| View previous topic :: View next topic |
| Author |
Message |
Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
|
 Posted: Mon Nov 08, 2010 10:51 pm Post subject: Nov 9 VH |
 |
|
Two steps:
XY-Wing 27 57 25 Pivoted in r1c6 removes 2 in r4c1 opens another
XY-Wing 14 16 46 Pivoted in r7c1 eliminating 4 in r4c9 solves it. |
|
| Back to top |
|
 |
peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
|
| Posted: Tue Nov 09, 2010 9:20 am Post subject: |
|
|
An m-wing(14) does it in one step...
| Code: | *-------------------------------------------------------------*
| 27 3 29 | 8 4 1 | 57 6 59 |
| 5 6 4 | 3 7 9 | 28 28 1 |
| 8 79 1 | 6 5 2 | 4 37 39 |
|---------------------+-------------------+-------------------|
| (1)2(4) 12 3 | 7 6 8 | 25 9 2(4)5 |
| 2467 79 2689 | 5 1 3 | 2678 2-478 2468 |
| 67 5 68 | 9 2 4 | 1 378 368 |
|---------------------+-------------------+-------------------|
| (1)6 8 7 | 2 3 5 | 9 (14) -46 |
| 9 12 5 | 4 8 6 | 3 12 7 |
| 3 4 26 | 1 9 7 | 268 5 268 |
*-------------------------------------------------------------*
m-wing(14) (4=1)r7c8 - r7c1=(1-4)r4c1=r4c9 ; r5c8<>4, r7c9<>4 |
|
|
| Back to top |
|
|
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Tue Nov 09, 2010 4:57 pm Post subject: |
|
|
| There's both a Finned X-Wing and Skyscraper on 7 but I didn't check if either completes the puzzle. Also a short AIC removing 7 from r5c2. |
|
| Back to top |
|
|
Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
|
| Posted: Tue Nov 09, 2010 5:52 pm Post subject: Nov 9 VH |
|
|
| Correction in my submission above: The pivot for XY-Wing 27 57 25 is in r1c7. |
|
| Back to top |
|
|
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Wed Nov 10, 2010 4:47 am Post subject: |
|
|
I found and "Almost" (or finned) xy-wing that made the same deletion as the m-wing posted by Peter.
AXY-wing 1-46 with vertex (16)r7c1, pincers (46)r5c1 & (14)r7c8 with fin (27)r5c1
If xy-wing is true then r5c8<>4
If fin is true then locked set(27)r15c1, then r6c1<>7=6, then r7c1<>6=1, then r7c8<>1=4; r5c8<>4
Ted |
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
