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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sun Oct 21, 2007 8:39 am Post subject: Oct 21 "vh" - medium at best |
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no difficulties at all.
only very basic steps, easy to see, not even box/line interactions.
wrong rating or wrong puzzle. |
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nataraj
Joined: 03 Aug 2007 Posts: 1048 Location: near Vienna, Austria
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Posted: Sun Oct 21, 2007 8:53 am Post subject: |
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To give us all something to do while the next true vh is being prepared, I suggest this puzzle from sudocue.net (Sept 25):
http://www.sudocue.net/olddaily.php?id=652&sol=0
After basic steps, this is where "vh" comes in:
Code: |
+--------------------------+--------------------------+--------------------------+
| 135 2 67 | 178 1378 9 | 4 1367 58 |
| 1345 15 47 | 2 6 1348 | 58 137 9 |
| 8 169 4679 | 147 137 5 | 2 1367 167 |
+--------------------------+--------------------------+--------------------------+
| 7 1689 5 | 189 12389 12368 | 689 4 268 |
| 129 3 2689 | 1789 4 1268 | 689 5 2678 |
| 29 4 2689 | 5 2789 268 | 1 267 3 |
+--------------------------+--------------------------+--------------------------+
| 259 589 3 | 6 1289 128 | 7 129 4 |
| 6 89 2489 | 1489 5 7 | 3 129 12 |
| 249 7 1 | 3 29 24 | 56 8 56 |
+--------------------------+--------------------------+--------------------------+
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Expect coloring and xy-wing but nothing too heavy.
Enjoy! |
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cgordon
Joined: 04 May 2007 Posts: 769 Location: ontario, canada
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Posted: Sun Oct 21, 2007 9:01 pm Post subject: |
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I thought I'd screwed up because I finished this without doing any clever stuff. But then I did it again - same result. Please- some one tell me I doubly screwed up - and that this is really a VH. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Oct 21, 2007 9:08 pm Post subject: |
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I must've missed something and did it the hard way; I used an XY-Wing and a Type 1 rectangle. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Oct 21, 2007 9:21 pm Post subject: |
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I didn't use any coloring, but it took me 6 steps. No doubt someone can find a shorter route:
X Wing in R38 removes <4> from R2C3
Finned X Wing in R16 removes <7> from R3C5
{13} W Wing in R23 removes <3> from R2C6 & R3C8
XY Wing w/ pivot R2C2 removes <3> from R1C8
X Wing in R35 removes <7> from R1C4
XYZ Wing w/ pivot R7C1 removes <9> from R9C1 |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun Oct 21, 2007 9:23 pm Post subject: |
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This is the starting position.
Code: | +----------------------+----------------------+----------------------+
| 1 36 5 | 4 8 379 | 239 239 239 |
| 38 34 348 | 1359 2 1359 | 7 6 1349 |
| 2368 7 9 | 1356 156 135 | 23458 2345 1234 |
+----------------------+----------------------+----------------------+
| 36789 369 3678 | 2 467 3479 | 349 1 5 |
| 35679 2 367 | 135679 14567 134579 | 349 8 34679 |
| 4 1 367 | 35679 567 8 | 239 239 23679 |
+----------------------+----------------------+----------------------+
| 2359 3459 234 | 158 145 1245 | 6 7 2349 |
| 23567 8 1 | 57 9 2457 | 2345 2345 234 |
| 2579 459 247 | 57 3 6 | 1 2459 8 |
+----------------------+----------------------+----------------------+
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The solution does not require any "advanced" moves. You only have to find the pairs, triples, and/or intersections in B456.
Keith |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Oct 21, 2007 9:39 pm Post subject: |
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I should clarify...
My post was responding to nataraj's alternate puzzle, not to the Oct 12 VH. |
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sheryl
Joined: 24 Sep 2007 Posts: 64 Location: New York
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Posted: Sun Oct 21, 2007 10:59 pm Post subject: i think its hard |
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can anyone who thought this puzzle was easy, explain to me how to go the next step in elimination without actually using trial and error. here's where i am now. i would greatly appreciate the help. thanks.
+------------+-----------------+----------------+
| 1 6 5 | 4 8 7 | 9 3 2 |
| 38 34 348 | 9 2 5 | 7 6 1 |
| 2 7 9 | 136 16 13 | 8 5 4 |
+------------+-----------------+----------------+
| 78 39 678 | 2 67 349 | 349 1 5 |
| 5 2 367 | 136 1467 1349 | 349 8 3679 |
| 4 1 367 | 36 5 8 | 239 239 23678 |
+------------+-----------------+----------------+
| 39 5 234 | 8 14 124 | 6 7 139 |
| 6 8 1 | 7 9 2 | 5 4 3 |
| 79 49 247 | 5 3 6 | 1 249 8 |
+------------+-----------------+----------------+ |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Oct 21, 2007 11:40 pm Post subject: Re: i think its hard |
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Sheryl, a next step could be an XY-Wing of 49-39-34, with the Wing being pivoted in r9c2.
