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Puzzle 10/05/20: (B) XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Thu May 20, 2010 5:01 am    Post subject: Puzzle 10/05/20: (B) XY Reply with quote

hint wrote:
As an alternative to an XY-Chain, my solver found 2x M-Wings -- one was superior to the other.

Code:
 +-----------------------+
 | . 5 2 | . . 6 | . 1 3 |
 | 7 . . | 9 3 . | 2 6 . |
 | 3 . . | . 4 . | . 9 . |
 |-------+-------+-------|
 | . 3 . | . . . | . . . |
 | . 6 9 | . 7 . | . . . |
 | 2 . . | . . 9 | 6 . . |
 |-------+-------+-------|
 | . 9 . | . . 4 | 3 . . |
 | 5 8 3 | . . . | . . 9 |
 | 4 . . | . . . | . 7 . |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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wapati



Joined: 10 Jun 2008
Posts: 472
Location: Brampton, Ontario, Canada.

PostPosted: Thu May 20, 2010 5:23 am    Post subject: Reply with quote

This is a VERY good one. No big fish, but the CHUM !!!
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Thu May 20, 2010 6:49 am    Post subject: Reply with quote

Quote:
A little discontinuous loop shows r4c1 must be 1 and solves the puzzle:

(1=8)r4c1-(8=1)r5c1-(1=4)r5c9-r5c4=(4-1)=(1)r4c1 ; Contradiction so r4c1 <> 8


Last edited by Mogulmeister on Fri May 21, 2010 9:33 pm; edited 1 time in total
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Fri May 21, 2010 1:39 pm    Post subject: Reply with quote

Several steps............

Type 1 UR26 in r48c45; r4c4<>26
x-wing 8 in r67c48; r459c4, r45c8<>8
ANP(25=8)r34c6 - (8=3)r6c4 - (3=5)r9c4# - r7c5 = (5)r6c5; #r9c6<>5 & r5c6<>5,
ANP(25=8)r4c68 - (8=3)r6c4 - (3=5)r9c4; r4c4<>5
xy-wing 14-5 with vertex 14 in r4c4; r6c3<>5

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Fri May 21, 2010 4:39 pm    Post subject: Reply with quote

It was a long slog, a BBDB.
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Luke451



Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California

PostPosted: Sat May 22, 2010 6:13 am    Post subject: Reply with quote

Mogulmeister wrote:
Quote:
A little discontinuous loop shows r4c1 must be 1 and solves the puzzle:

(1=8)r4c1-(8=1)r5c1-(1=4)r5c9-r5c4=(4-1)=(1)r4c1 ; Contradiction so r4c1 <> 8


That's clean, MM. Coulda trimmed the start, but no biggie.

Mainly, nice to see "discontinuous loop" rather than...well, something else, if you catch my drift.
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sat May 22, 2010 6:53 am    Post subject: Reply with quote

Ah Mullah Luke....

I see you may not have been reading your scriptures closely enough. We must not blaspheme the baphomet. Heretofore*, the baphomet has been single candidate only! Wink

*hitherto
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sat May 22, 2010 7:04 am    Post subject: Reply with quote

The lack of the trim was to highlight the contradiction by beginning and ending at the same cell.
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ronk



Joined: 07 May 2006
Posts: 398

PostPosted: Sat May 22, 2010 1:47 pm    Post subject: Reply with quote

Mogulmeister wrote:
The lack of the trim was to highlight the contradiction by beginning and ending at the same cell.

Nice find, but the AIC (1)r4c1 = ... = (1)r4c1 doesn't express a contradiction.
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Sat May 22, 2010 1:56 pm    Post subject: Reply with quote

ronk wrote:
But the AIC (1)r4c1 = ... = (1)r4c1 doesn't express a contradiction.

Hmmmm! Boy is my math rusty. I thought that assuming something was false ... and then showing that it must be true ... represented a contradiction on the original assumption. Similarly for a true assumption and a false conclusion. What is it called?
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ronk



Joined: 07 May 2006
Posts: 398

PostPosted: Sat May 22, 2010 2:21 pm    Post subject: Reply with quote

daj95376 wrote:
ronk wrote:
But the AIC (1)r4c1 = ... = (1)r4c1 doesn't express a contradiction.

Hmmmm! Boy is my math rusty. I thought that assuming something was false ... and then showing that it must be true ... represented a contradiction on the original assumption. Similarly for a true assumption and a false conclusion. What is it called?

My bad, Mogulmeister and you are correct, but I think the best expression is ...

(1=4)r5c9 - (4)r5c4 = (4-1)r4c4 = (1)r4c1 --> r5c1<>1

... which is an m-wing.
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sat May 22, 2010 2:49 pm    Post subject: Reply with quote

Thanks Ronk but I did want to show up the contradiction by starting and ending in the same place but in different truth states.

Something of an existential nightmare I agree, but whats a boy to do ? Wink
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ronk



Joined: 07 May 2006
Posts: 398

PostPosted: Sat May 22, 2010 3:16 pm    Post subject: Reply with quote

Mogulmeister wrote:
I did want to show up the contradiction by starting and ending in the same place but in different truth states.

Not a problem, add the weak links and get ...

(1)r5c1 - (1=4)r5c9 - (4)r5c4 = (4-1)r4c4 = (1)r4c1 - (1)r5c1 --> r5c1<>1

It still has only three strong links for the exclusion ... compared to your five for an inclusion.
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Sat May 22, 2010 3:21 pm    Post subject: Reply with quote

Thanks...I'll come quietly officer but if the logic works.......
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