View previous topic :: View next topic |
Author |
Message |
Johan
Joined: 25 Jun 2007 Posts: 206 Location: Bornem Belgium
|
Posted: Mon Jul 16, 2007 10:26 pm Post subject: XY-CHAIN VH 16 JULY |
|
|
After using X-wing on 7, I think i found an XY-chain length 8.
Starting with [4] in R7C7(1) = [9] in R7C4(2) = [1] in R7C1(3) = [7] in R1C1(4) = [1] in R1C7(5) = [6] in R3C7(6) = [7] in R3C9(7) = [2] in R6C9(8, chain end).
This means I think that 2 can only exist in R7C7 or in R6C9, which eliminates the 2's in R6C7,R4C7 and R9C9, because both cells [R7C7,R6C9] can see the other 2's in R6C7,R4C7, and R9C9. Therefore R9C9 is left with a single 6.
Can anyone confirm this please, because i'm not certain of the chain end.
The chain can also ends in R9C9.
Length 8 [24] [49] [91] [17] [71] [16] [67] [72]
Length 9 [24] [49] [91] [17] [71] [16] [67] [72] [26] |
|
Back to top |
|
|
Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
|
Posted: Tue Jul 17, 2007 12:14 am Post subject: |
|
|
Johan,
Your length 8 chain is correct and solves the puzzle completely.
The length 9 chain is of no use that I can see.
On the other thread for this puzzle, there is length 6 XY chain that eliminates <1> in R1C1 and also solves the puzzle, as an alternative to your chain. Quite a day for XY chains, it seems. |
|
Back to top |
|
|
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum
|
Powered by phpBB © 2001, 2005 phpBB Group
|