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Guest · Posted: Sun Jan 15, 2006 11:15 pm Post subject: Jan 3 - very hard

this is what i have...any help?

57? 39? 182
?3? ??? ?54
?8? 5?? 63?
??2 4?5 ??3
?5? ??3 2??
??3 629 5??
?25 ??? 39?
3?? 95? ?2?
?91 ?3? ?75

Thanks...

Steve R · Posted: Mon Jan 16, 2006 4:33 am Post subject: Jan 3 - very hard

Not an ideal puzzle for sticklers: I found a fair amount of scribbling round the edges helpful.

In the top left-hand box, column 1 is occupied by (12) so column 3 contains (469).
In the bottom right-hand box, column 9 contains (16).
Bearing this in mind, the only cells in row 5 which can admit 4 or 6 are in columns 1 and 8. As the 9 in that row is excluded from these two columns, it is forced into cell (5, 9). The rest is straightforward.

Steve

Guest · Posted: Mon Jan 16, 2006 12:07 pm Post subject:

Thanks very much...i missed that...