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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sun Apr 18, 2010 4:39 pm Post subject: Puzzle 10/04/18 (C) |
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Code: | +-----------------------+
| 2 . . | . . . | . 1 . |
| . . . | 3 . 5 | . . . |
| . . 4 | . 9 1 | . . . |
|-------+-------+-------|
| . 1 . | . . . | . . 3 |
| . . 5 | . 1 3 | . . 8 |
| . 9 3 | . 5 6 | 1 2 . |
|-------+-------+-------|
| . . . | . . 8 | 6 . 9 |
| 3 . . | . . 9 | . 8 . |
| . . . | 6 3 . | 7 . 5 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site
Hint wrote: | XYZ-Wing possible.
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Apr 18, 2010 9:39 pm Post subject: |
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I initially started this puzzle looking at URs.
UR47 in r78c25 forces r7c2=25 or r8c2=6
(2)r7c2 - r7c3 = r4c3 - (2=8)r4c5 - (8=6)r1c5 - (6=7)r1c9,
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(5)r7c2 - r1c2 = r1c7 - (5=7)r3c8,
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(6)r8c2 - (6=7)r2c2.
Thus r2c8<>7
Also, this UR47 has a strong link 4 in r8c25 that allows deletion of 7 in r7c2.
Now, look at the outside row implication of the UR53 r13c27.
Digit 3: None
Digit 5: r3c18
Thus to prevent the deadly pattern, one of r3c18 must be 5 so that r3c27<>5.
After all that fun but no results, I returned to standard VH steps.
Quote: | xy-wing 26-7 with vertex 26 in r2c5; r3x12<>7,
Another Kraken xyz-wing 678 in r2c3
(6)r2c3; r3c2<>6
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(7)r2c3 - (7=6)r2c2; r3c2<>6
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(8)r2c3 - r2c7 = (8-3)r3c7 = (3)r1c7 - r1c2 = (3)r3c2; r3c2<>6
Finally, a xy-wing 2-78 with vertex 28 in r4c5 completes the puzzle.
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I suspect the first three UR related deletions were not needed.
Ted |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Tue Apr 20, 2010 4:56 am Post subject: |
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W-Wing (67)
Type 4 UR (35), but better results were achieved by creating a pincer situation with the two DP killers
W-Wing (47) |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Tue Apr 20, 2010 4:59 am Post subject: |
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W-Wing (67)
Type 4 UR (35), but better results were achieved by creating a pincer situation with the two DP killers
W-Wing (47)
Quote: | UR47 in r78c25 forces r7c2=25 or r8c2=6
(2)r7c2 - r7c3 = r4c3 - (2=8)r4c5 - (8=6)r1c5 - (6=7)r1c9,
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(5)r7c2 - r1c2 = r1c7 - (5=7)r3c8,
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Ted, what does that symbol ll mean? |
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