c7 r2c7 r3c7. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Dec 15, 2007 2:51 pm Post subject: |
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There are two UR's, but they don't solve the puzzle. Here is the grid after basics:
Code: | +-------------------+-------------------+-------------------+
| 89 4 35% | 6 5789 1 | 3789 38@ 2 |
| 2 7 6 | 4 589 3 | 89 1 59 |
| 89 3-5 1 | 2 5789 79 | 34789 6 459 |
+-------------------+-------------------+-------------------+
| 7 29 29 | 3 4 6 | 1 5 8 |
| 5 1 4 | 8 79 79 | 6 2 3 |
| 3 6 8 | 1 2 5 | 49 7 49 |
+-------------------+-------------------+-------------------+
| 6 89 79 | 5 13 4 | 2 38# 17 |
| 4 23 23 | 7 16 8 | 5 9 16 |
| 1 58% -57 | 9 36 2 | 38@ 4 67 |
+-------------------+-------------------+-------------------+
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I do not see that the cells @, R1C8 and R9C7 are a W-wing. They are linked through the pair <38> # in R7C8. All you can say is that R1C8 and R9C7 have the same value. They are either both <3>, or both are <8>.
But, they are very useful! Take a look at R1 and R9. There is an extended XY-wing: <35> <38> <38> <38> <58>, %-@-#-@-% which takes out <5> in R3C2 and R9C3, solving the puzzle.
Keith
Last edited by keith on Sat Dec 15, 2007 3:23 pm; edited 1 time in total |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sat Dec 15, 2007 3:17 pm Post subject: |
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keith and nataraj,
You are both right. It is a W-Wing via that XY Chain: one or both must be <8>. And, via the single {38} bivalue, both must be <3> or both must be <8>. The only option that satisfies both demands is: both must be <8>, which is indeed the case. |
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cgordon
Joined: 04 May 2007 Posts: 769 Location: ontario, canada
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Posted: Sat Dec 15, 2007 3:26 pm Post subject: |
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I used a UR <79> R35 to leave <58> in R3C5
then a <589> xy-wing; pivot <89> in R2C7 that removed <5> in R2C5
then another UR <49> in C79
then a <358> xy-wing; pivot <58> R9C2 that removed <3> from R3C7
Sure - it could have been done in one step - but I had fun !!
BTW. I am very pleased to see something like 6 VHs in the last 10 days. Thank you. That's the way it should be. Let the plebs get their easy puzzles in the tabloids and leave this Forum to the sophisticates like what we are. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Dec 15, 2007 3:28 pm Post subject: |
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Quote: | Take a look at R1 and R9. There is an extended XY-wing: <35> <38> <38> <38> <58>, %-@-#-@-% which takes out <5> in R3C2 and R9C3, solving the puzzle. |
Same solution here. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Dec 15, 2007 3:34 pm Post subject: |
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Asellus wrote: | keith and nataraj,
You are both right. It is a W-Wing via that XY Chain: one or both must be <8>. And, via the single {38} bivalue, both must be <3> or both must be <8>. The only option that satisfies both demands is: both must be <8>, which is indeed the case. |
Asellus,
Thank you. I am inclined not to call it a W-wing which, in my mind, is usually a three-link chain WX-X=X-WX with pincers W.
Nataraj,
I apologize that I more or less missed your point.
Keith |
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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sat Dec 15, 2007 4:10 pm Post subject: |
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no problem, keith. And thanks, Asellus for your explanation. I can see that the "shorthand" notation for my xy-chain was too confusing. I was just too lazy to note all the steps in the chain with r1c3 ...
And to avoid any other misunderstanding: my xy-wing was 35-58-38 with pivot r9c2. It tkes out the "3" in r3c7 which makes 3 in r3c2 a hidden single. |
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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sat Dec 15, 2007 8:02 pm Post subject: |
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cgordon wrote: | ... and leave this Forum to the sophisticates like what we are. |
Are you being serious, cgordon, or just the tiniest bit trolling ?
____
edit. I checked. The last time anybody posted in this forum about a NOT vh puzzle was on Oct 30 by one "cgordon"
Quote: | BTW. I am very pleased to see something like 6 VHs in the last 10 days. Thank you. | I couldn't agree more. |
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cgordon
Joined: 04 May 2007 Posts: 769 Location: ontario, canada
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Posted: Sat Dec 15, 2007 8:26 pm Post subject: |
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Quote: | The last time anybody posted in this forum about a NOT vh puzzle was on Oct 30 by one "cgordon" |
That's when I was a neophyte and a philistine. |
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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sat Dec 15, 2007 8:40 pm Post subject: |
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cgordon wrote: | Quote: | The last time anybody posted in this forum about a NOT vh puzzle was on Oct 30 by one "cgordon" |
That's when I was a neophyte and a philistine. |
... and so much younger...
glad to hear that.
