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Guest · Posted: Mon Dec 19, 2005 12:48 pm Post subject: Wd 14-Dec-2005

Am completly stumped......HELP

-7-9-2-4-
6-23--9--
---1--5--
----15364
-654-37--
1347--2--
--6--9---
---6-14-9
-8-5-4-2-

David Bryant · Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado

You can place several instances of the value "1" in this puzzle fairly easily.

Look at row two. The only possible values at r2c6 are {7, 8}. The only possible values at r2c8 & r2c9 are {1, 7, 8}. So the values {1, 7, 8} occupy these three cells, leaving the pair {4, 5} in r2c2 & r2c5.

Armed with this knowledge you can see that the "1" in column 2 must appear at r7c2. You can also infer from the triplet {1, 7, 8} that the "1" in the top right 3x3 box must appear in row 2, meaning that the "1" in row 1 must appear at r1c3, and the "1" in column 7 must appear at r9c7.

It should be duck soup after that. dcb Smile