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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Jul 29, 2006 12:29 pm Post subject: DB Saturday Puzzle - July 29, 2006 |
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More difficult than usual?
Code: | Puzzle: DB072906 ******
+-------+-------+-------+
| . 9 . | 5 3 . | 4 . 8 |
| . . . | . . . | . 9 1 |
| . . 5 | . . 6 | . . 3 |
+-------+-------+-------+
| . . . | 9 . . | . 1 7 |
| . . . | . . . | . . . |
| 6 1 . | . . 8 | . . . |
+-------+-------+-------+
| 5 . . | 7 . . | 9 . . |
| 3 8 . | . . . | . . . |
| 9 . 1 | . 2 3 | . 8 . |
+-------+-------+-------+ |
Keith |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Jul 29, 2006 1:36 pm Post subject: My solution |
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I get it to here:
Code: | +----------------+----------------+----------------+
| 1 9 27a | 5 3 27b | 4 6 8 |
| 27b 36 36 | 8 47 247 | 5 9 1 |
| 8 4 5 | 1 9 6 | 27 27 3 |
+----------------+----------------+----------------+
| 24 235 238 | 9 6 45 | 238 1 7 |
| 247a 2357 89 | 23 1 457c | 68 24 69 |
| 6 1 79 | 23 47 8 | 23 5 49 |
+----------------+----------------+----------------+
| 5 26 246 | 7 8 1 | 9 3 246 |
| 3 8 247 | 6 5 9 | 1 47 24 |
| 9 67 1 | 4 2 3 | 67 8 5 |
+----------------+----------------+----------------+ |
Note the hidden triple <689> in R5.
There is an interesting UR in R78C39. R8C9 cannot be <4>, it must be <2>, but this does not solve the puzzle.
Coloring on <7> (either "a" or "b" is <7>) eliminates <7> from R5C6 ("c") and the puzzle is solved.
Keith |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Jul 29, 2006 4:00 pm Post subject: |
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Quote: | Note the hidden triple <689> in R5. |
Keith, just to clarify terminology: when I was learning the most basic stuff, this would have been a naked triple, or just plain triple. I thought hidden meant it had to be somewhat disguised by having other candidates in one or more of the cells. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Jul 29, 2006 5:17 pm Post subject: Re: My solution |
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keith wrote: | I get it to here:
Code: | +----------------+----------------+----------------+
| 1 9 27a | 5 3 27b | 4 6 8 |
| 27b 36 36 | 8 47 247 | 5 9 1 |
| 8 4 5 | 1 9 6 | 27 27 3 |
+----------------+----------------+----------------+
| 24 235 238 | 9 6 45 | 238 1 7 |
| 247a 2357 89 | 23 1 457c | 68 24 69 |
| 6 1 79 | 23 47 8 | 23 5 49 |
+----------------+----------------+----------------+
| 5 26 246 | 7 8 1 | 9 3 246 |
| 3 8 247 | 6 5 9 | 1 47 24 |
| 9 67 1 | 4 2 3 | 67 8 5 |
+----------------+----------------+----------------+ |
Note the hidden triple <689> in R5.
There is an interesting UR in R78C39. R8C9 cannot be <4>, it must be <2>, but this does not solve the puzzle.
Coloring on <7> (either "a" or "b" is <7>) eliminates <7> from R5C6 ("c") and the puzzle is solved.
Keith |
I must've reached a similar, if not the same, position as you did Keith. I noticed that rectangle but didn't try anything with it because I was looking for other options first.
Now I have a very interesting observation. There is a strong link on "7" in cols. 1 and 6 ( what you might call a "fork"); I used that to eliminate the "7" from r2c5 (either r1c6 or r6c5 must be "7") and that broke the puzzle wide open.