___
P.S. nothing better than a little provocation to liven things up once in a while |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Dec 15, 2007 10:17 pm Post subject: |
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cgordon wrote: | Quote: | The last time anybody posted in this forum about a NOT vh puzzle was on Oct 30 by one "cgordon" |
That's when I was a neophyte and a philistine. |
From neophyte and philistine to sophisticate in a mere 45 days redefines the term "warp speed." |
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mckeann
Joined: 29 Nov 2007 Posts: 4
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Posted: Sat Dec 15, 2007 11:43 pm Post subject: |
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All the explanations make sense, but i'm damned if i can spot the pattern without a clue from here |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Dec 16, 2007 12:56 am Post subject: |
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mckeann wrote: | All the explanations make sense, but i'm damned if i can spot the pattern without a clue from here |
Neil,
There are multiple techniques discussed here. Is there one in particular for which you're having difficulty spotting the pattern? |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Sun Dec 16, 2007 12:58 am Post subject: |
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geez, if i would have read the forum first I would have not gone through two ur's and some coloring only to find out that it has one step.
so this puzzle had a one "major" step life expectancy.
been a few VH's that didn't have a very long life expectancy. |
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mckeann
Joined: 29 Nov 2007 Posts: 4
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Posted: Sun Dec 16, 2007 1:11 am Post subject: |
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Marty R. wrote: | mckeann wrote: | All the explanations make sense, but i'm damned if i can spot the pattern without a clue from here |
Neil,
There are multiple techniques discussed here. Is there one in particular for which you're having difficulty spotting the pattern? |
the pattern spotted by keith in the second post. I have all the same info, just cant seem to spot that they all line up. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Dec 16, 2007 4:52 am Post subject: |
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Quote: | the pattern spotted by keith in the second post. I have all the same info, just cant seem to spot that they all line up. |
He talked about a couple of things. I can talk about the XY-Wing. I assume you're familiar with them. It's the pivot 58 in r9c2 and the pincers in r3c2 and r9c7. These pincers take out only a 3 from r3c7. But if r9c7 is 3, then r7c8 must be 8 and r1c8 must be 3. That becomes a new pincer which, working with the original pincer in r3c2, takes out the 3 from r1c3 and that solves the puzzle. |
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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sun Dec 16, 2007 11:27 am Post subject: |
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Marty R. wrote: | These pincers take out only a 3 from r3c7. But ... |
Just for the record... Once 3 is gone from r3c7, r3c2=3 (single in r3), r1c3=5 (single) , r9c3=7 (single), and so on. No need for pincers.
I think what keith was getting at with his diagram ...
Quote: | the pattern spotted by keith in the second post. I have all the same info, just cant seem to spot that they all line up. |
... was the "extended xy-wing".
This is how they "line up":
if r1c3 (marked %) =5 then r3c2<>5.
if r1c3 <> 5 (but is 3), then (the chain marked @#@ is set in motion and) r1c8=8, r7c8=3, r9c7=8, and finally r9c2=5. This again makes r3c2<>5
Of course, in the end it makes no difference whether one takes out the 3 in r1c3 first or the 5 in r3c2, the puzzle is solved either way. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Dec 16, 2007 11:43 am Post subject: |
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mckeann,
Perhaps you are referring to Keith's "extended XY Wing," which is actually a particular instance of an XY Chain, that removes the two <5>s. It involves the following cells in sequence:
r1c3 - r1c8 - r7c8 - r9c7 - r9c2
And, it works in this way:
(1) If r1c3 is <5>, then r3c2 and r9c3 cannot be <5>. (And we have no idea what r9c2 is.)
(2) If r1c3 is NOT <5>, then it is <3> and r1c8 is <8> and r7c8 is <3> and r9c7 is <8> and r9c2 is <5>... and r3c2 and r9c3 cannot be <5>.
So, since either (1) or (2) must be true, then one or both of r1c3 and r9c2 must be <5> and r3c2 and r9c3 can never be <5>.
A similar XY Wing would have a {35} - {38} - {58} structure. Because two more {38} cells occur in the middle, Keith called it an "extended" XY Wing.
[Edit: nataraj's post wasn't there when I started this. Well, two heads are better than one!] |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun Dec 16, 2007 12:35 pm Post subject: |
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I think Neil is complaining that he sees the cells, but does not recognize the pattern.
Any time you have three cells with the same pair of candidates that form two strong links, you should look for opportunities. The chain fragment is
XY=XY=XY
and, in the solution, each end has the same value, X or Y.
In this case, Marty and I used it to extend an XY-wing. The regular XY-wing is
XZ-XY-YZ
with pincers Z. (Any cell that sees both ends cannot be Z.) The extended wing is
XZ-XY=XY=XY-YZ
and has the same pincers, Z.
You can also possibly extend the end of an XY-wing:
XZ-XY-YZ=YZ=YZ
Another possibility is a step in Medusa coloring. Is there a strong link in either X or Y on one end? For example,
X=XY=XY=XY
is a chain that has X as pincers.
[Edit: Actually, this last one is simple coloring on X. The Medusa chain is
X=XY=Y=XY
and has X as pincers.]
Keith
Last edited by keith on Sun Dec 16, 2007 5:41 pm; edited 1 time in total |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Dec 16, 2007 4:51 pm Post subject: |
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Quote: | Just for the record... Once 3 is gone from r3c7, r3c2=3 (single in r3), r1c3=5 (single) , r9c3=7 (single), and so on. No need for pincers. |
Clearly, I missed that. But it's fun to do pincer coloring since it's relatively new to me. |
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