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Korky
Joined: 29 Mar 2006
Posts: 13
Location: Sheffield, UK
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 Posted: Wed Apr 12, 2006 2:43 pm Post subject: DT 12th April |
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Can anyone help with this
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x58 xx4 x92
xx9 2x8 x45
x42 59x 183
xx7 452 x16
x24 xx1 x5x
5x1 x8x 42x
283 749 561
915 863 274
476 125 x3x |
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David Bryant
Joined: 29 Jul 2005
Posts: 559
Location: Denver, Colorado
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| Posted: Wed Apr 12, 2006 3:31 pm Post subject: This is a "fork" position. |
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Hi, Korky!
The short answer is that you can eliminate the possibility of a "6" at r3c1. Here's why.
-- There are only two places for a "6" in column 2, at r2c2 and r6c2.
-- There are only two places for a "6" in column 6, at r3c6 and r6c6.
-- If r2c2 = 6, then clearly r3c1 <> 6.
-- But if r2c2 <> 6, then r6c2 = 6, r6c6 <> 6, r3c6 = 6, and r3c1 <> 6.
I think that's enough to solve the puzzle. dcb |
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ravel
Guest
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| Posted: Wed Apr 12, 2006 3:58 pm Post subject: |
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| For doing it without a forcing chain this link might help you. The 2 strong links to eliminate 6 in r3c1 here are either r5c1-r6c2 and r6c6-r3c6 or (as David pointed out) r2c2-r6c2 and r6c6-r3c6 |
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Korky
Joined: 29 Mar 2006
Posts: 13
Location: Sheffield, UK
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| Posted: Wed Apr 12, 2006 6:37 pm Post subject: |
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Thanks guys. The "fork position" is a new one on me. I'll try to spot it myself next time.
Your help much appreciated. |
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