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Puzzle 10/09/26: D XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Sun Sep 26, 2010 1:42 am    Post subject: Puzzle 10/09/26: D XY Reply with quote

I have several puzzles that appear to be difficult. This one seems to be the easiest.

Code:
 +-----------------------+
 | . 5 2 | . 7 . | 9 . 4 |
 | 8 9 4 | . 1 . | . . . |
 | 7 3 . | . . 4 | . . . |
 |-------+-------+-------|
 | . . . | 7 4 . | . . . |
 | 9 4 . | 3 . . | 1 . . |
 | . . 7 | . . 2 | . . . |
 |-------+-------+-------|
 | 4 . . | . 5 . | 6 . 9 |
 | . . . | . . . | . 4 . |
 | 3 . . | . . . | 5 . . |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Sun Sep 26, 2010 8:21 am    Post subject: Reply with quote

Two steps..
Quote:
skyscraper(8) ; r5c3<>8, r6c45<>8
s-wing(56) ; (6)r9c4=r9c6 - (6=5)r2c6 - (5)r5c6=r5c3 ; r5c3<>6
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JC Van Hay



Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium

PostPosted: Sun Sep 26, 2010 9:24 am    Post subject: Reply with quote

Quote:
4-SIS AIC : 5C3 9C3 (96)R9C6 (65)R2C6 : (5)r5c3=(5)r2c6 : => r5c6<>5
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Sun Sep 26, 2010 2:09 pm    Post subject: Reply with quote

Very interesting puzzle. It has a Type 1 UR(18)r39c89; two overlapping AURs, AUR(18)r78c34 and AUR(69)r89c36 that share cell r8c3; and finally a 12-cell BUG-Lite+8 (56). My first look at all of that "stuff" only resulted in the obvious Type 1 UR deletion, r3c8<>18, and a useless r8c6<> from the AUR(69). The BUG-Lite looks overwhelming to me but maybe someone else would like the challenge.

More later............

Ted
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Sun Sep 26, 2010 2:49 pm    Post subject: Reply with quote

Starting again from scratch, I was intrigued by all the 56s comprising the BUG-Lite and was looking for w-wings when I saw an AW-wing (56) in r2c6 & r5c3 with fin (8) in r5c3 and SL (6)r9c36. Chasing the fin, we get:
(8)r5c3-r78c3=r8c2-r8c6=r5c6; r5c3<>8 contradiction

Thus the w-wing is true; r5c6<>5

I just looked at the two previous posts and realized my solution is essentially the same.

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Mon Sep 27, 2010 10:45 pm    Post subject: Reply with quote

In honor of our friend from the NorCal foothills, I did an external analysis of the 69 UR in boxes 78. R8c4<>9 due to invalidity. The remaining killers forced r4c9=5 and r5c2=8.
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