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rfv6782
Joined: 22 Jan 2008
Posts: 2
Location: Greenville, SC
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 Posted: Tue Jan 22, 2008 5:16 pm Post subject: VH jan. 10, 2007 |
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Im new to this site and am practicing on the VH's.
can someone help with Jan 10 2007
| Code: |
+----------+-----------+-------------+
| 1 39 7 | 5 2 6 | 34 49 8 |
| 8 23 4 | 13 7 9 | 6 5 123 |
| 6 239 5 | 4 8 13 | 23 19 7 |
+----------+-----------+-------------+
| 4 5 3 | 19 6 2 | 7 8 19 |
| 79 8 1 | 39 45 357 | 234 6 239 |
| 79 6 2 | 8 14 37 | 5 14 39 |
+----------+-----------+-------------+
| 5 4 9 | 2 3 8 | 1 7 6 |
| 2 1 6 | 7 9 4 | 8 3 5 |
| 3 7 8 | 6 15 15 | 9 2 4 |
+----------+-----------+-------------+
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now what? |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Tue Jan 22, 2008 6:15 pm Post subject: |
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| Welcome to the forum. There is an XY-Wing pivoted in r5c4. Don't hesitate to ask more questions if needed. |
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rfv6782
Joined: 22 Jan 2008
Posts: 2
Location: Greenville, SC
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| Posted: Tue Jan 22, 2008 6:22 pm Post subject: |
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(79), (39)pivot ,(73) ?
taking out the 7 in r6c1? is that it....man ...i cant believe i missed it ....i looked so hard.
thanks alot. I just finished a VH from Nov. 07 and solved it with an XY wing. Cant believe i missed this one. |
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Asellus
Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA
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| Posted: Wed Jan 23, 2008 3:18 am Post subject: |
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Robert,
The {37}r6c6 - {39}r5c4 - {79}r5c1 XY-Wing also removes <7> from r5c6.
It's good to remember to check all of the common peers ("buddies") of the pincers when looking for eliminations. Sometimes it makes a key difference to the result. |
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George Woods
Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK
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| Posted: Wed Jan 23, 2008 9:06 am Post subject: W Wing and XY wing give sameish answer |
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| In the grid given at the start of this thread, there is a solution from an XY wing that removes the 7 from r6c1. The same conclusion (virtually) can be reached via a W-Wing - the 39s in boxes 5 and 6 operating on row 4 deny a 3 to r6c6 and hence deny the 7 to r6c1 (the W wing works thus. Both of 39s cannot be 9 since that would deny a 9 in row 4. Therefore one of them must be 3 and since r6c6 can see both of the 39s it cannot be 3!) |
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