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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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 Posted: Wed Oct 10, 2012 5:13 am Post subject: Menneske 2038613 |
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| Code: |
*-----------*
|...|...|7..|
|.4.|185|...|
|..9|.7.|.3.|
|---+---+---|
|.7.|.1.|.9.|
|.93|2.7|18.|
|.8.|.3.|.2.|
|---+---+---|
|.2.|.6.|9..|
|...|321|.7.|
|..5|...|...|
*-----------*
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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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| Posted: Wed Oct 10, 2012 7:53 am Post subject: Menneske 2038613 |
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Code after Basics | Code: |
+------------+------------+------------+
| 268 1 268 | 469 49 3 | 7 5 48 |
| 3 4 7 | 1 8 5 | 2 6 9 |
| 68 5 9 | 46 7 2 | 48 3 1 |
+------------+------------+------------+
| 245-6 7 2-6 | 8 1 D46 | 3 9 456 |
| 46 9 3 | 2 5 7 | 1 8 46 |
| 1456 8 A16 | 469 3 4-69 | 456 2 7 |
+------------+------------+------------+
| 7 2 B18 | 5 6 C48 | 9 14 3 |
| 9 6 4 | 3 2 1 | 58 7 58 |
| 18 3 5 | 7 49 489 | 26 14 26 |
+------------+------------+------------+
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XY-Chain ABCD: r6c3=6; r4c13<>6, r6c6<>6
(6=1)r6c3-(1=8)r7c3-(8=4)r7c6-(4=6)r4c6; r4c13<>6, r6c6<>6 solves it. |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Wed Oct 10, 2012 2:00 pm Post subject: |
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My initial solution was the same as that already posted by Clement so I looked for an alternative.
I did spot an almost hidden pair AHP(45)r46c1=(4)r5c1 which set r5c1=4 but, to my surprise and disappointment, it did not advance the puzzle.
So, I settled for a variation of my original solution:
5r6c7=(5-1)r6c1=r6c3-(1=8=4)r7c36-r46c6=r6c4-(4=5)r6c7 => 5r6c7
Ted |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Wed Oct 10, 2012 2:25 pm Post subject: |
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I like wings.
| Code: |
*-----------------------------------------------------------*
| 268 1 268 | 469 49 3 | 7 5 48 |
| 3 4 7 | 1 8 5 | 2 6 9 |
| 68 5 9 | 46 7 2 | 48 3 1 |
|-------------------+-------------------+-------------------|
| 245-6 7 2-6 | 8 1 a46 | 3 9 456 |
| 46 9 3 | 2 5 7 | 1 8 46 |
| 1456 8 c16 | 49 3 49-6 | 45 2 7 |
|-------------------+-------------------+-------------------|
| 7 2 b18 | 5 6 b48 | 9 14 3 |
| 9 6 4 | 3 2 1 | 58 7 58 |
| 18 3 5 | 7 49 489 | 6 14 2 |
*-----------------------------------------------------------*
als xy-wing
(6=4)r4c6-(4=1)als:r7c36-(1=6)r6c3 => -6r4c13,r6c6; stte
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Wed Oct 10, 2012 6:32 pm Post subject: |
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| Code: | +----------------+----------------+----------------+
| 268 1 268 | 49+6 49 3 | 7 5 48 |
| 3 4 7 | 1 8 5 | 2 6 9 |
| 68 5 9 | 46 7 2 | 48 3 1 |
+----------------+----------------+----------------+
| 2456 7 26 | 8 1 46 | 3 9 456 |
| 46 9 3 | 2 5 7 | 1 8 46 |
| 1456 8 C16 | 49 3 A49+6 | 45 2 7 |
+----------------+----------------+----------------+
| 7 2 8-1 | 5 6 48 | 9 14 3 |
| 9 6 4 | 3 2 1 | 58 7 58 |
|D18 3 5 | 7 49 B49+8 | 6 14 2 |
+----------------+----------------+----------------+ |
Note the DP 49 in R169C456.
One way to prevent the DP is that AB is 68, forming an XY-wing with CD. R7C3 <>1. (Which solves the puzzle.)
Now, how to make an argument about R1C4 <6>?
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Oct 11, 2012 2:14 am Post subject: |
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| I also used the DP 49 in boxes 258. Either r1c4 or r6c6=6 or r9c6=8. Common outcome; r4c6=6. |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Thu Oct 11, 2012 2:28 am Post subject: |
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| Marty R. wrote: | | I also used the DP 49 in boxes 258. Either r1c4 or r6c6=6 or r9c6=8. Common outcome; r4c6=6. |
r6c6 = 6 implies r4c6 =6? How can that be? They are in the same column.
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Oct 11, 2012 2:44 am Post subject: |
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You beat me to it. I was going to delete the post, but you're too fast and (justifiably) untrusting.   |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Thu Oct 11, 2012 5:15 pm Post subject: |
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| keith wrote: | | Marty R. wrote: | | I also used the DP 49 in boxes 258. Either r1c4 or r6c6=6 or r9c6=8. Common outcome; r4c6=6. |
r6c6 = 6 implies r4c6 =6? How can that be? They are in the same column.
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If r6c6=6 is false, then it's conceivable that it could lead to r4c6=6.
Guess what, r6c6=6 is false. Unfortunately, Marty doesn't list his derived chains. |
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Luke451
Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California
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| Posted: Thu Oct 11, 2012 10:03 pm Post subject: |
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| keith wrote: | | Marty R. wrote: | | I also used the DP 49 in boxes 258. Either r1c4 or r6c6=6 or r9c6=8. Common outcome; r4c6=6. |
r6c6 = 6 implies r4c6 =6? How can that be? They are in the same column. |
| Code: | *-----------------------------------------------------------*
| 268 1 268 | 469 49 3 | 7 5 48 |
| 3 4 7 | 1 8 5 | 2 6 9 |
| 68 5 9 | 46 7 2 | 48 3 1 |
|-------------------+-------------------+-------------------|
| 2456 7 26 | 8 1 46 | 3 9 456 |
| 46 9 3 | 2 5 7 | 1 8 46 |
| 1456 8 16 | 49 3 469 | 45 2 7 |
|-------------------+-------------------+-------------------|
| 7 2 18 | 5 6 48 | 9 14 3 |
| 9 6 4 | 3 2 1 | 58 7 58 |
| 18 3 5 | 7 49 489 | 6 14 2 |
*-----------------------------------------------------------* |
(6)r6c6-(6=1)r6c3-(1=8)r7c3-(8=4)r7c6-(4=6)r4c6
So Marty, if you can remember the other two paths, I'd say you're exonerated  |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Thu Oct 11, 2012 10:12 pm Post subject: |
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| Luke451 wrote: |
(6)r6c6-(6=1)r6c3-(1=8)r7c3-(8=4)r7c6-(4=6)r4c6
So Marty, if you can remember the other two paths, I'd say you're exonerated |
However, proving r6c6<>6 doesn't make r4c6=6 an "outcome". |
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Luke451
Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California
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| Posted: Thu Oct 11, 2012 10:27 pm Post subject: |
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| ronk wrote: | | Luke451 wrote: |
(6)r6c6-(6=1)r6c3-(1=8)r7c3-(8=4)r7c6-(4=6)r4c6
So Marty, if you can remember the other two paths, I'd say you're exonerated |
However, proving r6c6<>6 doesn't make r4c6=6 an "outcome". |
Yah, sure. One would have to prove the same "outcome" from (6)r1c4 and (8)r9c6.
@ Ted: I'm gonna start calling you "Extra Node Langlet."  |
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