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Assistance Needed

 
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PostPosted: Fri Sep 16, 2005 12:59 pm    Post subject: Assistance Needed Reply with quote
Can anyone help with the following?

14x x97 2x8
xxx x2x 4x1
xxx 514 x7x

62x x7x xxx
518 239 746
xxx xxx x12

x9x x63 xxx
xx7 9xx xxx
4x1 x52 x9x

I tried the draw program which gave a hint of 5 in r7c3 but I don't understand it!!
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chobans



Joined: 21 Aug 2005
Posts: 39
PostPosted: Fri Sep 16, 2005 4:26 pm    Post subject: Reply with quote
In box 3 (r1c7-r3c9), 5 can ONLY go in column 8. So you can eliminate 5 in the other cells in column 8. This makes r7c8 possibilities to just 2 and 8.

r7c1 is also 2 or 8. So this creates a pair in row 7. So you can eliminate 2 and 8 in other cells in row 7. So, eventhough r7c3 CAN Be 2 or 5, you can eliminate 2 and get a 5 in that cell.
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