| View previous topic :: View next topic |
| Author |
Message |
arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
|
 Posted: Mon Dec 26, 2011 1:09 pm Post subject: rh122611 |
 |
|
I liked the last puzzle-- here is another | Code: | *-----------*
|.8.|..3|.1.|
|..7|.1.|..2|
|...|..2|4..|
|---+---+---|
|1.4|...|.2.|
|...|5..|...|
|.3.|...|5.9|
|---+---+---|
|..2|7..|...|
|9..|.2.|3..|
|.7.|4..|.8.|
*-----------* |
|
|
| Back to top |
|
 |
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Mon Dec 26, 2011 6:27 pm Post subject: |
|
|
External analysis of 35 UR in boxes 78 using the 3 and 5 in box7. Common outcomes; r2c1=4, r9c1<>5.
W-Wing (56), SL 5 in c3; r3c8, r789c9<>6.
Looked like there might've been something with a possible BUG Lite on the 68s, but I didn't check for sure because it looked like one of the cells would've had too many excess candidates to do anything efficiently. |
|
| Back to top |
|
|
Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
|
| Posted: Mon Dec 26, 2011 6:55 pm Post subject: rh122611 |
|
|
| The Hiddden UR 35 in Grid r79c15; r9c1<>5 leads to a pair in 58 in r7c1 and r8c3. This opens an x-wing on 4 in r78; r2c2<>4 and the finned x-wing on 5 in r18; r9c9<>5 solves it. |
|
| Back to top |
|
|
JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
|
| Posted: Mon Dec 26, 2011 7:49 pm Post subject: |
|
|
A simple "wing" (again ...) : 8r7c1=(8-6)r7c6=6r8c6-(6=4)r8c2 : -4r7c1; stte.
That is ... (pivot : bilocal 6C6)
Either r7c6=6 -> r7c1=8; or r8c6=6 -> r8c2=4. In both cases, r7c1<>4. stte. |
|
| Back to top |
|
|
arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
|
| Posted: Mon Dec 26, 2011 9:31 pm Post subject: |
|
|
| JC Van Hay wrote: | A simple "wing" (again ...) : 8r7c1=(8-6)r7c6=6r8c6-(6=4)r8c2 : -4r7c1; stte.
|
Nice job JC. I was close; but you kocked it out of the park!  | Code: | *--------------------------------------------------------------------*
| 2 8 56 | 69 4 3 | 679 1 567 |
|e346 469 7 | 689 1 5 | 689 369 2 |
| 356 169 13 | 689 7 2 | 4 3569 3568 |
|----------------------+----------------------+----------------------|
| 1 5 4 | 3 9 7 | 68 2 68 |
| 68 2 9 | 5 68 4 | 17 37 137 |
| 7 3 68 | 2 68 1 | 5 4 9 |
|----------------------+----------------------+----------------------|
|d34568 146 2 | 7 35 c68 | 169 569 1456 |
| 9 a46 568 | 1 2 b68 | 3 567 4567 |
| 356 7 13 | 4 35 9 | 2 8 156 |
*--------------------------------------------------------------------*
(4=6)r8c2-(6)r8c6=(6-8)r7c6=(8-4)r7c1=(4)r2c1 => r2c2<>4 |
|
|
| Back to top |
|
|
daj95376
Joined: 23 Aug 2008
Posts: 3854
|
| Posted: Tue Dec 27, 2011 1:22 am Post subject: |
|
|
If you perform Clement's finned X-Wing, then the <35> UR has strong links for r7c1<>3 that crack the puzzle with the help of a subsequent <58> Hidden Pair.
| Code: | finned X-Wing r18\c39 <> 5 r79c9
+-----------------------------------------------------------------------+
| 2 8 56 | 69 4 3 | 679 1 567 |
| 346 469 7 | 689 1 5 | 689 369 2 |
| 356 169 13 | 689 7 2 | 4 3569 3568 |
|-----------------------+-----------------------+-----------------------|
| 1 5 4 | 3 9 7 | 68 2 68 |
| 68 2 9 | 5 68 4 | 17 37 137 |
| 7 3 68 | 2 68 1 | 5 4 9 |
|-----------------------+-----------------------+-----------------------|
| *34568 146 2 | 7 *35 68 | 169 569 146 |
| 9 46 568 | 1 2 68 | 3 567 4567 |
| *356 7 13 | 4 *35 9 | 2 8 16 |
+-----------------------------------------------------------------------+
# 67 eliminations remain
|
|
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
