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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Tue Feb 07, 2012 1:31 pm Post subject: au 020712 tough |
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Code: | *-----------*
|.94|...|..3|
|...|5..|..1|
|...|..6|72.|
|---+---+---|
|81.|..3|...|
|...|...|...|
|...|1..|.49|
|---+---+---|
|.53|7..|...|
|6..|..8|...|
|7..|...|56.|
*-----------* |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Tue Feb 07, 2012 5:24 pm Post subject: |
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Code after basics:
Code: | *--------------------------------------------------------------------*
| 125 9 4 | 28 1278 127 | 6 58 3 |
| 23 67 67 | 5 2348 24 | 489 89 1 |
| 135 38 58 | 349 1349 6 | 7 2 45 |
|----------------------+----------------------+----------------------|
| 8 1 579 | 469 479 3 | 2 57 567 |
| 49 2347 2579 | 2689 2789 2579 | 138 13578 5678 |
| 35 2367 2567 | 1 278 257 | 38 4 9 |
|----------------------+----------------------+----------------------|
| 49 5 3 | 7 6 1249 | 1489 189 248 |
| 6 24 129 | 249 5 8 | 1349 1379 247 |
| 7 248 1289 | 2349 12349 1249 | 5 6 24 |
*--------------------------------------------------------------------*
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First pass based on UR/AURs
1: UR(67)r26c23; r6c23<>7
2: AUR(24)r89c29[(7)r8c9=(8)r9c2]-(8=3)r3c2-(3=2)r2c1-(2=4)r2c6-(4=89)r2c78-(8=5)r1c8-(5=7)r4c8; r45c9,r8c8<>7
3: AUR(49)r34c45[(4)r3c9=(9-7)r4c3]=(7-5)r4c8=r4c9; r3c9<>5
Ted |
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Luke451
Joined: 20 Apr 2008 Posts: 310 Location: Southern Northern California
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Posted: Tue Feb 07, 2012 6:53 pm Post subject: |
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Hi, Ted, I also tried exploiting that 8=7 AUR link but was not as patient as you in getting results.
Went with the ole hidden pair trick instead. Been a while since I tried these so I hope I got it right.
SE = 7.1
Code: | *--------------------------------------------------------------------*
| 125 9 4 | 28 1278 127 | 6 58 3 |
| 23 67 67 | 5 2348 24 | 489 89 1 |
| 135 38 58 | 349 1349 6 | 7 2 45 |
|----------------------+----------------------+----------------------|
| 8 1 579 | 469 479 3 | 2 57 567 |
| 49 2347 2579 | 2689 2789 2579 | 138 13578 5678 |
| 35 2367 2567 | 1 278 257 | 38 4 9 |
|----------------------+----------------------+----------------------|
| 49 5 3 | 7 6 1249 | 1489 189 248 |
| 6 24 129 | 249 5 8 | 1349 1379 247 |
| 7 248 1289 | 2349 12349 1249 | 5 6 24 |
*--------------------------------------------------------------------* |
hp(23)r2c15=(2)r2c6-(2=8)r1c4
==>r2c5<>8, stte.
Edit: simplified things |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Tue Feb 07, 2012 8:00 pm Post subject: |
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Code: | *--------------------------------------------------------------------*
| 125 9 4 |b28 1278 127 | 6 c58 3 |
| 23 67 67 | 5 2348 a24 | 89-4 89 1 |
| 135 38 58 | 39-4 139-4 6 | 7 2 d45 |
|----------------------+----------------------+----------------------|
| 8 1 579 | 469 479 3 | 2 57 567 |
| 49 2347 2579 | 2689 2789 2579 | 138 13578 5678 |
| 35 2367 2567 | 1 278 257 | 38 4 9 |
|----------------------+----------------------+----------------------|
| 49 5 3 | 7 6 1249 | 1489 189 248 |
| 6 24 129 | 249 5 8 | 1349 1379 247 |
| 7 248 1289 | 2349 12349 1249 | 5 6 24 |
*--------------------------------------------------------------------*
xy-chain
(4=2)r2c6-(2=8)r1c4-(8=5)r1c8-(5=4)r3c9 => r2c7,r3c45<>4 |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Tue Feb 07, 2012 10:02 pm Post subject: |
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I used a few worthless moves before noticing the XY-Chain. Mine made the same eliminations but I used the 5 in r3c9 to prove 4 in r2c6. |
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