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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun Mar 18, 2012 1:30 pm Post subject: Interesting ... |
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This from my Saturday newspaper, labelled "Universal Sudoku Puzzle". I have not before seen these puzzles require advanced moves. Code: | Puzzle: AD20120317
+-------+-------+-------+
| 9 4 1 | 7 . . | . . 8 |
| . 2 . | . . 6 | . . 7 |
| 7 . 6 | 1 . . | . . 3 |
+-------+-------+-------+
| . . 7 | . . 5 | . . 4 |
| . . . | . . . | . . . |
| 8 . . | 9 . . | 2 . . |
+-------+-------+-------+
| 4 . . | . . 9 | 3 . 6 |
| 3 . . | 5 . . | . 4 . |
| 6 . . | . . 8 | 7 5 9 |
+-------+-------+-------+ | Keith |
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Auburnmom
Joined: 13 Mar 2008 Posts: 25 Location: Auburn, AL
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Posted: Sun Mar 18, 2012 2:20 pm Post subject: |
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I also have this puzzle and am stopped. So I am sure there is a step that is beyond my ability.
[/img] |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Mar 18, 2012 4:41 pm Post subject: |
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Given Keith's comments, I did not pursue non-advanced moves but found three views of the same deletions.
After basics:
Code: | *-----------------------------------------------------------------------------*
| 9 4 1 | 7 235 23 | 56 26 8 |
| 5 2 3 | 48 489 6 | 149 19 7 |
| 7 8 6 | 1 2459 24 | 459 29 3 |
|-------------------------+-------------------------+-------------------------|
| 12 369 7 | 368 12 5 | 689 3689 4 |
| 12 3569 459 | 3468 123478 12347 | 689 36789 15 |
| 8 356 45 | 9 1347 1347 | 2 367 15 |
|-------------------------+-------------------------+-------------------------|
| 4 57 58 | 2 17 9 | 3 18 6 |
| 3 79 89 | 5 6 17 | 18 4 2 |
| 6 1 2 | 34 34 8 | 7 5 9 |
*-----------------------------------------------------------------------------*
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almost xy-wing (24-9)[r3c68+r2c5]=(8)r2c5-(8=4)r2c4-(4=2)r3c6-(2=9)r3c8; r2c78, r3c5<>9
or
anp(9=48)r2c54-(4=2)r3c6-(2=9)r3c8; r2c78, r3c5<>9
or
ALS XZ; r2c78, r3c5<>9
a=(489)r2c45
b=(249)r3c68
x=4
z=9
Ted |
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Sun Mar 18, 2012 5:01 pm Post subject: |
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Code: | After 8 singles
+---------------+---------------------+--------------------+
| 9 4 1 | 7 235 23 | 56 26 8 |
| 5 2 3 | 48 8-4(9) 6 | -9(14) -9(1) 7 |
| 7 8 6 | 1 24(59) 24 | 9(45) 29 3 |
+---------------+---------------------+--------------------+
| 12 369 7 | 368 1238 5 | 1689 13689 4 |
| 12 3569 459 | 3468 123478 12347 | 15689 136789 15 |
| 8 356 45 | 9 1347 1347 | 2 1367 15 |
+---------------+---------------------+--------------------+
| 4 57 58 | 2 17 9 | 3 18 6 |
| 3 79 89 | 5 6 17 | 18 4 2 |
| 6 1 2 | 34 34 8 | 7 5 9 |
+---------------+---------------------+--------------------+
4-SIS AIC : 9r2c5=(9-5)r3c5=(5-4)r3c7=(4-1)r2c7=1r2c8 => -4r2c5, -9r2c78; stte |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Mar 18, 2012 5:12 pm Post subject: |
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Code: | *-----------------------------------------------------------------------------*
| 9 4 1 | 7 235 23 | 56 26 8 |
| 5 2 3 | 48 489 6 | 149 19 7 |
| 7 8 6 | 1 2459 24 | 459 29 3 |
|-------------------------+-------------------------+-------------------------|
| 12 369 7 | 368 12 5 | 689 3689 4 |
| 12 3569 459 | 3468 123478 12347 | 689 36789 15 |
| 8 356 45 | 9 1347 1347 | 2 367 15 |
|-------------------------+-------------------------+-------------------------|
| 4 57 58 | 2 17 9 | 3 18 6 |
| 3 79 89 | 5 6 17 | 18 4 2 |
| 6 1 2 | 34 34 8 | 7 5 9 |
*-----------------------------------------------------------------------------* |
I don't know if mine is similar as JC's due to my Eureka deficiencies. But in a short AIC, r3c8=2 proves r2c5=9; r2c78, r3c5<>9. |
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Sun Mar 18, 2012 6:00 pm Post subject: |
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Marty,
What was exactly your path ? ...
