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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Oct 22, 2011 1:31 am Post subject: Free Press October 21, 2011 |
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Not yet done. Code: | Puzzle: FP102111
+-------+-------+-------+
| 7 5 . | . . . | . . . |
| 3 . . | . . 8 | . . 6 |
| 1 . . | 6 . . | . . . |
+-------+-------+-------+
| . . 3 | 7 . . | 8 . . |
| 6 . 2 | 8 . 4 | 9 . 3 |
| . . . | . . 9 | 1 . . |
+-------+-------+-------+
| . . . | . . 1 | . . 4 |
| 9 . . | 4 . . | 5 . 7 |
| . . . | . . . | . 3 8 |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
Keith |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Oct 22, 2011 4:06 am Post subject: |
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Nice puzzle!
I found two one-steppers. Look at 6 and 4.
Keith |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sat Oct 22, 2011 2:10 pm Post subject: |
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Another one stepper is
anp(23=6)r6c45-(6=9=5)r9c54-(5=3=2)r76c4; r4c6<>2
Ted |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Oct 22, 2011 3:35 pm Post subject: |
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After basics: Code: | +----------------+----------------+----------------+
| 7 5 6 | 239 2349 23 | 34 8 1 |
| 3 2 9 | 1 47 8 | 47 5 6 |
| 1 8 4 | 6 37 5 | 37 2 9 |
+----------------+----------------+----------------+
| 45 9 3 | 7 1 26 | 8 46 25 |
| 6 1 2 | 8 5 4 | 9 7 3 |
| 8 47 57 | 23 236 9 | 1 46 25 |
+----------------+----------------+----------------+
| 25 367 57 | 35 8 1 | 26 9 4 |
| 9 36 8 | 4 236 236 | 5 1 7 |
| 245 46 1 | 59 69 7 | 26 3 8 |
+----------------+----------------+----------------+ |
There is a W-wing 46. With transport, it takes out 6 in R9C5.
An M-wing based on 36 takes out 6 in R8C6.
Keith |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Oct 22, 2011 4:48 pm Post subject: |
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Quote: | There is a W-wing 46. With transport, it takes out 6 in R9C5. |
I played the same move. |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sat Oct 22, 2011 5:15 pm Post subject: |
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keith wrote: | I found two one-steppers. Look at 6 and 4.
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I thought your hint meant:
Code: | M-Wing 1A: (6=4)r9c2 - r6c2 = (4-6)r6c8 = (6)r6c5 => r9c5<>6
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But, after reading ...
keith wrote: | There is a W-wing 46. With transport, it takes out 6 in R9C5.
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I realized that you meant:
Code: | (6=4)r9c2 - r6c2 = r4c1 - (4=6)r4c8 - r4c6 = (6)r8c6 => r8c2,r9c5<>6
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Now, I wouldn't have even mentioned it, if it wasn't for the fact that I can't find:
keith wrote: | An M-wing based on 36 takes out 6 in R8C6.
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Oct 22, 2011 6:29 pm Post subject: |
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daj95376 wrote: |
Now, I wouldn't have even mentioned it, if it wasn't for the fact that I can't find:
keith wrote: | An M-wing based on 36 takes out 6 in R8C6.
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After basics: Code: | +----------------+----------------+----------------+
| 7 5 6 | 239 2349 23 | 34 8 1 |
| 3 2 9 | 1 47 8 | 47 5 6 |
| 1 8 4 | 6 37 5 | 37 2 9 |
+----------------+----------------+----------------+
| 45 9 3 | 7 1 26d | 8 46 25 |
| 6 1 2 | 8 5 4 | 9 7 3 |
| 8 47 57 | 23 236c 9 | 1 46 25 |
+----------------+----------------+----------------+
| 25 367 57 | 35b 8 1 | 26 9 4 |
| 9 36a 8 | 4 236 23-6 | 5 1 7 |
| 245 46 1 | 59 69 7 | 26 3 8 |
+----------------+----------------+----------------+
| My W-wing was based on 46 in R4C8 and R9C2, transport 6 from the first to R6C5. R6C8 and R9C2 are the basis of an M-wing that does the same thing.
3 in a forces 3 in c (via b). ad are pincers on 6.
Keith |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sun Oct 23, 2011 1:32 am Post subject: |
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Withdrawn: I was tired and thought I had a point. Now, I'm not so sure.
Last edited by daj95376 on Sun Oct 23, 2011 7:32 am; edited 1 time in total |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun Oct 23, 2011 3:15 am Post subject: |
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daj95376 wrote: | When basic MWSL-Wings are expanded/transported by adding additional strong links for one or both values, accurately describing the path becomes important. For the current puzzle, there may only be two 3-SIS/basic M-Wings present, but there are twelve 4-SIS M-Wings present. In particular, there are four 4-SIS M-Wings for "(6=4)r9c2 - ... - (6)r6c5 => r9c5<>6".
Code: | +--------------------------------------------------------------+
| 7 5 6 | 239 2349 23 | 34 8 1 |
| 3 2 9 | 1 47 8 | 47 5 6 |
| 1 8 4 | 6 37 5 | 37 2 9 |
|--------------------+--------------------+--------------------|
| 45 9 3 | 7 1 26 | 8 46 25 |
| 6 1 2 | 8 5 4 | 9 7 3 |
| 8 47 57 | 23 236 9 | 1 46 25 |
|--------------------+--------------------+--------------------|
| 25 367 57 | 35 8 1 | 26 9 4 |
| 9 36 8 | 4 236 236 | 5 1 7 |
| 245 46 1 | 59 69 7 | 26 3 8 |
+--------------------------------------------------------------+
# 39 eliminations remain
===== =====
M-Wing 1A (6=4)r9c2 - r6c2 = (4-6)r6c8 = (6)r6c5 => r9c5<6> r8c6<6> r8c6<6> r8c6<6> r8c6<6> r9c5<6> r9c5<6> r9c5<6> r9c5<6> r8c2<6> r8c2,r9c5<6> r8c2,r9c5<6> r13c5<3> r1c7,r3c5<>3
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Trust me, you don't want to see the list of 5-SIS and 6-SIS M-Wings in this grid.
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Danny,
I said: Quote: |
3 in a forces 3 in c (via b). ad are pincers on 6.
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I am not sure what the point of your post is, but I found my elimination by hand, and I think it is relatively easy to spot.
Keith |
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Sun Oct 23, 2011 3:35 am Post subject: |
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keith wrote: | I said: Quote: |
3 in a forces 3 in c (via b). ad are pincers on 6.
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I am not sure what the point of your post is, but I found my elimination by hand, and I think it is relatively easy to spot. |
Almost easier to spot than the 'a', 'b', 'c' and 'd' tags on the pencilmarks. With candidates left-justified, the tags would be easier to spot if they were on the left. |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Oct 23, 2011 12:52 pm Post subject: |
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tlanglet wrote: | Another one stepper is
anp(23=6)r6c45-(6=9=5)r9c54-(5=3=2)r76c4; r4c6<>2 |
Beautiful! Great logic -- even if it hurt my head |
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