Code: | +------------+-----------------+----------------+
| 1 6 5 | 4 8 7 | 9 3 2 |
| 38 34 348 | 9 2 5 | 7 6 1 |
| 2 7 9 | 136 16 13 | 8 5 4 |
+------------+-----------------+----------------+
| 78 39 678 | 2 67 349 | 349 1 5 |
| 5 2 367 | 136 1467 1349 | 349 8 3679 |
| 4 1 367 | 36 5 8 | 239 239 23678 |
+------------+-----------------+----------------+
| 39 5 234 | 8 14 124 | 6 7 139 |
| 6 8 1 | 7 9 2 | 5 4 3 |
| 79 49 247 | 5 3 6 | 1 249 8 |
+------------+-----------------+----------------+ |
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sheryl
Joined: 24 Sep 2007 Posts: 64 Location: New York
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Posted: Sun Oct 21, 2007 11:57 pm Post subject: oct. 21 vh? |
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Marty, isn't this still guessing. one still has to say, if the 49 is a 9 then the 39 is a 3 and the 34 is a 4 but in reality the 49 is 4 and the 39 is a 9 and the 34 is a 3 so you still have to go thru all the machinations to find the answer and if you pick the wrong "pivot" then you end up in a hole and have to repeat that. what i want to understand is how you elimate the possibilies, how do you Pivot the 49 into a 4 and not the 9. |
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kragzy
Joined: 01 May 2007 Posts: 112 Location: Australia
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Posted: Mon Oct 22, 2007 12:30 am Post subject: |
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I'm with nataraj and cgordon on this one. I've done the puzzle twice - both times with easy straightforward moves - 12 minutes first time, 11 minutes for the second. I deliberately tried to attack the puzzle from a different direction the second time.
I'm not trying to be smart because there are many people on this forum who live in a Sudoku world way above mine, but I am puzzled as to how this puzzle could develop into a VH.
Cheers |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Mon Oct 22, 2007 12:37 am Post subject: |
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Sheryl,
Let's make certain you are viewing the XY Wing correctly:
Code: | +-------------+-----------------+----------------+
| 1 6 5 | 4 8 7 | 9 3 2 |
|#38 p34 348 | 9 2 5 | 7 6 1 |
| 2 7 9 | 136 16 13 | 8 5 4 |
+-------------+-----------------+----------------+
| 78 39 678 | 2 67 349 | 349 1 5 |
| 5 2 367 | 136 1467 1349 | 349 8 3679 |
| 4 1 367 | 36 5 8 | 239 239 23678 |
+-------------+-----------------+----------------+
|p39 5 234 | 8 14 124 | 6 7 139 |
| 6 8 1 | 7 9 2 | 5 4 3 |
| 79 v49 247 | 5 3 6 | 1 249 8 |
+-------------+-----------------+----------------+ |
The pivot is marked "v". The two pincers are marked "p". The victim is marked #.
If the pivot is <4>, the pincer in Row 2 is <3>. Alternately, if the pivot is <9>, the pincer in Row 7 is <3>. Since one of these two alternatives must be true, the victim cell cannot contain <3>.
This isn't guesswork because it's a well-established pattern that has a clear logic. As sudoku techniques go, it is one of the easier to spot and apply. It might help to read this:
http://www.sudocue.net/guide.php#XYWing |
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kragzy
Joined: 01 May 2007 Posts: 112 Location: Australia
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Posted: Mon Oct 22, 2007 12:44 am Post subject: |
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I appreciate you're just trying to help Sheryl on XY wings, but if this is the point where others have started to use advance techniques in this puzzle, my question is Why? There is only one 9 in Box 4. The puzzle falls apart from this point. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Mon Oct 22, 2007 12:45 am Post subject: |
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Sheryl,
Your grid has lots of candidates that can be removed. For example, look at <2> in Box 8, or at <3> and <8> in Column 9, or <4> in Box 9. It is important to be careful about removing candidates from "buddie" cells when you solve a cell. I suspect you'll find that that XY Wing isn't even required. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Oct 22, 2007 1:49 am Post subject: Re: i think its hard |
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sheryl wrote: | can anyone who thought this puzzle was easy, explain to me how to go the next step in elimination without actually using trial and error. here's where i am now. i would greatly appreciate the help. thanks.
