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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Thu Jul 19, 2012 5:31 am Post subject: au tough July 17, 2012 |
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Code: |
*-----------*
|2..|...|91.|
|...|7..|5..|
|...|.5.|8..|
|---+---+---|
|..4|.91|...|
|9..|...|..8|
|...|68.|2..|
|---+---+---|
|..1|.2.|...|
|..7|..4|...|
|.46|...|..5|
*-----------*
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Jul 19, 2012 1:09 pm Post subject: |
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Code after basics:
Code: | *-----------------------------------------------------------*
| 2 3567 358 | 348 346 368 | 9 1 467 |
| 146 136 89 | 7 1346 89 | 5 36 2 |
| 1467 1367 39 | 19 5 2 | 8 367 467 |
|-------------------+-------------------+-------------------|
| 67 8 4 | 2 9 1 | 67 5 3 |
| 9 3567 2 | 34 347 357 | 1 67 8 |
| 17 1357 35 | 6 8 357 | 2 4 9 |
|-------------------+-------------------+-------------------|
| 35 9 1 | 35 2 67 | 4 8 67 |
| 58 2 7 | 58 36 4 | 36 9 1 |
| 38 4 6 | 19 137 3789 | 37 2 5 |
*-----------------------------------------------------------*
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An easy solution is a w-wing(67)r5c8|r7c6 SL(7)r59c5 plus transport
(6=7)r5c8-r5c5=r9c5-(7=6)r7c6-r7c9=r8c7; -6r4c7
A fun solution was a AUR(17)r36c12 external SIS : (1)r3c4, (7)r1c2, (7)r6c6
(1)r3c4-r9c4=(1-7)r9c5=r79c6-r56c6=r5c5-r5c8=r3c8;
(7)r1c2;
(7)r6c6-r79c6=r9c5-r9c7=r4c7-r5c8=r3c8; -7r3c12
Ted |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu Jul 19, 2012 6:10 pm Post subject: |
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Code: | +---------------+------------------+----------------+
| 2 3567 358 | 348 346 368 | 9 1 467 |
| 146 136 389 | 7 1346 23689 | 5 36 246 |
| 1467 1367 39 | 1349 5 2369 | 8 D367 2467 |
+---------------+------------------+----------------+
| 67 8 4 | 2 9 1 | A67 5 3 |
| 9 3567 2 | 34 F347 357 | 1 C6-7 8 |
| 17 1357 35 | 6 8 357 | 2 4 9 |
+---------------+------------------+----------------+
| 35 9 1 | 35 2 67 | 4 8 67 |
| 58 2 7 | 58 36 4 | 36 9 1 |
| 38 4 6 | 1389 E137 3789 | B37 2 5 |
+---------------+------------------+----------------+ |
Multi-coloring on 7. Skyscraper in c78; B or D must be 7. Transport B to F via E; r5c8<>7. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu Jul 19, 2012 7:28 pm Post subject: |
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Code: | *-----------------------------------------------------------*
| 2 3567 358 | 348 346 368 | 9 1 467 |
| 146 136 89 | 7 1346 89 | 5 36 2 |
| 1467 1367 39 | 19 5 2 | 8 367 467 |
|-------------------+-------------------+-------------------|
| 67 8 4 | 2 9 1 | 67 5 3 |
| 9 3567 2 | 34 347 357 | 1 67 8 |
| 17 1357 35 | 6 8 357 | 2 4 9 |
|-------------------+-------------------+-------------------|
| 35 9 1 | 35 2 67 | 4 8 67 |
| 58 2 7 | 58 36 4 | 36 9 1 |
| 38 4 6 | 19 137 3789 | 37 2 5 |
*-----------------------------------------------------------*
An easy solution is a w-wing(67)r5c8|r7c6 SL(7)r59c5 plus transport
(6=7)r5c8-r5c5=r9c5-(7=6)r7c6-r7c9=r8c7; -6r4c7 |
Ted, I can't make heads nor tails of the transport. I can see a simple transport from r7c6 to r8c7 that makes the elimination, but I don't see from the notation what roles r5c5 and r9c5 play in the transport or how it works if the transport starts with r5c8. |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Wed Jul 25, 2012 2:32 pm Post subject: |
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Marty R. wrote: | Code: | *-----------------------------------------------------------*
| 2 3567 358 | 348 346 368 | 9 1 467 |
| 146 136 89 | 7 1346 89 | 5 36 2 |
| 1467 1367 39 | 19 5 2 | 8 367 467 |
|-------------------+-------------------+-------------------|
| 67 8 4 | 2 9 1 | 67 5 3 |
| 9 3567 2 | 34 347 357 | 1 67 8 |
| 17 1357 35 | 6 8 357 | 2 4 9 |
|-------------------+-------------------+-------------------|
| 35 9 1 | 35 2 67 | 4 8 67 |
| 58 2 7 | 58 36 4 | 36 9 1 |
| 38 4 6 | 19 137 3789 | 37 2 5 |
*-----------------------------------------------------------*
An easy solution is a w-wing(67)r5c8|r7c6 SL(7)r59c5 plus transport
(6=7)r5c8-r5c5=r9c5-(7=6)r7c6-r7c9=r8c7; -6r4c7 |
Ted, I can't make heads nor tails of the transport. I can see a simple transport from r7c6 to r8c7 that makes the elimination, but I don't see from the notation what roles r5c5 and r9c5 play in the transport or how it works if the transport starts with r5c8. |
Marty, Sorry for the delay in responding to your post but I was traveling on vacation again.
Cells r5c5 and r9c5 form the strong link on (7). The first four entries in the posted AIC form the w-wing(67) and the last two entries are the transport.
Ted |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Jul 25, 2012 3:37 pm Post subject: |
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Quote: | An easy solution is a w-wing(67)r5c8|r7c6 SL(7)r59c5 plus transport
(6=7)r5c8-r5c5=r9c5-(7=6)r7c6-r7c9=r8c7; -6r4c7 |
Thanks Ted. Obviously I made the silly mistake of thinking that everything following the words "plus transport" referred just to the transport. |
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