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sarah Guest
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Posted: Tue Mar 28, 2006 4:15 am Post subject: March 8!!! |
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Very strange ... I often solve very hard puzzles, yet this "hard" puzzle has me so stumped I can't get more than 3 numbers filled in!!! I'm totally puzzled (no pun intended).
So far I have 8 in c1r5, 5 in c9r4 and 9 in c3r8. Draw gives a hint of 8 in c7r9, then 2 in c9r9. Those hints not only leave me clueless still, but I can't figure out why they make sense.
Any help?
Thanks!
Sarah |
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guest Guest
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Posted: Tue Mar 28, 2006 9:54 am Post subject: Re: March 8!!! |
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sarah wrote: | ... 5 in c9r4 ... |
I dont know how you found this.
Anyway, the key is the naked triplet in box3/column 8. |
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George woods Guest
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Posted: Tue Mar 28, 2006 11:58 am Post subject: solving it |
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e7b7e98i3h3f4 is how I started
abc
def
ghi
and e7 menas put a 7 into obvious square in block e |
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Guest
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Posted: Tue Mar 28, 2006 12:04 pm Post subject: |
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George,
i suppose you have another puzzle, i was talking about this one (where 7 is a given in block e)
Code: | ------------
.8.|1..|4..
1.7|...|..9
...|..6|1.3
------------
7..|..4|.6.
...|2.3|...
.9.|7..|..8
------------
2.8|5..|...
5..|...|7.1
..3|..9|.5.
------------
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george woods Guest
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Posted: Tue Mar 28, 2006 12:10 pm Post subject: |
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Ok I haven't checked it against original but my record is
f7d8i8g9i2f5c65
I have put an exclamation mark beside f7 implying something subtle! |
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george woods Guest
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Posted: Tue Mar 28, 2006 12:24 pm Post subject: march 8 |
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The subtelty arises from the pair 56 in Cc and Cg (because of the 5 and 6 in col 8 |
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george Guest
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Posted: Tue Mar 28, 2006 12:27 pm Post subject: |
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I mean of course Cc and Cd |
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Guest
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Posted: Tue Mar 28, 2006 1:38 pm Post subject: |
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Yep, now we are on the same line. The hidden pair 56 in box 3 (c) is the counterpart to the triplet i mentioned. |
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TKiel
Joined: 22 Feb 2006 Posts: 292 Location: Kalamazoo, MI
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Posted: Tue Mar 28, 2006 9:11 pm Post subject: |
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Sarah,
If you've made the exclusions from the naked triple in box 3, then the only possibility in box 9 for an 8 is r9c7, which then makes r9c9 the only possibility for a 2. |
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sarah Guest
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Posted: Thu Mar 30, 2006 7:20 pm Post subject: |
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Tracy- Thank you. Your response was the only one that made any sense to me. I do not know what a "naked triplet" is... although I do have the limitations of 27 for c8r1, 28 for c8r2, and 278 for c8r3. So I see how the 8 must therefore be in c7r9. But c9r9 can still be a 2 OR a 4, no?
And what is George going on about? All his letters and numbers are a mystery to me...
Sarah |
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sarah Guest
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Posted: Thu Mar 30, 2006 7:27 pm Post subject: |
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I take that back -- I see why c9r9 has to be a 2!
Thank you. |
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Guest
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Posted: Fri Mar 31, 2006 5:17 pm Post subject: |
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Glad to see a response finally, Sarah, sorry for the "t" in "naked triplet" (i am not English), which seemed to confuse you so, that
- you could not see the triple in the 3 cells i mentioned
- not the naked pair i mentioned
- and you were not able to ask what i meant with it
i will .ry .o avoid .he "t" in the fu.ure |
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