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tlanglet · Posted: Fri Apr 16, 2010 2:57 pm Post subject:

An "almost BBDBer".

Marty R. · Posted: Sat Apr 17, 2010 9:07 pm Post subject:

I used seven steps, all of them assorted wings except the last step, a Type 1 UR.

peterj · Joined: 26 Mar 2010 Posts: 974 Location: London, UK

I took Dannys hint ... three steps with a decisive xy-chain

Mogulmeister · Joined: 03 May 2007 Posts: 1151

Well this is one of the weirdest things I have come across since I have been doing this game and has taken a little time and is, I will admit, UGLY:

I was looking at various chains to see if there was a shorter solve path or a Dan style 1 step and I couldn't really find one quckly. So, I used as my starting point the number 2 as there are strong links everywhere for this number.

I looked at the strong link between 2s at r7c8 and r2c8.

1)If r7c8 is not 2 then r3c8 is 2

2)If r7c8 is 2 then r3c8 is {1,4,8}.

So I looked at what happens in each of these remaining cases:

Set to (248=1)r3c8-(1=5)r3c6-r3c1=r8c1-(5=2)r7c2-r7c8=(2)r3c8
Set to (128=4)r3c8-r3c7=r5c7-(4=15)r45c2-(5=2)r7c2-r7c8=(2)r3c8
Set to (124=8)r3c8-(8=15)r3c6-(5)r3c1=r8c1-(5=2)r7c2-r7c8=(2)r3c8

So perhaps I am going mad but r3c8 is 2 whatever you do and if so that solves the puzzle!
Shocked

storm_norm · Joined: 18 Oct 2007 Posts: 1741

Mogulmeister,

I plugged it all into xsudo and it works.

basically, you shown that with each candidate in r3c8 set to true, the 2 is true in r3c8 all four times.

or, you can view it as proving that the 1,4,8 don't belong in that cell.

Mogulmeister · Joined: 03 May 2007 Posts: 1151

Thanks Norm - I can now get out of this "special" waistcoat.

Mogulmeister · Joined: 03 May 2007 Posts: 1151

Danny,

Have you encountered this kind of thing before ?

tlanglet · Posted: Sun Apr 18, 2010 2:23 pm Post subject:

Mogulmeister, your move is fantastic Exclamation

Finding "non-standard/unique" steps is a special pleasure of playing Sudoku.

Great move..............

Ted

daj95376 · Joined: 23 Aug 2008 Posts: 3854