Furthermore, you only need "r3c8=2 proves r3c5=5" to get r3c5<>9
In Eureka, among a lot of other possibilities as Ted showed :
(9=2)r3c8-AHP[2r1c8=23r1c56]-5r1c5=5r3c5 => -9r3c5
or
(9=2)r3c8-(2=6)r1c8-(6=5)r1c7-5r1c5=5r3c5 => -9r3c5
or
... Regards, JC. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Mar 18, 2012 6:48 pm Post subject: |
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Path:
Code: | *----------------------------------------------------------------------------------*
| 9 4 1 | 7 235 23 | 56 26 8 |
| 5 2 3 | C48 D489 6 | 149 19 7 |
| 7 8 6 | 1 2459 B24 | 459 A29 3 |
|-------------------------+---------- -----------------+--------------------------|
| 12 369 7 | 368 12 5 | 689 3689 4 |
| 12 3569 459 | 3468 123478 12347 | 689 36789 15 |
| 8 356 45 | 9 1347 1347 | 2 367 15 |
|-------------------------+----------------------------+--------------------------|
| 4 57 58 | 2 17 9 | 3 18 6 |
| 3 79 89 | 5 6 17 | 18 4 2 |
| 6 1 2 | 34 34 8 | 7 5 9 |
*---------------------------------------------------------------------------------* |
I can follow how the 2 proves the 5 but that's probably not the kind of thing I'd notice. |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Mar 18, 2012 7:16 pm Post subject: |
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I got the same as Ted
Code: | *-----------------------------------------------------------------------------*
| 9 4 1 | 7 d235 23 |c56 b26 8 |
| 5 2 3 | 48 489 6 | 149 19 7 |
| 7 8 6 | 1 e245-9 24 | 459 a29 3 |
|-------------------------+-------------------------+-------------------------|
| 12 369 7 | 368 12 5 | 689 3689 4 |
| 12 3569 459 | 3468 123478 12347 | 689 36789 15 |
| 8 356 45 | 9 1347 1347 | 2 367 15 |
|-------------------------+-------------------------+-------------------------|
| 4 57 58 | 2 17 9 | 3 18 6 |
| 3 79 89 | 5 6 17 | 18 4 2 |
| 6 1 2 | 34 34 8 | 7 5 9 |
*-----------------------------------------------------------------------------*
xy-wing with extension???
(9=2)r3c8-(2=6)r1c8-(6=5)r1c7-(5)r1c5=(5)r3c5 => r1c5<>9 |
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Sun Mar 18, 2012 7:43 pm Post subject: |
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Marty,
OK, now I understand your logic.
In a word, you are using the same SIS as Ted who gave 3 different interpretations of the same deletions.
In Eureka, I am reading your path as
4-SIS t-Chain : (9=2)r3c8-(2=4)r3c6-(4=8)r2c4-(84#2=9)r2c5 => -9r3c5, -9r2c78
That is :
Either r3c8=9; Or r3c8=2, r3c6<>2, r3c6=4, r2c4<>4, r2c4=8, [r2c5<>8 and r2c5<>4(because of r3c6=4)], r2c5=9
=> pincers (9r3c8,9r2c5) => r3c5<>9 and r2c78<>9
Thanks a lot for the clarifications.
Regards, JC |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Mar 18, 2012 10:30 pm Post subject: |
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JC Van Hay wrote: | (9=2)r3c8-(2=4)r3c6-(4=8)r2c4-(84#2=9)r2c5 => -9r3c5, -9r2c78
| wouldn't
(9=2)r3c8-(2=4)r3c6-(48=9)r2c45 => -9r3c5, -9r2c78
be better? |
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Mon Mar 19, 2012 8:16 pm Post subject: |
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Dan,
Of course, it's better to write (9=2)r3c8-(2=4)r3c6-(4=89)r2c45 => -9r3c5, -9r2c78.
However, in my previous post, I hoped to translate Marty's logic as faithfully as possible.
Therfore, my "detailed" presentation.
Regards, JC. |
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