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Free Press May 20, 2011

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Fri May 20, 2011 9:37 am    Post subject: Free Press May 20, 2011 Reply with quote

Not yet done. Requites advanced moves.
Code:
Puzzle: FP052011
+-------+-------+-------+
| . . . | 9 . . | . . 1 |
| . 9 4 | . . 8 | . . 2 |
| 2 . . | 6 . . | . . 7 |
+-------+-------+-------+
| . 1 . | 2 . . | . 5 . |
| 6 . 2 | . . . | 8 . 3 |
| . 3 . | . . . | . 1 . |
+-------+-------+-------+
| 1 . . | . . 6 | . . 9 |
| 5 . . | 4 . . | 6 3 . |
| 9 . . | . . 7 | . . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Fri May 20, 2011 5:39 pm    Post subject: Reply with quote

A short (four-cell) XY-Chain did it for me; 4 in r7c2 proves 8 in r4c3; r79c3<>8.
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Fri May 20, 2011 7:09 pm    Post subject: Reply with quote

After basics:
Code:
+-------------------+-------------------+-------------------+
| 378   5678  568   | 9     3457  2     | 345   48    1     |
| 37    9     4     | 1357  1357  8     | 35    6     2     |
| 2     58    1     | 6     345   345   | 3459  489   7     |
+-------------------+-------------------+-------------------+
| 478   1     89    | 2     36789 39    | 79    5     46    |
| 6     57    2     | 157   14579 1459  | 8     79    3     |
| 478   3     589   | 578   56789 59    | 2     1     46    |
+-------------------+-------------------+-------------------+
| 1     48    38    | 358   2358  6     | 47    247   9     |
| 5     2     7     | 4     19    19    | 6     3     8     |
| 9     468   368   | 38    238   7     | 1     24    5     |
+-------------------+-------------------+-------------------+
Keith
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Fri May 20, 2011 8:02 pm    Post subject: Reply with quote

Code:
+-------------------+-------------------+-------------------+
| 378  567-8  568   | 9     3457  2     | 345   48@   1     |
| 37    9     4     | 1357  1357  8     | 35    6     2     |
| 2     58$   1     | 6     345   345   | 3459 -489$  7     |
+-------------------+-------------------+-------------------+
| 478   1     89    | 2     36789 39    | 79    5     46    |
| 6     57    2     | 157   14579 1459  | 8     79    3     |
| 478   3     589   | 578   56789 59    | 2     1     46    |
+-------------------+-------------------+-------------------+
| 1     48@   38    | 358   2358  6     | 47   2-47   9     |
| 5     2     7     | 4     19    19    | 6     3     8     |
| 9    46-8#  368   | 38    238   7     | 1     24#   5     |
+-------------------+-------------------+-------------------+

The 48 cells @ are connected by strong links 4# and 8$: They are a double W-wing, and a remote pair. Further, the two W-wings form a closed cycle, all links are strong, and we can make the eliminations shown.

Leading to another loop:
Code:
+-------------------+-------------------+-------------------+
| 378  -567   568   | 9     3457  2     | 345   48    1     |
| 37    9     4     | 1357  1357  8     | 35    6     2     |
| 2     58@   1     | 6     345   345   | 3459  89@   7     |
+-------------------+-------------------+-------------------+
| 478   1     89    | 2     36789 39    | 79    5     46    |
| 6     57@   2     |15-7  145-79 1459  | 8     79@   3     |
| 478   3     589   | 578   56789 59    | 2     1     46    |
+-------------------+-------------------+-------------------+
| 1     48    38    | 358   2358  6     | 47    27    9     |
| 5     2     7     | 4     19    19    | 6     3     8     |
| 9     46    368   | 38    238   7     | 1     24    5     |
+-------------------+-------------------+-------------------+
Interesting moves, they do not solve the puzzle.

An M-wing is a single-stepper: 8 In R4C3 forces 8 in R3C8. R4C3 and R5C8 are pincers on 9, solving R4C7 as 7.

Keith
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susume



Joined: 13 May 2011
Posts: 36
Location: Southeastern US

PostPosted: Sun May 22, 2011 7:51 pm    Post subject: Reply with quote

A different single step approach involving 4 cells:

Discontinuous nice loop
[r1c3]=6=[r1c2]=7=[r5c2]=5=[r6c3]-5-[r1c3] => r1c3<>5
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