+------------+-----------------+----------------+
| 1 6 5 | 4 8 7 | 9 3 2 |
| 38 34 348 | 9 2 5 | 7 6 1 |
| 2 7 9 | 136 16 13 | 8 5 4 |
+------------+-----------------+----------------+
| 78 39 678 | 2 67 349 | 349 1 5 |
| 5 2 367 | 136 1467 1349 | 349 8 3679 |
| 4 1 367 | 36 5 8 | 239 239 23678 |
+------------+-----------------+----------------+
| 39 5 234 | 8 14 124 | 6 7 139 |
| 6 8 1 | 7 9 2 | 5 4 3 |
| 79 49 247 | 5 3 6 | 1 249 8 |
+------------+-----------------+----------------+ |
Sheryl:
R6C9 is the only cell in row 6 that can be <8>.
R7C6 is the only cell in column 6 that can be <2>.
R6C7 is the only cell in column 7 that can be <2>.
R6C8 is the only cell in column 8 that can be <3>.
R9C8 is the only cell in column 8 that can be <4>.
R7C9 is the only cell in column 9 that can be <1>.
R4C2 is the only cell in block 4 that can be <9>.
Keith |
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kragzy
Joined: 01 May 2007 Posts: 112 Location: Australia
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Posted: Mon Oct 22, 2007 3:05 am Post subject: |
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Keith,
wrong
wrong
right
wrong
wrong
wrong
right
Check the cells that re already solved.
Cheers |
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duffy
Joined: 13 Sep 2007 Posts: 26 Location: Toronto Canada
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Posted: Mon Oct 22, 2007 3:07 am Post subject: |
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Keith,
I hope Sheryl doesn't get a headache from your statements that are true if you ignore all the singles, but otherwise are mostly not true! But I think your point must be that her grid (which is the same as the easier-to-read one posted by Marty) does allow for these statements on the basis of inspecting the unresolved candidates only.
Sheryl,
My suggestion would be to clean up the extra candidates based on the singles and note the 34 locked pair in r4, as a next step. And maybe an aspirin!
Don D. |
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duffy
Joined: 13 Sep 2007 Posts: 26 Location: Toronto Canada
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Posted: Mon Oct 22, 2007 3:16 am Post subject: |
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Sheryl,
Considering Marty's suggestion and your response, I think you don't have a handle on xy-wings yet. The wing he noted eliminates the 3 in r2c1. Maybe think of that 3's effect if it were true: it would make r2c2 a 4, and make r7c1 a 9: these would then leave r9c2 with no remaining candidate.
Don D. |
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sheryl
Joined: 24 Sep 2007 Posts: 64 Location: New York
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Posted: Mon Oct 22, 2007 3:23 am Post subject: |
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well, everyone, thanks for trying. here's where i am...
keith, i think you have the wrong day's puzzle. i say this because of your first statement which says that r6c9 is the only cell that can be an 8. in fact 8 is given in that box in r5 c8.
kragzy and asellus, i see your points. i did not notice the 9 in box 4 nor the 2 in box 9 so i have to be much more careful in the future. that probably would have helped alot. also, asellus, your explanation of the xy wing was very helpful as in fact i did not have the xy wing correct. and now i see how that deduction was made.
the only thing i now question is how does one figure out the xy wings. what is it i am to look for. i have read several pages on xy wings and it is quite confusing to me on how to identify them in an actual puzzle so any tips would be most welcome
duffy, i am going to take your suggestion and clean up the 'candidates' and see how that plays out. then i will take the aspirin.
i might be back again tomorrow with more questions. i hope you folks don't mind because this has been extremely helpful to me. i am determined to 'get to the bottom' of solving the VH sudokus.
thanks again!!! |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Oct 22, 2007 3:31 am Post subject: |
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(revised Oct 23, 2007)
My solver was thrown off by having incorrect candidates in the unsolved cells.
Here are the correct candidates:
Code: | +----------------+----------------+----------------+
| 1 6 5 | 4 8 7 | 9 3 2 |
| 38 34 348 | 9 2 5 | 7 6 1 |
| 2 7 9 | 136 16 13 | 8 5 4 |
+----------------+----------------+----------------+
| 3789 39 3678 | 2 467 349 | 34 1 5 |
| 5 2 367 | 136 1467 1349 | 34 8 679 |
| 4 1 367 | 36 5 8 | 23 29 679 |
+----------------+----------------+----------------+
| 39 5 234 | 8 14 14 | 6 7 9 |
| 6 8 1 | 7 9 2 | 5 4 3 |
| 79 49 247 | 5 3 6 | 1 29 8 |
+----------------+----------------+----------------+ |
R7C9 must be <9>.
R7C3 is the only square in row 7 that can be <2>.
R6C7 is the only square in column 7 that can be <2>.
R9C8 is the only square in block 9 that can be <2>.
Keith
Last edited by keith on Wed Oct 24, 2007 9:25 am; edited 2 times in total |
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