So we each solved the puzzle by eliminating a "7" from c5, but from two different cells. Therefore, one of us has made an error or else this puzzle does not have a unique solution. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Jul 29, 2006 5:34 pm Post subject: Unhidden triple |
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Marty,
One step back from what I posted, the situation is:
Code: | +----------------------+----------------------+----------------------+
| 1 9 27 | 5 3 27 | 4 6 8 |
| 27 36 36 | 8 47 247 | 5 9 1 |
| 8 4 5 | 1 9 6 | 27 27 3 |
+----------------------+----------------------+----------------------+
| 24 235 2348 | 9 6 45 | 238 1 7 |
| 247 2357 234789 | 23 1 457 | 2368 24 2469 |
| 6 1 479 | 23 47 8 | 23 5 49 |
+----------------------+----------------------+----------------------+
| 5 26 246 | 7 8 1 | 9 3 246 |
| 3 8 247 | 6 5 9 | 1 247 24 |
| 9 67 1 | 4 2 3 | 67 8 5 |
+----------------------+----------------------+----------------------+ |
The triple is hidden. I "unhid" it. It is quite difficult to spot, I think. The corresponding naked set in R5 is <23457>.
There is a UR on <23> in R56C47 which will help to partly reveal the triple.
Keith |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Jul 29, 2006 5:51 pm Post subject: The fork that I see |
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Marty,
The fork that I see is in C1 (ab) and C5 (cd):
Code: | +----------------+----------------+----------------+
| 1 9 27g | 5 3 27h | 4 6 8 |
| 27a 36 36 | 8 47c 247 | 5 9 1 |
| 8 4 5 | 1 9 6 | 27 27 3 |
+----------------+----------------+----------------+
| 24 235 238 | 9 6 45 | 238 1 7 |
| 247b 2357 89 | 23 1 457f | 68 24 69 |
| 6 1 79e | 23 47d 8 | 23 5 49 |
+----------------+----------------+----------------+
| 5 26 246 | 7 8 1 | 9 3 246 |
| 3 8 247 | 6 5 9 | 1 47 24 |
| 9 67 1 | 4 2 3 | 67 8 5 |
+----------------+----------------+----------------+ |
One of b or d must be <7>; You can eliminate <7> from cells e and f. The last one is the same elimination I made with coloring.
edit: Now I see the other fork in R1 (gh) and R5 (ed). One of h or d must be <7>; You can eliminate <7> from cells f and c.
Keith |
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David Bryant
Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado
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Posted: Sat Jul 29, 2006 6:01 pm Post subject: Rows or columns? |
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Marty R wrote: | ... one of us has made an error or else this puzzle does not have a unique solution. |
I don't see a "fork" in columns 1 and 6, Marty ... I see it in rows 1 & 6, instead. I think that might be a typo.
There's no conflict between your method and Keith's -- you eliminated "7" from r2c5, meaning that r2c5 = 4, and Keith eliminated a "7" from r5c6, leaving the {4, 5} pair in r45c6, and eliminating "4" from r2c6 (leaving r2c5 = 4, unique horizontal). Maybe we're all getting cross-eyed from staring at these things too long!
Oh -- I hit on the same basic structure, but I noticed the "fork" between row 1 and column 5 ({2, 7} pair in row 1 -- {4, 7} pair in column 5). That allows one to eliminate "7" from r6c3, and r6c3 = 9 also solves this puzzle. dcb |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Jul 29, 2006 6:28 pm Post subject: |
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Quote: | The triple is hidden. I "unhid" it. It is quite difficult to spot, I think. The corresponding naked set in R5 is <23457>.
There is a UR on <23> in R56C47 which will help to partly reveal the triple. |
I did the same thing as you did Keith. It's just a difference what we call things. Rather than a hidden triple (which would be near-impossible for me to spot), I spotted the naked set which I would call a "quint", and that exposed the triple.
I also used that 23 rectangle, which I forgot to mention in my original post.
Quote: | I don't see a "fork" in columns 1 and 6, Marty ... I see it in rows 1 & 6, instead. I think that might be a typo.
There's no conflict between your method and Keith's -- you eliminated "7" from r2c5, meaning that r2c5 = 4, and Keith eliminated a "7" from r5c6, |
Yes David, a typo. The fork is in rows, not columns.
As to no conflict between Keith's method and mine, again correct. Maybe I'm getting dyslexic in my dotage, as I saw his elimination of the "7" from r5c6 and I was thinking r6c5.
Sorry to start all this confusion and cause all the wasted keystrokes. |
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