| View previous topic :: View next topic |
| Author |
Message |
arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
|
 Posted: Fri Jul 27, 2012 5:58 am Post subject: Vanhegan extreme July 26, 2012 |
 |
|
| Code: | *-----------*
|.7.|89.|...|
|..9|.56|.2.|
|..2|3..|...|
|---+---+---|
|64.|9.7|.5.|
|9.7|.1.|6.3|
|.1.|6.8|.74|
|---+---+---|
|...|..3|7..|
|.9.|28.|5..|
|...|.49|.1.|
*-----------*
|
|
|
| Back to top |
|
 |
Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
|
| Posted: Fri Jul 27, 2012 5:28 pm Post subject: Vanhagen extreme July 26, 2012 |
|
|
After the Basics | Code: |
+-------------+-------+-------------+
| 145 7 145-6 | 8 9 2 | *134 36 15 |
| 48 3 9 | 1 5 6 | 48 2 7 |
| 158 56 2 | 3 7 4 | 18 69 1589 |
+-------------+-------+-------------+
| 6 4 8 | 9 3 7 | 12 5 12 |
| 9 2 7 | 4 1 5 | 6 8 3 |
| 35 1 35 | 6 2 8 | 9 7 4 |
+-------------+-------+-------------+
| 124 8 14 | 5 6 3 | 7 49 29 |
| 7 9 34 | 2 8 1 | 5 34 6 |
| 235 56 3-56 | 7 4 9 | *238 1 28 |
+-------------+-------+-------------+
|
Hidden UR 35 in row 69; r9c3<>5 opens a
W-Wing 36 with SL 3 in col 7 or row 8; r1c3<>6 which solves it. |
|
| Back to top |
|
|
arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
|
| Posted: Fri Jul 27, 2012 6:28 pm Post subject: |
|
|
| Code: |
*-----------------------------------------------------------*
| 145 7 145-6 | 8 9 2 | 134 a36 15 |
| 48 3 9 | 1 5 6 | 48 2 7 |
| 158 56 2 | 3 7 4 | 18 69 1589 |
|-------------------+-------------------+-------------------|
| 6 4 8 | 9 3 7 | 12 5 12 |
| 9 2 7 | 4 1 5 | 6 8 3 |
| 35 1 c35 | 6 2 8 | 9 7 4 |
|-------------------+-------------------+-------------------|
| 124 8 14 | 5 6 3 | 7 49 29 |
| 7 9 c34 | 2 8 1 | 5 b34 6 |
| 235 56 c356 | 7 4 9 | 238 1 28 |
*-----------------------------------------------------------*
(6=3)r1c8-(3=4)r8c8-(4=356)r689c3 => -6r1c3; stte
if r1c8 is not 6 then r9c3 is 6 |
|
|
| Back to top |
|
|
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Fri Jul 27, 2012 10:23 pm Post subject: |
|
|
| Using the Type 3 UR on 35, r9c1=2 or r9c3=6. Trying each yields a common outcome of r3c2=6. |
|
| Back to top |
|
|
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Sat Jul 28, 2012 12:35 pm Post subject: |
|
|
Another solution is
anp[(56)r3c2|r1c3=ls(14)r17c3]-(4)r8c3=r8c8-(4=9=6)r73c8-(6=5)r3c2; -5r13c1
Ted |
|
| Back to top |
|
|
tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
|
| Posted: Sat Jul 28, 2012 12:37 pm Post subject: |
|
|
| arkietech wrote: | | Code: |
*-----------------------------------------------------------*
| 145 7 145-6 | 8 9 2 | 134 a36 15 |
| 48 3 9 | 1 5 6 | 48 2 7 |
| 158 56 2 | 3 7 4 | 18 69 1589 |
|-------------------+-------------------+-------------------|
| 6 4 8 | 9 3 7 | 12 5 12 |
| 9 2 7 | 4 1 5 | 6 8 3 |
| 35 1 c35 | 6 2 8 | 9 7 4 |
|-------------------+-------------------+-------------------|
| 124 8 14 | 5 6 3 | 7 49 29 |
| 7 9 c34 | 2 8 1 | 5 b34 6 |
| 235 56 c356 | 7 4 9 | 238 1 28 |
*-----------------------------------------------------------*
(6=3)r1c8-(3=4)r8c8-(4=356)r689c3 => -6r1c3; stte
if r1c8 is not 6 then r9c3 is 6 |
|
Very simple, elegant solution. Good Go 
Ted |
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
