| View previous topic :: View next topic |
| Author |
Message |
keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
|
 Posted: Fri Jun 17, 2011 1:30 pm Post subject: Free Press June 17, 2011 |
 |
|
Not yet started. Requires advanced moves.
| Code: | Puzzle: FP061711
+-------+-------+-------+
| . . . | 8 . 2 | 1 . . |
| . 2 . | . . . | . 5 . |
| . . . | 4 1 . | 2 . . |
+-------+-------+-------+
| 7 5 9 | . . . | . . 3 |
| . 3 . | . 4 . | . 8 . |
| 8 . . | . . . | 5 6 9 |
+-------+-------+-------+
| . . 5 | . 7 8 | . . . |
| . 6 . | . . . | . 3 . |
| . . 2 | . . 6 | . . . |
+-------+-------+-------+
|
Play this puzzle online at the Daily Sudoku site
Keith |
|
| Back to top |
|
 |
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Fri Jun 17, 2011 2:35 pm Post subject: |
|
|
A quick two stepper..............
| Quote: | Type 6 UR(79)r13c28; r1c8,r3c2<>9
Plus external sis r9c2=7,r9c8=7; r9c9<>7
kite (7) b9; r1c3<>7=3
|
A second pass uncovered a one step solution.
| Quote: | Hidden aur(47)r19c89 with x-wing (4); r1c9<>7
Plus external sis: (7)r9c2=(7)r8c3-aur(47)[(7)r8c9=(7)r3c89]; r3c2<>7
|
Ted
[Edited to add second solution.] |
|
| Back to top |
|
|
cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
|
| Posted: Fri Jun 17, 2011 6:46 pm Post subject: |
|
|
I used a Type 6 UR (79) and a Type 4 (47) and an ER on 7. Probably more than needed.
Don't know what a sis is short for. I assume it's not a sibling or a girlie guy. |
|
| Back to top |
|
|
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Sat Jun 18, 2011 1:20 am Post subject: |
|
|
What is there about certain puzzles that one makes consistent mechanical errors? And the frustrating thing is that I rarely get to find out what I did wrong. On this one I ended three times with an invalid solution. Thankfully, I got it on the 4th try or who knows how much more time I would've wasted.
Type 6 UR (79); r1c2, r3c8=9
Kite; r1c3<>7 |
|
| Back to top |
|
|
keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
|
| Posted: Sat Jun 18, 2011 3:45 am Post subject: |
|
|
Marty,
That was the solution I eventually found.
This one had a lot of naked / hidden pairs to get through basics.
Keith |
|
| Back to top |
|
|
dejsmith
Joined: 23 Oct 2005
Posts: 42
|
| Posted: Tue Jun 21, 2011 10:20 pm Post subject: BUG +5? |
|
|
I tried to do something a little different this time since I am pretty confident with URs. After basics & an XY Wing extension so that r8c5<>5; I noticed there were only 5 cells left that each had 3 candidates; i.e. the rest were all pairs. Based on my understanding of BUGs, either in Box 1 r3c23=7, or in Box 3 r1c89=7, or in Box 9 r9c9=7. Since they all see r3c9, then r3c9<>7; & the puzzle solves. Is that valid reasoning; & would that be called a BUG +5?
Dave |
|
| Back to top |
|
|
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Wed Jun 22, 2011 12:03 am Post subject: |
|
|
| I can't comment on the reasoning without seeing a grid. However, I do believe it would properly be called a BUG+5. That move is rather unusual, as most of the BUG moves don't go higher than BUG+3. |
|
| Back to top |
|
|
daj95376
Joined: 23 Aug 2008
Posts: 3854
|
| Posted: Wed Jun 22, 2011 12:21 am Post subject: Re: BUG +5? |
|
|
| dejsmith wrote: | I tried to do something a little different this time since I am pretty confident with URs. After basics & an XY Wing extension so that r8c5<>5; I noticed there were only 5 cells left that each had 3 candidates; i.e. the rest were all pairs. Based on my understanding of BUGs, either in Box 1 r3c23=7, or in Box 3 r1c89=7, or in Box 9 r9c9=7. Since they all see r3c9, then r3c9<>7; & the puzzle solves. Is that valid reasoning; & would that be called a BUG +5?
|
Your grid as I've reconstructed it. A BUG+5 using a single extra value. Impressive!
| Code: | *--------------------------------------------------*
| 56 79 37 | 8 35 2 | 1 49+7 46+7 |
| 4 2 1 | 79 6 79 | 3 5 8 |
| 56 89+7 38+7 | 4 1 35 | 2 79 6-7 |
|----------------+----------------+----------------|
| 7 5 9 | 6 8 1 | 4 2 3 |
| 2 3 6 | 59 4 59 | 7 8 1 |
| 8 1 4 | 27 23 37 | 5 6 9 |
|----------------+----------------+----------------|
| 9 4 5 | 3 7 8 | 6 1 2 |
| 1 6 78 | 25 29 4 | 89 3 57 |
| 3 78 2 | 1 59 6 | 89 47 45+7 |
*--------------------------------------------------*
|
It would also have worked as a BUG+6 if you hadn't performed r8c5<>5:
| Code: | (5)r8c5 - (5=7)r8c9 - (7)r3c9
|
Essentially, basics followed by a BUG+6.
Regards, Danny |
|
| Back to top |
|
|
susume
Joined: 13 May 2011
Posts: 36
Location: Southeastern US
|
| Posted: Wed Jun 22, 2011 3:25 am Post subject: |
|
|
Besides basics I needed an X-wing (9) r89c57 to get to daj's grid of mostly bivalues (with the 5 still in r8c5).
From there, those lovely bivalue cells can be used in a Nice Loop that solves it:
r1c9 -6- r1c1 -5- r1c5 -3- r1c3 -7- r8c3 =7= r8c9 -7- r3c9 -6- r1c9 => r1c9<>6, r3c9=6
It's essentially a W-wing of 7 in c39, using the bivalues in r1c15 to convert the r1c3 pincer to a 6. |
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
